任务一
#pragma once #include <iostream> #include <string> using std::string; using std::cout; // °´Å¥Àà class Button { public: Button(const string &text); string get_label() const; void click(); private: string label; }; Button::Button(const string &text): label{text} { } inline string Button::get_label() const { return label; } void Button::click() { cout << "Button '" << label << "' clicked\n"; } #include "window.hpp" #include <iostream> using std::cout; using std::cin; void test() { Window w1("new window"); w1.add_button("maximize"); w1.display(); w1.close(); } int main() { cout << "用组合类模拟简单GUI:\n"; test(); } #pragma once #include "button.hpp" #include <vector> #include <iostream> using std::vector; using std::cout; using std::endl; // ´°¿ÚÀà class Window{ public: Window(const string &win_title); void display() const; void close(); void add_button(const string &label); private: string title; vector<Button> buttons; }; Window::Window(const string &win_title): title{win_title} { buttons.push_back(Button("close")); } inline void Window::display() const { string s(40, '*'); cout << s << endl; cout << "window title: " << title << endl; cout << "It has " << buttons.size() << " buttons: " << endl; for(const auto &i: buttons) cout << i.get_label() << " button" << endl; cout << s << endl; } void Window::close() { cout << "close window '" << title << "'" << endl; buttons.at(0).click(); } void Window::add_button(const string &label) { buttons.push_back(Button(label)); }
问题一:运用标准库中的vector和string 两个类;组合关系:window类中用Button类,button集合是window类的属性;
问题二:不适合,const修饰的对象是不可以更改的,而inline可以减少函数调用的开销;在小型函数中inline可以提高效率;
问题三:增强输出的可读性,作用是输出40个“*”;
任务二
#include <iostream> #include <vector> using namespace std; void output1(const vector<int> &v) { for(auto &i: v) cout << i << ", "; cout << "\b\b \n"; } void output2(const vector<vector<int>> v) { for(auto &i: v) { for(auto &j: i) cout << j << ", "; cout << "\b\b \n"; } } void test1() { vector<int> v1(5, 42); const vector<int> v2(v1); v1.at(0) = -999; cout << "v1: "; output1(v1); cout << "v2: "; output1(v2); cout << "v1.at(0) = " << v1.at(0) << endl; cout << "v2.at(0) = " << v2.at(0) << endl; } void test2() { vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}}; const vector<vector<int>> v2(v1); v1.at(0).push_back(-999); cout << "v1: \n"; output2(v1); cout << "v2: \n"; output2(v2); vector<int> t1 = v1.at(0); cout << t1.at(t1.size()-1) << endl; const vector<int> t2 = v2.at(0); cout << t2.at(t2.size()-1) << endl; } int main() { cout << "²âتش1:\n"; test1(); cout << "\n²âتش2:\n"; test2(); }
问题一:初始化v1,并且v2复制v1,将v1的42改成-999;
问题二:初始化v1 ;v2为常量复制v1 ;将v1第一行中的最后一个改成-999;
问题三:将v1,v2的第一行元素分别复制给f1,f2,输出这一行最后一个元素;
问题四:进行深复制;
任务三:
#pragma once #include <iostream> #include <cassert> using std::cout; using std::endl; // 动态int数组对象类 class vectorInt{ public: vectorInt(int n); vectorInt(int n, int value); vectorInt(const vectorInt &vi); ~vectorInt(); int& at(int index); const int& at(int index) const; vectorInt& assign(const vectorInt &v); int get_size() const; private: int size; int *ptr; // ptr指向包含size个int的数组 }; vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} { } vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} { for(auto i = 0; i < size; ++i) ptr[i] = value; } vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} { for(auto i = 0; i < size; ++i) ptr[i] = vi.ptr[i]; } vectorInt::~vectorInt() { delete [] ptr; } const int& vectorInt::at(int index) const { assert(index >= 0 && index < size); return ptr[index]; } int& vectorInt::at(int index) { assert(index >= 0 && index < size); return ptr[index]; } vectorInt& vectorInt::assign(const vectorInt &v) { delete[] ptr; // 释放对象中ptr原来指向的资源 size = v.size; ptr = new int[size]; for(int i = 0; i < size; ++i) ptr[i] = v.ptr[i]; return *this; } int vectorInt::get_size() const { return size; }
#include "vectorInt.hpp"
#include <iostream>
using std::cin;
using std::cout;
void output(const vectorInt &vi) {
for(auto i = 0; i < vi.get_size(); ++i)
cout << vi.at(i) << ", ";
cout << "\b\b \n";
}
void test1() {
int n;
cout << "Enter n: ";
cin >> n;
vectorInt x1(n);
for(auto i = 0; i < n; ++i)
x1.at(i) = i*i;
cout << "x1: "; output(x1);
vectorInt x2(n, 42);
vectorInt x3(x2);
x2.at(0) = -999;
cout << "x2: "; output(x2);
cout << "x3: "; output(x3);
}
void test2() {
const vectorInt x(5, 42);
vectorInt y(10, 0);
cout << "y: "; output(y);
y.assign(x);
cout << "y: "; output(y);
cout << "x.at(0) = " << x.at(0) << endl;
cout << "y.at(0) = " << y.at(0) << endl;
}
int main() {
cout << "²âÊÔ1: \n";
test1();
cout << "\n²âÊÔ2: \n";
test2();
}
问题一:深
问题二:不能;报错:左操作数必须为左值;删除const后,可以运行;
问题三:可以改成vectorInt,但是需要额外空间;
任务四
#pragma once
#include <iostream>
#include <cassert>
using std::cout;
using std::endl;
// 类Matrix的声明
class Matrix {
public:
Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value
Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value
Matrix(const Matrix &x); // 复制构造函数, 使用已有的矩阵X构造
~Matrix();
void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值
void clear(); // 把矩阵对象的值置0
const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用
double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用
int get_lines() const; // 返回矩阵对象行数
int get_cols() const; // 返回矩阵对象列数
void display() const; // 按行显示矩阵对象元素值
private:
int lines; // 矩阵对象内元素行数
int cols; // 矩阵对象内元素列数
double *ptr;
};
// 类Matrix的实现:待补足
// xMatrix::Matrix(const Matrix &x): lines{x.get_lines()}, cols{x.get_cols()}, ptr{new double[lines*cols]}{ for(int i = 0;i < lines;i++) for(int j = 0;j < cols;j++){ *(ptr+cols*i+j) = x.ptr[cols*i + j]; } }
} Matrix::Matrix(int n, int m): lines{n}, cols{m}, ptr{new double[lines*cols]} {} Matrix::Matrix(int n): lines{n}, cols{n}, ptr{new double[lines*cols]} {} Matrix::~Matrix(){ delete [] ptr; } void Matrix::set(const double *pvalue){ for(int i = 0;i < lines;i++){ for(int j = 0;j < cols;j++){ *(ptr+cols*i+j) = *(pvalue+cols*i+j); } } } void Matrix::clear(){ for(int i = 0;i < lines;i++){ for(int j = 0;j < cols;j++){ *(ptr+cols*i+j) = 0; } } } const double& Matrix::at(int i, int j) const{ assert(i >= 0 && i < lines && j >= 0 && j < cols); return *(ptr+cols*i+j); } double& Matrix::at(int i, int j){ assert(i >= 0 && i < lines && j >= 0 && j < cols); return *(ptr+cols*i+j); } int Matrix::get_lines() const{ return lines; } int Matrix::get_cols() const{ return cols; } void Matrix::display() const{ for(int i = 0;i < lines;i++){ for(int j = 0;j < cols;j++){ cout << *(ptr+cols*i+j) << " "; } cout << endl; } }
#include "matrix.hpp"
#include <iostream>
#include <cassert>
using std::cin;
using std::cout;
using std::endl;
const int N = 1000;
// 输出矩阵对象索引为index所在行的所有元素
void output(const Matrix &m, int index) {
assert(index >= 0 && index < m.get_lines());
for(auto j = 0; j < m.get_cols(); ++j)
cout << m.at(index, j) << ", ";
cout << "\b\b \n";
}
void test1() {
double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
int n, m;
cout << "Enter n and m: ";
cin >> n >> m;
Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m
m1.set(x); // 用一维数组x的值按行为矩阵m1赋值
Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n
m2.set(x); // 用一维数组x的值按行为矩阵m1赋值
Matrix m3(2); // 创建一个2×2矩阵对象
m3.set(x); // 用一维数组x的值按行为矩阵m4赋值
cout << "矩阵对象m1: \n"; m1.display(); cout << endl;
cout << "矩阵对象m2: \n"; m2.display(); cout << endl;
cout << "矩阵对象m3: \n"; m3.display(); cout << endl;
}
void test2() {
Matrix m1(2, 3);
m1.clear();
const Matrix m2(m1);
m1.at(0, 0) = -999;
cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl;
cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl;
cout << "矩阵对象m1第0行: "; output(m1, 0);
cout << "矩阵对象m2第0行: "; output(m2, 0);
}
int main() {
cout << "测试1: \n";
test1();
cout << "测试2: \n";
test2();
}
任务五
#pragma once #include <iostream> #include <string> class User { public: User(const std::string& username, const std::string& password = "", const std::string& email = ""); void set_email(); void change_password(); void display() const; private: std::string username_; std::string password_; std::string email_; }; // 构造函数实现 User::User(const std::string& username, const std::string& password, const std::string& email) : username_(username), password_(password), email_(email) {} void User::set_email() { std::string input_email; bool has_at_symbol = false; do { std::cout << "Enter email for " << username_ << ": "; std::cin >> input_email; for (char c : input_email) { if (c == '@') { has_at_symbol = true; break; } } if (!has_at_symbol) { std::cout << "无效的邮箱" << std::endl; } } while (!has_at_symbol); email_ = input_email; } void User::change_password() { std::string old_password; int attempts = 0; while (attempts < 3) { std::cout << "输入旧密码: " << username_ << ": "; std::cin >> old_password; if (old_password == password_) { std::string new_password; std::cout << "输入新密码: " << username_ << ": "; std::cin >> new_password; password_ = new_password; break; } else { attempts++; std::cout << "旧密码错误 " << 3 - attempts << std::endl; } } if (attempts == 3) { std::cout << "错误多次,稍后再试" << std::endl; } } void User::display() const { std::string password_display(password_.length(), '*'); std::cout << "Username: " << username_ << ", Password: " << password_display << ", Email: " << email_; }
#include "user.hpp"
#include <iostream>
#include <vector>
#include <string>
using std::cin;
using std::cout;
using std::endl;
using std::vector;
using std::string;
void test() {
vector<User> user_lst;
User u1("Alice", "2024113", "[email protected]");
user_lst.push_back(u1);
cout << endl;
User u2("Bob");
u2.set_email();
u2.change_password();
user_lst.push_back(u2);
cout << endl;
User u3("Hellen");
u3.set_email();
u3.change_password();
user_lst.push_back(u3);
cout << endl;
cout << "There are " << user_lst.size() << " users. they are: " << endl;
for(auto &i: user_lst) {
i.display();
cout << endl;
}
}
int main() {
test();
}
任务六:
//account.h #ifndef __ACCOUNT_H__ #define __ACCOUNT_H__ #include "date.h" #include <string> class SavingsAccount {//储蓄账户类 private: std::string id;//账号 double balance;//余额 double rate;//存款的年利率 Date lastDate;//上次变更余额的时期 double accumulation;//按日累加以和 static double total;//所有账户的总金额 //记录一笔账,date为日期,amount为金额,desc为说明 void record(const Date & date, double amount, const std::string & desc); //报告错误信息 void error(const std::string & msg) const; //获得指定日期为止的存款金额按日累增值 double accumulate(const Date & date) const { return accumulation + balance * date.distance(lastDate); } public: //构造函数 SavingsAccount(const Date & date, const std::string & id, double rate);//获得账号 const std::string & getId() const { return id; } //获得余额 double getBalance() const { return balance; } //获得年利率 double getRate() const { return rate; } static double getTotal() { return total; }//存入现金 void deposit(const Date & date, double amount, const std::string & desc);//取出现金 void withdraw(const Date & date, double amount, const std::string & desc);//结算利息,每年1月1日调用一次该函数 void settle(const Date & date); //显示账户信息 void show() const; }; #endif //__ACCOUNT_H__#pragma once
//date.h #ifndef __DATE_H__ #define __DATE_H__ class Date {//日期类 private: int year; //年 int month;//月 int day;//日 int totalDays;//该日期是从公元元年1月1日开始的第几天 public: Date(int year, int month, int day);//用年、月、日构造日期 int getYear() const { return year; } int getMonth() const { return month; } int getDay() const { return day; } int getMaxDay() const;//获得当月有多少天 bool isLeapYear() const {//判断当年是否为闰年 return year % 4 == 0 && year % 100 != 0 || year % 400 == 0; } void show() const;//输出当前日期 int distance(const Date & date) const { return totalDays - date.totalDays; } }; #endif //__DATE_H__
//account.cpp #include "account.h" #include <cmath> #include <iostream> using namespace std; double SavingsAccount::total = 0; //SavingsAccount类相关成员函数的实现 SavingsAccount::SavingsAccount(const Date &date,const string &id,double rate):id(id),balance(0),rate(rate),lastDate(date),accumulation(0){ date.show(); cout << "\t#" << id << " created" << endl; } void SavingsAccount::record(const Date & date, double amount, const string & desc) { accumulation = accumulate(date); lastDate = date; amount = floor(amount * 100 + 0.5) / 100; //保留小数点后两位 balance += amount; total += amount; date.show(); cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl; } void SavingsAccount::error(const string & msg) const { cout << "Error(#" << id << "): " << msg << endl; } void SavingsAccount::deposit(const Date & date, double amount, const string & desc) { record(date, amount, desc); } void SavingsAccount::withdraw(const Date & date, double amount, const string & desc) { if (amount > getBalance()) error("not enough money"); else record(date, -amount, desc); } void SavingsAccount::settle(const Date & date) { double interest = accumulate(date) * rate / date.distance(Date(date.getYear() - 1, 1, 1)); if (interest != 0) record(date, interest, "interest"); accumulation = 0; } void SavingsAccount::show() const { cout << "ID: " << id << "\tBalance: " << balance; }
//date.cpp #include "date.h" #include <iostream> #include <cstdlib> using namespace std; namespace { //namespace使下面的定义只在当前文件中有效 const int DAYS_BEFORE_MONTH[] = { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 356 }; } Date::Date(int year, int month, int day) :year(year), month(month), day(day) { if (day <= 0 || day > getMaxDay()) { cout << "Invalid date: "; show(); cout << endl; exit(1); } int years = year - 1; totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFORE_MONTH[month - 1] + day; if (isLeapYear() && month > 2) totalDays++; } int Date::getMaxDay() const { if (isLeapYear() && month == 2) return 29; else return DAYS_BEFORE_MONTH[month] - DAYS_BEFORE_MONTH[month - 1]; } void Date::show() const { cout << getYear() << "-" << getMonth() << "-" << getDay(); }
//6.25.cpp #include "account.h" #include <iostream> using namespace std; int main() { Date date(2008, 11, 1); //起始日期 //建立几个账户 SavingsAccount accounts[] = { SavingsAccount(date, "03755217", 0.015), SavingsAccount(date, "02342342", 0.015) }; //几笔账目 accounts[0].deposit(Date(2008, 11, 5), 5000, "salary"); accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323"); accounts[0].deposit(Date(2008, 12, 5), 5500, "salary"); accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop"); //结算所有账户并输出各个账户信息 cout << endl; for (int i = 0; i < sizeof(accounts) / sizeof(SavingsAccount); i++) { accounts[i].settle(Date(2009, 1, 1)); accounts[i].show(); cout << endl; } cout << "Total: " << SavingsAccount::getTotal() << endl; return 0; }标签:std,const,cout,int,void,实验,string From: https://www.cnblogs.com/jhgvj/p/18537897