c语言中多个变量连续赋值

001、

[root@PC1 test]# ls
test.c
[root@PC1 test]# cat test.c          ##测试c程序
#include <stdio.h>

int main(void)
{
        int i,j;

        i = j = 5;                   // 连续赋值

        printf("i = %d\n", i);
        printf("j = %d\n", j);

        return 0;
}
[root@PC1 test]# gcc test.c -o kkk
[root@PC1 test]# ls
kkk  test.c
[root@PC1 test]# ./kkk
i = 5
j = 5

002、

[root@PC1 test]# ls
test.c
[root@PC1 test]# cat test.c
#include <stdio.h>

int main(void)
{
        int i = j = 5;                 // 无法再初始化过程中连续赋值

        printf("i = %d\n", i);
        printf("j = %d\n", j);

        return 0;
}
[root@PC1 test]# gcc test.c -o kkk
test.c: In function ‘main’:
test.c:5:10: error: ‘j’ undeclared (first use in this function)
  int i = j = 5;
          ^
test.c:5:10: note: each undeclared identifier is reported only once for each function it appears in

003、

[root@PC1 test]# ls
test.c
[root@PC1 test]# cat test.c              ## 测试c程序
#include <stdio.h>

int main(void)
{
        int array1[3] = {1,3,4};         // 数组可以连续赋值初始化

        return 0;
}
[root@PC1 test]# gcc test.c -o kkk       ## 编译
[root@PC1 test]# ls
kkk  test.c

004、

[root@PC1 test]# ls
test.c
[root@PC1 test]# cat test.c                        ## 测试c程序
#include <stdio.h>

int main(void)
{
        int array[3];

        array[3] = {1,3,8};                        //数组中不可以这样连续赋值

        return 0;
}
[root@PC1 test]# gcc test.c -o kkk                  ## 无法编译
test.c: In function ‘main’:
test.c:7:13: error: expected expression before ‘{’ token
  array[3] = {1,3,8};
             ^

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