ReflectiveJournalFinal1.Atthebeginningofthecourse,Ijusthaveablurryunderstandingofdigitalmultimodalcomposing.Afterhavingcoursesformanytimes,Igraduallygraspedtheconceptofdigitalmultimodalcomposing.Thekeyresidesin“multim

​Intoday'svideo,IwanttointroducetheDragonBoatFestivaltoyou.TherearemanydifferentversionsregardingtheoriginofDragonBoatFestival,butthemostwidelyacceptedoneiscommemoratingthedeathofthepatrioticpoetQuYuan,whocom

vue-cli创建项目ERROR in Conflict: Multiple assets emit different content to the same filename index.html问题的解决办法用vue-cli正常来创建新的项目在运行npmrundev或者npmrunserve有以下报错：ERRORinConflict:Multipleassetsemitdifferentco

文章目录一.静态合批(StaticBatching)1.启用静态合批2.举例说明3.静态合批的限制4.静态合批的优点缺点5.动态指定物品合批二.动态合批(DynamicBatching)1.启用动态合批2.合批规则3.举例说明4.使用限制三.GPUInstancing1.启用GPUInstancing2.启用限制3.举例说明

Thehand-pushfloorscrubberisanelectriccleaningequipmentsuitablefordifferentfloormaterialsanddifferentcleaningplaces.Whilecleaningthefloor,itsucksupthesewageandtakesthesewageawayfromthesite.Theworkingprincipleissimple,

ERRORFailedtocompilewith1error20:32:04errorConflict:Multipleassetsemitdifferentcontenttothesamefilenameindex.htmlERRORinConflict:Multipleassetsemitdif

之前已经编译好了一个文件夹A下的工程然后复制出一个文件夹B，再次编译时出现了问题，报错ThecurrentCMakeCache.txtdirectory...isdifferentfrom...其实也能猜到就是当路径从A变到B，不匹配导致报错，但是不知道应该在哪里改CSDN上有个文章给出回答：删除build文件夹，当然把log和ins

Frozen​Elsa'sperspective​I'mElsa,aprincess,andIhaveasisternamedAnna.Ihavethemagictocontroltheiceandsnow.However,duringaplaywithmysister,Iaccidentallyhurtherwithmagic.Myparentstookustoaskthetrollsforhel

Unity中Batching大致可以分为StaticBatching,DynamicBatching,SRPBatching与GPUInstancing四大类，但在使用时我们经常会遇到合批失败的情况，这里汇总了四大类的合批使用限制与合批失败的关键错误信息.StaticBatching的限制额外的内存开销64000个顶点限制影响

Thispaperisadaptedfrompartonecadaverizationof《聊斋志异》.Thisisoriginaltext:https://liaozhai.5000yan.com/19939.htmlThepointofviewofthestory:ThethirdpersonpointofviewThepointwillIusedinthestory.:FirstpersonpointofviewThe

TheLittleMatchGirlTodaywasthelastdayofthisyear.Theweatherwaschillwithsnowflakesdancingintheair.Iwaspushtosellmatchesbymymother.WhenIlefthome,Iworeapairofoversizeslippers,whichbelongedtomymother.Myclothesand

ThestoryIchoose:TheLittleMatch-GirlThepointofviewofthestory:ThirdpersonpointofviewNewpointofview:FirstpersonpointofviewScript:ThatwasaChristmasEvewithheavysnow.Iwassellingmatchesonthestreet.“Matches,matches!”B

Myfavoritestory:upThepointofviewofthestory:FirstpersonpointofviewNewpointofview:ThirdpersonpointofviewScript:LittleboyCarlwasmadaboutadventurefromchildhood,hopingtobeagreatadventurer.Oneday,heencounteredtomboy

Myfavoritestory:SoulThepointofviewofthestory:ThirdpersonpointofviewNewpointofview:FirstpersonpointofviewScript:MynameisJoeGardner.I'manordinarymiddleschoolmusicteacher.Mydailylifeisarepetitionofthesameth

错误现象：Resolved[org.mybatis.spring.MyBatisSystemException:nestedexceptionisorg.apache.ibatis.type.TypeException:Couldnotsetparametersformapping:ParameterMapping{property='keywords',mode=IN,javaType=classjava.lang.Object,jdbcType=n

52Things:Number1:DifferentTypesofProcessors52件事：数字1：不同类型的处理器Thisisthefirstinaseriesofblogpoststoaddressthelistof '52ThingsEveryPhDStudentShouldKnow' todoCryptography.Thesetofquestionshasbeencompiledt

52Things:Number3:Computationalandstoragepowerofdifferentformfactors52件事：数字3：不同外形尺寸的计算和存储能力Thisisthethirdinaseriesofblogpoststoaddressthelistof '52ThingsEveryPhDStudentShouldKnow' todoCryptography.Thes

Rustprovidesthreemainusagescenariosforgenericparameters,eachwithitsuniquepurposesandadvantages:DelayedBinding:Genericsallowdelayingtheconcretetypebindingofdatastructures,providingflexibilityandcodereusability.Whendefinin

PDF格式公众号回复关键字:ZKYD009阅读理解技巧，在帮助读者有效获取和理解文本信息方面发挥着重要作用，熟练掌握如下6个技巧，可快速突破阅读理解1预览文章结构在开始深入阅读之前，快速浏览文章的标题、段落开头和结尾，可以迅速把握文章的主题、大致内容和结构标题通常能概括文章

Ihavelearnedalotinclassrecently.First,Ilearnedwhatdigitalmultimodalcomposingis.ItconvertstraditionalpaperandpenmediaintocomputerorInternetmedia,andproducesdigitaltextbycombiningtext,imageandsound.Then,Ialsoknowthe

写点简单的思维题https://codeforces.com/problemset/problem/1927/D思路：用两个数组，一个存储原始数据，一个用nex存该位置第一次不一样的下标#include<iostream>#include<vector>#include<algorithm>#include<math.h>#include<sstream>#include<string>#include<str

DifferentSubsetsForAllTuples数学题面有一个长度为\(n\)的数列，每个位置上数字的值在\([1,m]\)范围内，则共有\(m^n\)种可能的数列。分别求出每个数列中本质不同的子序列个数（包含空序列），然后求和，答案对\(10^9+7\)取模。（\(1\len,m\le10^6\)）数据范围$1<=n,m<=10^{6}$解法

前言拿到题目首先看数据量，n，q都是2e5的数量级，如果是暴力解的话时间复杂度会达到O（m*n）（最差情况m次询问，每次l和r为1和n），很明显会超时。这就意味着我们要在线性的时间内完成查询，即每次询问的查询时间保证在O（1）。题解准备一个数组b存储该连续相同数字串的起始点，然后我们从左向右遍历

题解我们只需要遍历1~k，这时会有四种情况：1、只存于a数组中。2、只存于b数组中。3、同时存于ab数组中。4、不存在于ab数组中。对于情况三，这种数我们不需要去管，因为它可以算在任意的数组上。那么我们只需要判断情况一和二的数是否都<=k/2，并且情况一二三的数总和为k.Code 

原题链接核心\(p[i]\)代表离\(a[i]\)最近的不同元素code#include<bits/stdc++.h>usingnamespacestd;inta[200005]={0};intp[200005]={0};intmain(){intt;cin>>t;while(t--){intn;cin>>n;for(inti=1