491. 递增子序列
LinkedList<Integer> path = new LinkedList<>();
List<List<Integer>> result = new ArrayList<>();
public List<List<Integer>> findSubsequences(int[] nums) {
backTracing(nums, 0);
return result;
}
public void backTracing(int[] nums, int startIndex) {
if (path.size() > 1) {
result.add(new ArrayList<>(path));
}
boolean[] used = used = new boolean[201];
for (int i = startIndex; i < nums.length; i++) {
if ((!path.isEmpty() && path.getLast() > nums[i]) || used[nums[i] + 100]) {
continue;
}
used[nums[i] + 100] = true;
path.add(nums[i]);
backTracing(nums, i + 1);
path.removeLast();
}
}
46. 全排列
``List<Integer> path = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
boolean[] used;
public List<List<Integer>> permute(int[] nums) {
used = new boolean[nums.length];
backTracing(nums, nums.length);
return res;
}
public void backTracing(int[] nums, int size) {
if (path.size() == size) {
res.add(new ArrayList<>(path));
return;
}
for (int i = 0; i < nums.length; i++) {
if (!used[i]) {
path.add(nums[i]);
used[i] = true;
}else {
continue;
}
backTracing(nums, size);
path.remove(path.size()-1);
used[i] = false;
}
}`
### 47. 全排列 II
```java\
List<Integer> path = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
boolean[] used;
public List<List<Integer>> permuteUnique(int[] nums) {
Arrays.sort(nums);
used = new boolean[nums.length];
backTracing2(nums,nums.length);
return res;
}
public void backTracing2(int[] nums, int size) {
if (path.size() == size) {
res.add(new ArrayList<>(path));
}
for (int i = 0; i < nums.length; i++) {
if (i > 0 && nums[i] == nums[i - 1] && !used[i - 1]) {
continue;
}
if (!used[i]) {
path.add(nums[i]);
used[i] = true;
backTracing2(nums, size);
used[i] = false;
path.remove(path.size() - 1);
}
}
}
标签:used,nums,int,47,40,二刷,new,path,size
From: https://www.cnblogs.com/Chain-Tian/p/17048389.html