// 计算10亿秒约等于多少年,并打印输出 #include <stdio.h> int main() { int year; year = 1e9 / (60 * 60 * 24 * 365+0.5
); printf("10亿秒约等于%d年\n", year); return 0; }
#include<stdio.h> int main() { double c; double f; while (scanf_s("%lf", &c) != EOF) { f = (9 / 5) * c + 32; printf("当摄氏度c=%.2f时,华氏度f=%.2f", c, f); } return 0; }
#include <stdio.h> #include <math.h> int main() { double a, b, c,s,area; while (scanf("%lf%lf%lf", &a, &b, &c)!=EOF) { s = (a + b + c) / 2; area = sqrt(s * (s - a) * (s - b) * (s - c)); printf("a=%lf,b=%lf,c=%lf,area=%.3f", a, b, c, area); } return 0; }
#include <stdio.h> #include <math.h> int main() { double x, ans; while (scanf_s("%lf", &x) != EOF) { ans = pow(x, 365); printf("%.2f的365次方: %.2f\n", x, ans); printf("\n"); } return 0; }
#include<stdio.h> int main() { printf(" 0\n"); printf("<H>\n"); printf("I I\n"); printf(" 0\n"); printf("<H>\n"); printf("I I\n"); system("pause"); return 0; }
#include<stdio.h> int main() { printf(" 0 0\n"); printf("<H> <H>\n"); printf("I I I I\n"); system("pause"); return 0; }
#include<stdio.h> int main() { float a, b, c; scanf("%f%f%f",&a,&b,&c); if(a+b>c&a+c>b&b+c>a) printf("能够成三角形\n"); else printf("不能够成三角形"); system("pause"); return 0; }
#include<stdio.h> int main() { char ans1,ans2; printf("每次课前认真预习,课后及时复习了没(输入y或Y表示有,输入n或N表示没有):"); ans1=getchar(); getchar(); printf("\n动手敲代码实践了没(输入y或Y表示敲了,输入n或N表示木有敲):"); ans2=getchar(); if( ((ans1=='y' )| ans1 =='Y')&( (ans2 =='y')|ans2=='Y')) printf("\n罗马不是一天建成的,继续保持哦)\n"); else printf("\n罗马不是一天毁灭的,我们来建设吧\n"); system("pause"); return 0; }
标签:lf,include,return,int,实验,printf,main From: https://www.cnblogs.com/suning17/p/17735884.html