task1
#include <stdio.h> #include <stdlib.h> #include <time.h> #include <windows.h> #define N 80 void print_text(int line, int col, char text[]); void print_spaces(int n); void print_blank_lines(int n); int main() { int line, col, i; char text[N] = "hi, April~"; srand(time(0)); for(i = 1; i <= 10; ++i){ line = rand() % 25; col = rand() % 80; print_text(line, col, text); Sleep(1000); } return 0; } void print_spaces(int n){ int i; for(i = 1; i <= n; ++i) printf(" "); } void print_blank_lines(int n){ int i; for(i = 1; i <= n; ++i) printf("\n"); } void print_text(int line, int col, char text[]){ print_blank_lines(line-1); print_spaces(col-1); printf("%s", text); }
功能:每隔1000ms将指定字符串随机打在屏幕上
task 2
#include <stdio.h> long long fac(int n); int main() { int i, n; printf("Enter n:"); scanf("%d", &n); for(i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n){ static long long p = 1; p = p * n; printf("p = %llf\n", p); return p; }
#include <stdio.h> int func(int, int); int main() { int k = 4, m = 1, p1, p2; p1 = func(k, m); p2 = func(k, m); printf("%d, %d\n", p1, p2); return 0; } int func(int a, int b){ static int m = 0, i = 2; i += m + 1; m = i + a + b; return m; }
实验运行结果与理论分析一致。
static变量特性:每次运算后,会保留变量运算后的变量的值,并以此作为下一次函数调用的变量初始值。
task3
#include <stdio.h> long long func(int n); int main() { int n; long long f; while(scanf("%d", &n) != EOF){ f = func(n); printf("n = %d, f = %lld\n", n, f); } return 0; } long long func(int n){ if(n == 1) return 1; else return func(n - 1) * 2 + 1; }
task4
#include <stdio.h> int func(int n, int m); int main() { int n, m; while(scanf("%d%d", &n, &m) != EOF) printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m)); return 0; } int func(int n, int m){ if(n < m) return 0; else if(n == 1 || m == 0) return 1; else return func(n - 1, m) + func(n - 1, m - 1); }
task5_1
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while(scanf("%d%d", &x, &y) != EOF){ ans = mypow(x, y); printf("%d的%d次方:%g\n\n", x, y, ans); } return 0; } double mypow(int x, int y){ int i; double ans = 1; if(y >= 0){ for(i = 0; i <= y-1; i++) ans = ans * x; return ans;} else for(i = 1;i <= -y; i++) ans = ans / x; return ans; }
task5_2
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while(scanf("%d%d", &x, &y) != EOF){ ans = mypow(x, y); printf("%d的%d次方:%g\n\n", x, y, ans); } return 0; } double mypow(int x, int y){ double ans; if(y == 0) return 1; if(y >= 0){ ans = mypow(x, y-1) * x; return ans; } else ans = mypow(x, y+1) / x; return ans; }
task6
#include <stdio.h> #include <stdlib.h> void hanoi(unsigned int n,char from,char temp,char to); void moveplate(unsigned int n,char from,char to); int sum = 0; int main() { unsigned int n; while(scanf("%u", &n) != EOF){ hanoi(n, 'A', 'B', 'C'); printf("\n一共移动了%d次。\n", sum); sum = 0; } return 0; } void hanoi(unsigned int n,char from,char temp,char to){ if(n == 1) moveplate(n, from, to); else { hanoi(n-1, from, to, temp); moveplate(n, from, to); hanoi(n-1, temp, from, to); } } void moveplate(unsigned int n,char from,char to){ printf("%u: %c --> %c\n", n, from, to); sum += 1; }
task7
#include <stdio.h> #include <math.h> #include <windows.h> int is_prime(int n); int main() { int i, a, j, k; for(a = 1;a <= 20; a++){ if((a % 2 == 0)&& (a >= 4)){ for(i = 1;i < a; i++){ if(is_prime(i)) if(is_prime(a - i)){ j = i; k = a - i;} }printf("%d = %d + %d\n", a, j, k); } } return 0; } int is_prime(int n){ int i; for(i = 2; i <= n; i++){ if(n % i == 0) break; } if(i == n) return 1; else return 0; }
task8
#include <stdio.h> #include <math.h> long func(long s); int main() { long s, t; printf("Enter a number: "); while(scanf("%ld", &s) != EOF){ t = func(s); printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } long func(long s){ int y, a, i = 1; while(s != 0){ y = s % 10; if(y != 0 && y % 2 != 0){ a += y * pow(10, i-1); i++;} s = s / 10; } return a; }
标签:return,int,long,实验,func,ans,include From: https://www.cnblogs.com/zynzn/p/17273695.html