1 #pragma once 2 3 #include <iostream> 4 #include <string> 5 6 using std::string; 7 using std::cout; 8 9 // 按钮类 10 class Button { 11 public: 12 Button(const string &text); 13 string get_label() const; 14 void click(); 15 16 private: 17 string label; 18 }; 19 20 Button::Button(const string &text): label{text} { 21 } 22 23 inline string Button::get_label() const { 24 return label; 25 } 26 27 void Button::click() { 28 cout << "Button '" << label << "' clicked\n"; 29 } 30 31 32 33 #pragma once 34 #include "button.hpp" 35 #include <vector> 36 #include <iostream> 37 38 using std::vector; 39 using std::cout; 40 using std::endl; 41 42 // 窗口类 43 class Window{ 44 public: 45 Window(const string &win_title); 46 void display() const; 47 void close(); 48 void add_button(const string &label); 49 50 private: 51 string title; 52 vector<Button> buttons; 53 }; 54 55 Window::Window(const string &win_title): title{win_title} { 56 buttons.push_back(Button("close")); 57 } 58 59 inline void Window::display() const { 60 string s(40, '*'); 61 62 cout << s << endl; 63 cout << "window title: " << title << endl; 64 cout << "It has " << buttons.size() << " buttons: " << endl; 65 for(const auto &i: buttons) 66 cout << i.get_label() << " button" << endl; 67 cout << s << endl; 68 } 69 70 void Window::close() { 71 cout << "close window '" << title << "'" << endl; 72 buttons.at(0).click(); 73 } 74 75 void Window::add_button(const string &label) { 76 buttons.push_back(Button(label)); 77 } 78 79 80 81 82 #include "window.hpp" 83 #include <iostream> 84 85 using std::cout; 86 using std::cin; 87 88 void test() { 89 Window w1("new window"); 90 w1.add_button("maximize"); 91 w1.display(); 92 w1.close(); 93 } 94 95 int main() { 96 cout << "用组合类模拟简单GUI:\n"; 97 test(); 98 }task1
1.两个类window和button 两个标准库类string和vector。
2.没必要。剩下的函数执行时不会改变对象值。
3.定义一个对象s,其长度为40且都是“*”。
1 #include <iostream> 2 #include <vector> 3 4 using namespace std; 5 6 void output1(const vector<int> &v) { 7 for(auto &i: v) 8 cout << i << ", "; 9 cout << "\b\b \n"; 10 } 11 12 void output2(const vector<vector<int>> v) { 13 for(auto &i: v) { 14 for(auto &j: i) 15 cout << j << ", "; 16 cout << "\b\b \n"; 17 } 18 } 19 20 void test1() { 21 vector<int> v1(5, 42); 22 const vector<int> v2(v1); 23 24 v1.at(0) = -999; 25 cout << "v1: "; output1(v1); 26 cout << "v2: "; output1(v2); 27 cout << "v1.at(0) = " << v1.at(0) << endl; 28 cout << "v2.at(0) = " << v2.at(0) << endl; 29 } 30 31 void test2() { 32 vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}}; 33 const vector<vector<int>> v2(v1); 34 35 v1.at(0).push_back(-999); 36 cout << "v1: \n"; output2(v1); 37 cout << "v2: \n"; output2(v2); 38 39 vector<int> t1 = v1.at(0); 40 cout << t1.at(t1.size()-1) << endl; 41 42 const vector<int> t2 = v2.at(0); 43 cout << t2.at(t2.size()-1) << endl; 44 } 45 46 int main() { 47 cout << "测试1:\n"; 48 test1(); 49 50 cout << "\n测试2:\n"; 51 test2(); 52 }task2
1.定义一个长度为5的一维数组,其元素均为42;定义一个和v1相同的数组v2;将v1中第一个元素修改为-999。
2.定义一个二维数组v1,第一行为123,第二行为4567;定义一个和v1相同且值不能改变的数组v2;在v1第一行末尾插入一个值-999。
3.定义一个数组t1,其元素为v1的第一行元素,输出t1的最后一个元素;定义一个不能改变的数组v2,其值为v2的第一行元素,输出t2的最后一个元素。
4.深复制;是
1 #include "vectorInt.hpp" 2 #include <iostream> 3 4 using std::cin; 5 using std::cout; 6 7 void output(const vectorInt &vi) { 8 for(auto i = 0; i < vi.get_size(); ++i) 9 cout << vi.at(i) << ", "; 10 cout << "\b\b \n"; 11 } 12 13 14 void test1() { 15 int n; 16 cout << "Enter n: "; 17 cin >> n; 18 19 vectorInt x1(n); 20 for(auto i = 0; i < n; ++i) 21 x1.at(i) = i*i; 22 cout << "x1: "; output(x1); 23 24 vectorInt x2(n, 42); 25 vectorInt x3(x2); 26 x2.at(0) = -999; 27 cout << "x2: "; output(x2); 28 cout << "x3: "; output(x3); 29 } 30 31 void test2() { 32 const vectorInt x(5, 42); 33 vectorInt y(10, 0); 34 35 cout << "y: "; output(y); 36 y.assign(x); 37 cout << "y: "; output(y); 38 39 cout << "x.at(0) = " << x.at(0) << endl; 40 cout << "y.at(0) = " << y.at(0) << endl; 41 } 42 43 int main() { 44 cout << "测试1: \n"; 45 test1(); 46 47 cout << "\n测试2: \n"; 48 test2(); 49 } 50 51 52 53 #pragma once 54 55 #include <iostream> 56 #include <cassert> 57 58 using std::cout; 59 using std::endl; 60 61 // 动态int数组对象类 62 class vectorInt{ 63 public: 64 vectorInt(int n); 65 vectorInt(int n, int value); 66 vectorInt(const vectorInt &vi); 67 ~vectorInt(); 68 69 int& at(int index); 70 const int& at(int index) const; 71 72 vectorInt& assign(const vectorInt &v); 73 int get_size() const; 74 75 private: 76 int size; 77 int *ptr; // ptr指向包含size个int的数组 78 }; 79 80 vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} { 81 } 82 83 vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} { 84 for(auto i = 0; i < size; ++i) 85 ptr[i] = value; 86 } 87 88 vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} { 89 for(auto i = 0; i < size; ++i) 90 ptr[i] = vi.ptr[i]; 91 } 92 93 vectorInt::~vectorInt() { 94 delete [] ptr; 95 } 96 97 const int& vectorInt::at(int index) const { 98 assert(index >= 0 && index < size); 99 100 return ptr[index]; 101 } 102 103 int& vectorInt::at(int index) { 104 assert(index >= 0 && index < size); 105 106 return ptr[index]; 107 } 108 109 vectorInt& vectorInt::assign(const vectorInt &v) { 110 delete[] ptr; // 释放对象中ptr原来指向的资源 111 112 size = v.size; 113 ptr = new int[size]; 114 115 for(int i = 0; i < size; ++i) 116 ptr[i] = v.ptr[i]; 117 118 return *this; 119 } 120 121 int vectorInt::get_size() const { 122 return size; 123 }task3
1.深复制。
2.不能。存在安全隐患,int&表示新变量与其共享内存,若去掉const,后续新变量值改变时会一起改变原先变量的值。
3.可以。这段代码目的是为了将v的内容赋值给当前对象,若改成vectorint,就是调用复制构造函数生成一个新对象,对结果没有影响。
1 #pragma once 2 3 #include <iostream> 4 #include <cassert> 5 6 using std::cout; 7 using std::endl; 8 9 // 类Matrix的声明 10 class Matrix { 11 public: 12 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value 13 Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value 14 Matrix(const Matrix &x); // 复制构造函数, 使用已有的矩阵X构造 15 ~Matrix(); 16 17 void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 18 void clear(); // 把矩阵对象的值置0 19 20 const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用 21 double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用 22 23 int get_lines() const; // 返回矩阵对象行数 24 int get_cols() const; // 返回矩阵对象列数 25 26 void display() const; // 按行显示矩阵对象元素值 27 28 private: 29 int lines; // 矩阵对象内元素行数 30 int cols; // 矩阵对象内元素列数 31 double *ptr; 32 }; 33 34 // 类Matrix的实现:待补足 35 // xxx 36 37 38 39 40 41 #include "matrix.hpp" 42 #include <iostream> 43 #include <cassert> 44 45 using namespace std; 46 47 // 构造函数:使用行数 n 和列数 m 初始化矩阵 48 Matrix::Matrix(int n, int m) : lines(n), cols(m) { 49 assert(n > 0 && m > 0); 50 ptr = new double[n * m](); // 动态分配内存并初始化为 0 51 } 52 53 // 构造函数:初始化为一个 n x n 的方阵 54 Matrix::Matrix(int n) : lines(n), cols(n) { 55 assert(n > 0); 56 ptr = new double[n * n](); // 动态分配内存并初始化为 0 57 } 58 59 // 拷贝构造函数:进行深复制 60 Matrix::Matrix(const Matrix& x) : lines(x.lines), cols(x.cols) { 61 ptr = new double[lines * cols]; 62 for (int i = 0; i < lines * cols; ++i) { 63 ptr[i] = x.ptr[i]; 64 } 65 } 66 67 // 析构函数:释放动态分配的内存 68 Matrix::~Matrix() { 69 delete[] ptr; 70 } 71 72 // 使用给定的数组 pvalue 初始化矩阵内容 73 void Matrix::set(const double* pvalue) { 74 for (int i = 0; i < lines * cols; ++i) { 75 ptr[i] = pvalue[i]; 76 } 77 } 78 79 // 将矩阵所有元素设为 0 80 void Matrix::clear() { 81 for (int i = 0; i < lines * cols; ++i) { 82 ptr[i] = 0; 83 } 84 } 85 86 // 常量版本的 at 函数:获取矩阵中的元素,不能修改 87 const double& Matrix::at(int i, int j) const { 88 assert(i >= 0 && i < lines && j >= 0 && j < cols); 89 return ptr[i * cols + j]; 90 } 91 92 // 非常量版本的 at 函数:获取矩阵中的元素,可修改 93 double& Matrix::at(int i, int j) { 94 assert(i >= 0 && i < lines && j >= 0 && j < cols); 95 return ptr[i * cols + j]; 96 } 97 98 // 获取矩阵的行数 99 int Matrix::get_lines() const { 100 return lines; 101 } 102 103 // 获取矩阵的列数 104 int Matrix::get_cols() const { 105 return cols; 106 } 107 108 // 输出矩阵的内容 109 void Matrix::display() const { 110 for (int i = 0; i < lines; ++i) { 111 for (int j = 0; j < cols; ++j) { 112 cout << at(i, j) << " "; 113 } 114 cout << endl; 115 } 116 } 117 118 119 120 121 #include "matrix.hpp" 122 #include <iostream> 123 #include <cassert> 124 125 using std::cin; 126 using std::cout; 127 using std::endl; 128 129 130 const int N = 1000; 131 132 // 输出矩阵对象索引为index所在行的所有元素 133 void output(const Matrix &m, int index) { 134 assert(index >= 0 && index < m.get_lines()); 135 136 for(auto j = 0; j < m.get_cols(); ++j) 137 cout << m.at(index, j) << ", "; 138 cout << "\b\b \n"; 139 } 140 141 142 void test1() { 143 double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; 144 145 int n, m; 146 cout << "Enter n and m: "; 147 cin >> n >> m; 148 149 Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m 150 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 151 152 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n 153 m2.set(x); // 用一维数组x的值按行为矩阵m1赋值 154 155 Matrix m3(2); // 创建一个2×2矩阵对象 156 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值 157 158 cout << "矩阵对象m1: \n"; m1.display(); cout << endl; 159 cout << "矩阵对象m2: \n"; m2.display(); cout << endl; 160 cout << "矩阵对象m3: \n"; m3.display(); cout << endl; 161 } 162 163 void test2() { 164 Matrix m1(2, 3); 165 m1.clear(); 166 167 const Matrix m2(m1); 168 m1.at(0, 0) = -999; 169 170 cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl; 171 cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl; 172 cout << "矩阵对象m1第0行: "; output(m1, 0); 173 cout << "矩阵对象m2第0行: "; output(m2, 0); 174 } 175 176 int main() { 177 cout << "测试1: \n"; 178 test1(); 179 180 cout << "测试2: \n"; 181 test2(); 182 }task4
1 #pragma once 2 #include <iostream> 3 #include <string> 4 5 using namespace std; 6 7 class User { 8 private: 9 string name; // 用户名 10 string password; // 密码 11 string email; // 邮箱 12 13 public: 14 // 构造函数:允许仅使用用户名初始化 15 User(const string& n, const string& p = "", const string& e = "") 16 : name(n), password(p), email(e) {} 17 18 // 设置邮箱 19 void set_email() { 20 string input_email; 21 while (true) { 22 cout << "Enter email address: "; 23 cin >> input_email; 24 25 // 简单检查邮箱是否包含 '@' 和 '.' 符号 26 if (input_email.find('@') != string::npos && input_email.find('.') != string::npos) { 27 email = input_email; 28 cout << "Email is set successfully..." << endl; 29 break; 30 } else { 31 cout << "Illegal email. Please re-enter email: "; 32 } 33 } 34 } 35 36 // 修改密码 37 void change_password() { 38 string old_password, new_password, confirm_password; 39 40 cout << "Enter old password: "; 41 cin >> old_password; 42 43 // 检查旧密码是否正确 44 if (old_password == password) { 45 while (true) { 46 cout << "Enter new password: "; 47 cin >> new_password; 48 49 cout << "Please re-enter again: "; 50 cin >> confirm_password; 51 52 // 检查两次输入的密码是否一致 53 if (new_password == confirm_password) { 54 password = new_password; 55 cout << "New password is set successfully..." << endl; 56 break; 57 } else { 58 cout << "Password input error. Please re-enter again." << endl; 59 } 60 } 61 } else { 62 cout << "Password input error. Please try after a while." << endl; 63 } 64 } 65 66 // 显示用户信息 67 void display() const { 68 cout << "Name: " << name << endl; 69 cout << "Pass: " << (password.empty() ? "******" : password) << endl; 70 cout << "Email: " << (email.empty() ? "******" : email) << endl; 71 } 72 }; 73 74 75 76 77 78 #include "user.hpp" 79 #include <iostream> 80 #include <vector> 81 #include <string> 82 83 using std::cin; 84 using std::cout; 85 using std::endl; 86 using std::vector; 87 using std::string; 88 89 void test() { 90 vector<User> user_lst; 91 92 User u1("Alice", "2024113", "[email protected]"); 93 user_lst.push_back(u1); 94 cout << endl; 95 96 User u2("Bob","123456"); 97 u2.set_email(); 98 u2.change_password(); 99 user_lst.push_back(u2); 100 cout << endl; 101 102 User u3("Hellen"); 103 u3.set_email(); 104 u3.change_password(); 105 user_lst.push_back(u3); 106 cout << endl; 107 108 cout << "There are " << user_lst.size() << " users. they are: " << endl; 109 for(auto &i: user_lst) { 110 i.display(); 111 cout << endl; 112 } 113 } 114 115 int main() { 116 test(); 117 }task5
1 #pragma once 2 class Date { 3 private: 4 int year; int month; int day; int totalDays; 5 public: 6 Date(int year, int month, int day); 7 int getYear()const { return year; } 8 int getMonth()const { return month; } 9 int getDay()const { return day; } 10 int getMaxDay()const; 11 bool isLeapYear()const { 12 return year % 4 == 0 && year % 100 != 0 || year % 400 == 0; 13 } 14 void show()const; 15 int distance(const Date& date)const { 16 return totalDays - date.totalDays; 17 } 18 }; 19 20 21 #include"date.h" 22 #include<iostream> 23 #include<cstdlib> 24 using namespace std; 25 namespace { 26 const int DAYS_BEFORE_MONTH[] = { 0,31,59,90,120,151,181,212,243,273,304,334,365 }; 27 } 28 Date::Date(int year, int month, int day) : year(year), month(month), day(day) { 29 if (day <= 0 || day > getMaxDay()) { 30 cout << "Invalid date:"; 31 show(); 32 cout << endl; 33 exit(1); 34 } 35 int years = year - 1; 36 totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFORE_MONTH[month - 1] + day; 37 if (isLeapYear() && month > 2)totalDays++; 38 } 39 int Date::getMaxDay()const { 40 if (isLeapYear() && month == 2) 41 return 29; 42 else 43 return DAYS_BEFORE_MONTH[month] - DAYS_BEFORE_MONTH[month - 1]; 44 } 45 void Date::show()const { 46 cout << getYear() << "-" << getMonth() << "-" << getDay(); 47 } 48 49 50 #include"date.h" 51 #include<string> 52 class SavingsAccount { 53 private: 54 std::string id; 55 double balance; 56 double rate; 57 Date lastDate; 58 double accumulation; 59 static double total; 60 void record(const Date& date, double amount, const std::string& desc); 61 void error(const std::string& msg)const; 62 double accumulate(const Date& date)const { 63 return accumulation + balance * date.distance(lastDate); 64 } 65 public: 66 SavingsAccount(const Date& date, const std::string& id, double rate); 67 const std::string& getId()const { return id; } 68 double getBalance()const { return balance; } 69 double getRate()const { return rate; } 70 static double getTotal() { return total; } 71 void deposit(const Date& date, double amount, const std::string& desc); 72 void withdraw(const Date& date, double amount, const std::string& desc); 73 void settle(const Date& date); 74 void show()const; 75 }; 76 77 78 #include"account.h" 79 #include<cmath> 80 #include<iostream> 81 using namespace std; 82 double SavingsAccount::total = 0; 83 84 SavingsAccount::SavingsAccount(const Date& date, const string& id, double rate) :id(id), balance(0), rate(rate), lastDate(date), accumulation(0) { 85 date.show(); 86 cout << "\t#" << id << "created" << endl; 87 } 88 void SavingsAccount::record(const Date& date, double amount, const std::string& desc) { 89 accumulation = accumulate(date); 90 lastDate = date; 91 amount = floor(amount * 100 + 0.5) / 100; 92 balance += amount; 93 total += amount; 94 date.show(); 95 cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl; 96 } 97 void SavingsAccount::error(const std::string& msg)const { 98 cout << "Error(#" << id << ");" << msg << endl; 99 } 100 void SavingsAccount::deposit(const Date& date, double amount, const std::string& desc) { 101 record(date, amount, desc); 102 } 103 void SavingsAccount::withdraw(const Date& date, double amount, const std::string& desc) { 104 if (amount > getBalance()) 105 { 106 error("not enough money"); 107 } 108 else 109 record(date, -amount, desc); 110 } 111 void SavingsAccount::settle(const Date& date) { 112 double interest = accumulate(date) * rate / date.distance(Date(date.getYear() - 1, 1, 1)); 113 if (interest != 0) 114 record(date, interest, "interest"); 115 accumulation = 0; 116 } 117 void SavingsAccount::show()const { 118 cout << id << "\tBalance:" << balance; 119 } 120 121 122 #include"account.h" 123 #include<iostream> 124 using namespace std; 125 int main() 126 { 127 Date date(2008, 11, 1); 128 SavingsAccount accounts[] = { 129 SavingsAccount(date,"03755217",0.015), 130 SavingsAccount(date,"02342342",0.015) 131 }; 132 const int n = sizeof(accounts) / sizeof(SavingsAccount); 133 accounts[0].deposit(Date(2008, 11, 5), 5000, "salary"); 134 accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323"); 135 136 accounts[0].deposit(Date(2008, 12, 5), 5000, "salary"); 137 accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop"); 138 139 cout << endl; 140 for (int i = 0; i < n; i++) 141 { 142 accounts[i].settle(Date(2009, 1, 1)); 143 accounts[i].show(); 144 cout << endl; 145 } 146 cout << "Total:" << SavingsAccount::getTotal() << endl; 147 return 0; 148 }task6
标签:std,const,cout,int,void,实验,string From: https://www.cnblogs.com/syxlyw/p/18525835