实验一
task1-1.c
1 #include<stdio.h>
2 int main()
3 {
4 printf(" O \n");
5 printf("<H>\n");
6 printf("I I\n");
7 printf(" O \n");
8 printf("<H>\n");
9 printf("I I\n");
10
11 return 0;
12 }
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task1-2.c
1 #include<stdio.h>
2 int main()
3 {
4 printf(" O O \n");
5 printf("<H> <H>\n");
6 printf("I I I I\n");
7
8
9 return 0;
10 }
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task2.c
#include<stdio.h>
int main()
{
float a,b,c;
scanf("%f%f%f",&a,&b,&c);
if(a+b>c&a+c>b&b+c>a )
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
return 0;
}
task3.c
1 #include <stdio.h>
2 int main()
3 {
4 char ans1, ans2; // 用于保存用户输入的答案
5 printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) :");
6
7 ans1 = getchar(); // 从键盘输入一个字符，赋值给ans1
8 getchar(); // 思考这里为什么要加这一行。试着去掉这一行，看看对运行有没有影响。
9 printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) : ");
10 ans2 = getchar();
11 if (ans1=='y',ans2=='y'||ans1=='y',ans2=='Y') // 待补足，判断用户回答ans1和ans2都是小写y或大写Y
12 printf("\n罗马不是一天建成的, 继续保持哦:)\n");
13 else
14 printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
15 return 0;
16 }
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1 #include<stdio.h>
2 int main()
3 {
4 double x, y;
5 char c1, c2, c3;
6 int a1, a2, a3;
7 scanf("%d%d%d", &a1, &a2, &a3);
8 printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3);
9 scanf("%c%c%c", &c1, &c2, &c3);
10 printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
11 scanf("%lf %lf", &x, &y);
12 printf("x = %lf, y = %lf\n",x, y);
13 return 0;
14 }
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task4.c
1 #include<stdio.h>
2 int main()
3 {
4 double x, y;
5 char c1, c2, c3;
6 int a1, a2, a3;
7 scanf("%d%d%d", &a1, &a2, &a3);
8 printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3);
9 scanf("%c%c%c", &c1, &c2, &c3);
10 printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
11 scanf("%f%lf", &x, &y);
12 printf("x = %f, y = %lf\n",x, y);
13 return 0;
14 }
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1 #include<stdio.h>
2 int main()
3 {
4 double x, y;
5 char c1, c2, c3;
6 int a1, a2, a3;
7 scanf("%d%d%d", &a1, &a2, &a3);
8 printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3);
9 scanf("%c%c%c", &c1, &c2, &c3);
10 printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
11 scanf("%lf %lf", &x, &y);
12 printf("x = %lf, y = %lf\n",x, y);
13 return 0;
14 }
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task5.c
1 #include <stdio.h>
2 #include <stdlib.h>
3 int main()
4 {
5 double year;
6 double num = 1000000000;
7 year = num/(3600*24*365);
8 if (year-int(year) < 0.5)
9 printf("10亿秒约等于%d年\n", int(year));
10 else{
11 printf("10亿秒约等于%d年\n", int(year + 1));
12 }
13 return 0;
14 }
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test6.1.c
1 #include <stdio.h>
2 #include <math.h>
3 int main()
4 {
5 double x, ans;
6 scanf("%lf", &x);
7 ans = pow(x, 365);
8 printf("%.2f的365次方: %.2f\n", x, ans);
9 return 0;
10 }
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test6.2.c
1 #include <stdio.h>
2 #include <math.h>
3
4 int main()
5 {
6 double x, ans;
7
8 while(scanf("%lf",&x) != EOF)
9 {ans = pow(x, 365);
10 printf("%.2f的365次方：%.2f\n", x, ans);
11 printf("\n");
12 }
13 return 0;
14 }
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text7.c
1 #include <stdio.h>
2 #include <math.h>
3 int main()
4 {
5 float c,f;
6
7 while(scanf("%f",&c) != EOF){
8
9 f = 9*c/5 +32;
10 printf("摄氏度c = %.2f时 华氏度f = %.2f\n\n",c,f);
11 }
12
13 return 0;
14 }
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test8.c
1 #include <stdio.h>
2 #include <math.h>
3 int main()
4 {
5 int a,b,c;
6 double s,area;
7 while(scanf("%d%d%d",&a,&b,&c) != EOF)
8 {
9 s = ((double)a+(double)b+(double)c)/2;
10 area = sqrt(s*(s-a)*(s-b)*(s-c));
11 printf("a = %d b = %d c = %d area = %.3lf ",a,b,c,area);
12 }
13 return 0;
14 }
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标签：lf,10,int,scanf,实验,printf,include From： https://www.cnblogs.com/zyqJ/p/17735919.html