数学题 求解 1+\(\frac{1}{3}\)+\(\frac{1}{3^2}\)+\(\frac{1}{3^3}\)+\(\frac{1}{3^4}\)+\(\frac{1}{3^5}\)+\(\frac{1}{3^6}\)+\(\frac{1}{3^7}\)+\(\frac{1}{3^8}\)+\(\frac{1}{3^9}\)+\(\frac{1}{3^10}\)
解题思路:
令 S =1+\(\frac{1}{3}\)+\(\frac{1}{3^2}\)+\(\frac{1}{3^3}\)+\(\frac{1}{3^4}\)+\(\frac{1}{3^5}\)+\(\frac{1}{3^6}\)+\(\frac{1}{3^7}\)+\(\frac{1}{3^8}\)+\(\frac{1}{3^9}\)+\(\frac{1}{3^10}\) 设为 等式①
那么 ,
3S=3+1+\(\frac{1}{3}\)+\(\frac{1}{3^2}\)+\(\frac{1}{3^3}\)+\(\frac{1}{3^4}\)+\(\frac{1}{3^5}\)+\(\frac{1}{3^6}\)+\(\frac{1}{3^7}\)+\(\frac{1}{3^8}\)+\(\frac{1}{3^9}\) 设为 等式②
等式②减去等式①,则:
2S = 3 - \(\frac{1}{3^10}\) ,那么:
最终答案 : S= \({3}-\frac{1}{3^10}\over{2}\)
标签:10,frac,2S,3S,等式,数学题 From: https://www.cnblogs.com/yuntao/p/18402734