请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。
数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)
注意:
一个有效的数独(部分已被填充)不一定是可解的。
只需要根据以上规则,验证已经填入的数字是否有效即可。
空白格用 '.' 表示。
示例 1:
输入:board =
[["5","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
输出:true
示例 2:
输入:board =
[["8","3",".",".","7",".",".",".","."]
,["6",".",".","1","9","5",".",".","."]
,[".","9","8",".",".",".",".","6","."]
,["8",".",".",".","6",".",".",".","3"]
,["4",".",".","8",".","3",".",".","1"]
,["7",".",".",".","2",".",".",".","6"]
,[".","6",".",".",".",".","2","8","."]
,[".",".",".","4","1","9",".",".","5"]
,[".",".",".",".","8",".",".","7","9"]]
输出:false
解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
提示:
board.length == 9
board[i].length == 9
board[i][j]
是一位数字(1-9
)或者'.'
1 /** 2 * @param {character[][]} board 3 * @return {boolean} 4 */ 5 var isValidSudoku = function(board) { 6 //数独的每一行中每个数字的出现次数 7 const rows = new Array(9).fill(0).map(()=>new Array(9).fill(0)); 8 //数独的每一列中每个数字的出现次数 9 const columns = new Array(9).fill(0).map(()=>new Array(9).fill(0)); 10 //数独的每一个九宫格中的每个数字的出现次数 11 const subboxes=new Array(3).fill(0).map(()=>new Array(3).fill(0).map(()=>new Array(9).fill(0))); 12 for(let i =0;i<9;i++){ 13 for(let j =0;j<9;j++){ 14 const c = board[i][j]; 15 if(c!=='.'){ 16 const index = c.charCodeAt()-'0'.charCodeAt()-1; 17 rows[i][index]++; 18 columns[j][index]++; 19 subboxes[Math.floor(i/3)][Math.floor(j/3)][index]++; 20 if(rows[i][index]>1||columns[j][index]>1||subboxes[Math.floor(i/3)][Math.floor(j/3)][index]>1){ 21 return false; 22 } 23 } 24 } 25 } 26 return true; 27 };
标签:数字,36,有效,board,new,Array,数独,fill From: https://www.cnblogs.com/icyyyy/p/16849421.html