任务五:
vectorlnt.h
#pragma once #include<iostream> using std::cout; using std::cin; using std::endl; class vectorlnt { friend void output(const vectorlnt& obj); public: vectorlnt(int n); vectorlnt(int n, int val); vectorlnt(const vectorlnt& obj); int& at(int index); ~vectorlnt(); private: int size; int* data; }; vectorlnt::vectorlnt(int n) { data = new int[n]; size = n; cout << "构造1" << endl; } vectorlnt::vectorlnt(int n, int val) { data = new int[n]; size = n; for (int i = 0; i < n; i++) data[i] = val; cout << "构造2" << endl; } vectorlnt::vectorlnt(const vectorlnt& obj) { data = new int[obj.size]; size = obj.size; for (int i = 0; i < obj.size; i++) data[i] = obj.data[i]; cout << "复制构造" << endl; } int& vectorlnt::at(int index) { return data[index]; } vectorlnt::~vectorlnt() { size = 0; delete [] data; data = nullptr; cout << "析构" << endl; } void output(const vectorlnt& obj) { for (int i = 0; i < obj.size; i++) { cout << obj.data[i] << " "; } cout << endl; }
main.h
#include <iostream> #include "vectorlnt.h" using namespace std; void test() { using namespace std; int n; cin >> n; vectorlnt x1(n); for (auto i = 0; i < n; ++i) x1.at(i) = i * i; output(x1);
vectorlnt x2(n, 42); vectorlnt x3(x2); output(x2); output(x3); x2.at(0) = 77; output(x2); output(x3); } int main() { test(); }
任务五
matrix.h
#pragma once #include <iostream> using std::cout; using std::endl; class Matrix { public: Matrix(int n); // 构造函数,构造一个n*n的矩阵 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵 Matrix(const Matrix& X); // 复制构造函数,使用已有的矩阵X构造 ~Matrix(); //析构函数 void set(const double* pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 void set(int i, int j, double value); //设置矩阵第i行第j列元素值为value double& at(int i, int j); //返回矩阵第i行第j列元素的引用 double at(int i, int j) const; // 返回矩阵第i行第j列元素的值 int get_lines() const; //返回矩阵行数 int get_cols() const; //返回矩列数 void print() const; // 按行打印输出矩阵 private: int lines; // 矩阵行数 int cols; // 矩阵列数 double* p; // 指向存放矩阵数据的内存块的首地址 }; Matrix::Matrix(int n) { p = new double [n * n]; lines = cols = n; } Matrix::Matrix(int n, int m) { p = new double[n * m]; lines = n; cols = m; } Matrix::Matrix(const Matrix& x) { p = new double[x.lines * x.cols]; lines = x.lines; cols = x.cols; for (int i = 0; i < x.lines; i++) { for (int j = 0; j < x.cols; j++) { p[i * x.cols + j] = x.p[i * x.cols + j]; } } } Matrix::~Matrix() { delete[] p; p = nullptr; lines = cols = 0; } void Matrix::set(const double* pvalue) { int size = lines * cols; for (int i = 0; i < size; i++) p[i] = pvalue[i]; } void Matrix::set(int i, int j, double value) { p[i * cols + j] = value; } double& Matrix::at(int i, int j) { return p[i * cols + j]; } double Matrix::at(int i, int j)const { return p[i * cols + j]; } int Matrix::get_lines()const { return lines; } int Matrix::get_cols()const { return cols; } void Matrix::print()const { for (int i = 0; i < lines; i++) { for (int j = 0; j < cols; j++) { cout << p[i * cols + j] << " "; } cout << endl; } }
main.cpp
#include <iostream> #include "matrix.h" void test() { using namespace std; double x[] = { 6, 5, 4, 3, 2, 1 }; Matrix m1(3, 2); // 创建一个3×2的矩阵 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 m1.print(); // 打印矩阵m1的值 cout << "the first line is: " << endl; cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl; // 输出矩阵m1第1行两个元素的值 cout << endl; Matrix m2(2, 3); m2.set(x); m2.print(); cout << "the first line is: " << endl; cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl; cout << endl; Matrix m3(m2); // 用矩阵m2构造新的矩阵m3 m3.set(0, 0, 999); // 将矩阵m3第0行第0列元素值设为999 m3.print(); } int main() { test(); }
标签:const,Matrix,int,double,cols,实验,vectorlnt From: https://www.cnblogs.com/xelfin/p/16850432.html