#include<stdio.h> int main() { printf("0\n"); printf("<H>\n"); printf("I I\n"); printf("0\n"); printf("<H>\n"); printf("I I\n"); return 0; }teST1
test1.2
#include <stdio.h> int main() { float a,b,c; scanf("%f%f%f",&a,&b,&c); if (a+b>c&&a+c>b&&c+b>a) printf("能构成一个三角形\n"); else printf("不能构成一个三角形\n"); return 0; }test2
#include <stdio.h> int main() { char ans1, ans2; printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) :"); ans1 = getchar(); getchar(); printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : "); ans2 = getchar(); if ((ans2 == 'y' && ans1 == 'y') || (ans1 == 'Y' && ans2 == 'Y') || (ans1 == 'Y' && ans2 == 'y') || (ans1 == 'y' && ans2 == 'Y')) // printf("\n罗马不是一天建成的, 继续保持哦:)\n"); else printf("\n罗马不是一天毁灭的, 我们来建设吧\n"); system("pause"); return 0; }test3 test4
test5
#include <stdio.h> int main() { int year; const double second = 1e9; double temp = ((second / 3600) / 24) / 365; if (temp - (int)temp < 0.5) { year = (int)temp; } else { year = (int)temp + 1; } printf("10亿秒约等于%d年\n", year); system("pause"); return 0; }
test6
1 #include <stdio.h> 2 #include <math.h> 3 int main() 4 { 5 double x, ans; 6 while (scanf("%lf", &x) != EOF) { 7 ans = pow(x, 365); 8 printf("%.2f的365次方: %.2f\n", x, ans); 9 printf("\n"); 10 } 11 12 return 0; 13 }
#include <stdio.h> int main() { double f; double c; while (scanf("%lf", &c) != EOF) { f = 9.0 / 5.0 * c + 32.0; printf("摄氏度c = %.2lf时, 华氏度f = %.2lf\n", c, f); printf("\n"); } return 0; }test7
#include <stdio.h> #include <math.h> int main() { double a, b, c; double s; double area; while (scanf("%lf %lf %lf", &a, &b, &c) != EOF) { s = (a + b + c) / 2; area = sqrt(s * (s - a) * (s - b) * (s - c)); printf("a = %d, b = %d, c = %d, area = %.3lf\n", (int)a, (int)b, (int)c, area); printf("\n"); } return 0; }
标签:main,return,int,double,实验,printf,include From: https://www.cnblogs.com/LHLH0512/p/17745228.html