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100028 求扇形的弦长已知半径角度

时间:2022-12-08 18:46:24浏览次数:41  
标签:50 角度 110 100028 半径 sin 扇形

<?php
header('Content-Type: text/html; charset=utf-8');
define ('ROOT', $_SERVER['DOCUMENT_ROOT']);
include ROOT.'/assets/php/head.php';

$tit= '求扇形的弦长已知半径角度';
// 半径为50 ,角度为110
$val='50 110';
$img='';

//调用方法
mill($val,$img,$tit);

/**
 * mill 是磨粉机的方法
 * $val 传值过来计算,以空格分割成数值
 * $img 自定义图片名,默认以文件名为图片名
 * $tit 标题名
 * */
function mill($val,$img,$tit){
    //初始化
    include ROOT.'/assets/php/init.php';
    imgt($img,$tit);

    //设置小数点保留位数 
    bcscale (2);
    //$pi = round(pi(),2);

     //以空格分割成数值
    $vals = expl($val);
    $r = evev($vals[0]);
    $co = evev($vals[1]);

    //已知条件
    $know = array();
    array_push($know, $val);
    $v0 = eveq($vals[0]);
    array_push($know, "半径:$v0");
    $v1 = eveq($vals[1]);
    array_push($know, "角度:$v1");

    //计算步骤
    $step = array();
    array_push($step, "求扇形的弦长:");
    array_push($step, "{$math['eq']} $r{$math['mul']}sin{$math['lpar']}$co{$math['div']}2{$math['rpar']}{$math['mul']}2");
    $co2 = bcdiv($co, 2);
    array_push($step, "{$math['eq']} $r{$math['mul']}sin{$math['lpar']}$co2{$math['rpar']}{$math['mul']}2");
    $sinco2 = sin(deg2rad($co2));
    array_push($step, "{$math['eq']} $r{$math['mul']}$sinco2{$math['mul']}2");
    $rsinco2 = bcmul($r, $sinco2);
    array_push($step, "{$math['eq']} $rsinco2{$math['mul']}2");
    $c = bcmul($rsinco2, 2);
    array_push($step, "{$math['eq']} $c");

    //算出结果
    $ends = array();
    array_push($ends, "扇形的弦长:{$c}");

    //公式表示
    $home = array();
    array_push($home, "扇形的弦长:c{$math['eq']}r{$math['mul']}sin{$math['lpar']}{$math['ang']}C{$math['o']}{$math['sol']}2{$math['rpar']}{$math['mul']}2");

    //公式说明
    $info = array();
    array_push($info, "正弦(sin)等于对边比斜边;sinA=a/c;");
    array_push($info, "余弦(cos)等于邻边比斜边;cosA=b/c;");
    array_push($info, "正切(tan)等于对边比邻边;tanA=a/b;");
    array_push($info, "余切(cot)等于邻边比对边;cotA=b/a 。");
    array_push($info, "下面的方法同样可解:");
    array_push($info, "100026 求三角形各边各角度已知两边夹角:https://www.cnblogs.com/onestopweb/p/16939982.html");
    
    know($know);
    ends($ends);
    home($home);
    step($step);
    info($info);
}
?>
<?php include ROOT.'/assets/php/foot.php'; ?>

☁参考上图[22-12-08 chaoyi]

☀求扇形的弦长已知半径角度
50 110  
半径:50  
角度:110  

♠算出结果  
扇形的弦长:81.90  

♥公式表示  
扇形的弦长:c=r×sin(∠C°/2)×2  

♣计算步骤  
求扇形的弦长:  
= 50×sin(110÷2)×2  
= 50×sin(55.00)×2  
= 50×0.81915204428899×2  
= 40.95×2  
= 81.90  

♦公式说明  
正弦(sin)等于对边比斜边;sinA=a/c;  
余弦(cos)等于邻边比斜边;cosA=b/c;  
正切(tan)等于对边比邻边;tanA=a/b;  
余切(cot)等于邻边比对边;cotA=b/a 。  
下面的方法同样可解:  
100026 求三角形各边各角度已知两边夹角:https://www.cnblogs.com/onestopweb/p/16939982.html  

标签:50,角度,110,100028,半径,sin,扇形
From: https://www.cnblogs.com/onestopweb/p/16966956.html

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