1 #嵌套列表解析，讲3*4的矩阵转换成4*3的矩阵
2
3 matrix = [[1, 2, 3, 4],
4 [5, 6, 7, 8],
5 [9, 10, 11, 12]]
6
7
8 for row in matrix:
9 print("遍历每一行：",row)
10
11
12 print(" \n ")
13
14 s = [[row[i] for row in matrix] for i in range(4)]
15 print(s)
标签：转换成,matrix,Python,矩阵,嵌套,print,row From： https://www.cnblogs.com/bravesunforever/p/17674588.html