task1
源代码
#include <stdio.h> #include <stdlib.h> #include <time.h> #include <windows.h> #define N 80 void print_text(int line, int col, char text[]); void print_spaces(int n); void print_blank_lines(int n); int main() { int line, col, i; char text[N] = "hi, April~"; srand(time(0)); for(i = 1; i <= 10; ++i) { line = rand() % 25; col = rand() % 80; print_text(line, col, text); Sleep(1000); } return 0; } void print_spaces(int n) { int i; for(i = 1; i <= n; ++i) printf(" "); } void print_blank_lines(int n) { int i; for(i = 1; i <= n; ++i) printf("\n"); } void print_text(int line, int col, char text[]) { print_blank_lines(line-1); print_spaces(col-1); printf("%s", text); }
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结论
随机生成10次行数和列数,在对应位置输出hi,April~
task2.1
源代码
#include <stdio.h> long long fac(int n); int main() { int i, n; printf("Enter n: "); scanf("%d", &n); for (i = 1; i <= n; ++i) printf("%d! = %lld\n", i, fac(i)); return 0; } long long fac(int n) { static long long p = 1;
printf("p = %lld\n", p); p = p * n; return p; }
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task2.2
源代码
#include <stdio.h> int func(int, int); int main() { int k = 4, m = 1, p1, p2; p1 = func(k, m); p2 = func(k, m); printf("%d, %d\n", p1, p2); return 0; } int func(int a, int b) { static int m = 0, i = 2; i += m + 1; m = i + a + b; return m; }
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task3
源代码
#include <stdio.h> long long func(int n); int main() { int n; long long f; while (scanf("%d", &n) != EOF) { f = func(n); printf("n = %d, f = %lld\n", n, f); } return 0; } long long func(int n){ int i; long long m=0; for(i=1;i<=n;i++){ m=(m+1)*2-1; } return m; }
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task4
源代码
#include <stdio.h> int func(int n,int m); int main(){ int n,m; while(scanf("%d%d",&n,&m)!=EOF){ printf("n=%d,m=%d,ans=%d\n",n,m,func(n,m)); } return 0; } int func(int n,int m){ if (n==m || m==0){ return 1;} else if(n<m){return 0; } return func(n-1,m)+func(n-1,m-1); }
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task5
源代码
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while(scanf("%d%d", &x, &y) != EOF) { ans = mypow(x, y); printf("%d的%d次方: %g\n\n", x, y, ans); } return 0; } double mypow(int x, int y) { int i; double ans=1.0; if(y>=0) { for(i=1;i<=y;i++) ans=ans*x; return ans; } else { for(i=1;(i+y)<=0;i++) ans=ans/x; return ans; } }
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task5.2
源代码
#include <stdio.h> double mypow(int x, int y); int main() { int x, y; double ans; while(scanf("%d%d", &x, &y) != EOF) { ans = mypow(x, y); printf("%d的%d次方: %g\n\n", x, y, ans); } return 0; } double mypow(int x, int y) { double ans=1; if(y==0) ans=1; if(y>0) ans=ans*x*mypow(x,y-1); if(y<0) ans=ans/x*mypow(x,y+1); return ans; }
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task6
源代码
#include<stdio.h> #include<math.h> void hanoi(int n,char from,char temp,char to); void move(int n,char from,char to); int main() { int n; while(scanf("%d", &n) != EOF) { hanoi(n,'A','B','C'); printf("一共移动了%g次\n\n",pow(2,n)-1); } return 0; } void hanoi(int n,char from,char temp,char to) { if(n==1) move(n,from,to); else { hanoi(n-1,from,to,temp); move(n,from,to); hanoi(n-1,temp,from,to); } } void move(int n,char from,char to) { printf("%d:%c-->%c\n",n,from,to); }
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task7
源代码
#include<stdio.h> int is_prime(int n); int main() { int n,i; for(n=4;n<=20;n+=2) { for(i=2;i<=(n/2);i++) { if(is_prime(i)&&is_prime(n-i)) { printf("%d = %d + %d\n",n,i,n-i); break; } } } return 0; } int is_prime(int n) { int i,flag=1; for(i=2;i<n;i++) { if(n%i==0) flag=0; } return flag; }
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task8
源代码
#include <stdio.h> #include <math.h> long func(long s); int main() { long s, t; printf("Enter a number: "); while (scanf("%ld", &s) != EOF) { t = func(s); printf("new number is: %ld\n\n", t); printf("Enter a number: "); } return 0; } long func(long s) { long ans=0; long x,i=1; while(s!=0) { x=s%10,s=s/10; if(x%2!=0) { ans=ans+x*i; i=i*10; } } return ans; }
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标签:int,long,char,实验,func,ans,include From: https://www.cnblogs.com/qiuyp/p/17273640.html