实验三

实验任务一：

#pragma once

#include <iostream>
#include <string>

using std::string;
using std::cout;

// 按钮类
class Button {
public:
    Button(const string &text);
    string get_label() const;
    void click();

private:
    string label;
};

Button::Button(const string &text): label{text} {
}

inline string Button::get_label() const {
    return label;
}

void Button::click() {
    cout << "Button '" << label << "' clicked\n";
}

#pragma once
#include "button.hpp"
#include <vector>
#include <iostream>

using std::vector;
using std::cout;
using std::endl;

// 窗口类
class Window{
public:
    Window(const string &win_title);
    void display() const;
    void close();
    void add_button(const string &label);

private:
    string title;
    vector<Button> buttons;
};

Window::Window(const string &win_title): title{win_title} {
    buttons.push_back(Button("close"));
}

inline void Window::display() const {
    string s(40, '*');

    cout << s << endl;
    cout << "window title: " << title << endl;
    cout << "It has " << buttons.size() << " buttons: " << endl;
    for(const auto &i: buttons)
        cout << i.get_label() << " button" << endl;
    cout << s << endl;
}

void Window::close() {
    cout << "close window '" << title << "'" << endl;
    buttons.at(0).click();
}

void Window::add_button(const string &label) {
    buttons.push_back(Button(label));
}

#include "window.hpp"
#include <iostream>

using std::cout;
using std::cin;

void test() {
    Window w1("new window");
    w1.add_button("maximize");
    w1.display();
    w1.close();
}

int main() {
    cout << "用组合类模拟简单GUI:\n";
    test();
}

问题一：两个类；string和vector   ；button string  和    window string vector

问题二：  不合适。因为加const是为了修改内部的数据，加inline是表示成员函数要多次调用，没有必要

问题三：做分隔符

实验任务二：

#include <iostream>
#include <vector>

using namespace std;

void output1(const vector<int> &v) {
    for(auto &i: v)
        cout << i << ", ";
    cout << "\b\b \n";
}

void output2(const vector<vector<int>> v) {
    for(auto &i: v) {
        for(auto &j: i)
            cout << j << ", ";
        cout << "\b\b \n";
    }
}

void test1() {
    vector<int> v1(5, 42);
    const vector<int> v2(v1);

    v1.at(0) = -999;
    cout << "v1: ";  output1(v1);
    cout << "v2: ";  output1(v2);
    cout << "v1.at(0) = " << v1.at(0) << endl;
    cout << "v2.at(0) = " << v2.at(0) << endl;
}

void test2() {
    vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}};
    const vector<vector<int>> v2(v1);

    v1.at(0).push_back(-999);
    cout << "v1: \n";  output2(v1);
    cout << "v2: \n";  output2(v2);

    vector<int> t1 = v1.at(0);
    cout << t1.at(t1.size()-1) << endl;
    
    const vector<int> t2 = v2.at(0);
    cout << t2.at(t2.size()-1) << endl;
}

int main() {
    cout << "测试1:\n";
    test1();

    cout << "\n测试2:\n";
    test2();
}

问题一：创建一个容量为5且全是42的容器；对象赋值；将v1的第一个数改成-999

问题二：创建一个含有容器的vector容器，且大小为2，里面包含数据；对v2进行赋值；在v1的第一个容器中的最后位置添加-999

问题三：取出v1的第一个容器赋值给t1；输出t1的最后元素的值；使用v2的第一个容器初始化t2；输出t2的最后元素的值

问题四：深复制；没错；

实验任务三：

#pragma once

#include <iostream>
#include <cassert>

using std::cout;
using std::endl;

// 动态int数组对象类
class vectorInt{
public:
    vectorInt(int n);
    vectorInt(int n, int value);
    vectorInt(const vectorInt &vi);
    ~vectorInt();

    int& at(int index);
    const int& at(int index) const;

    vectorInt& assign(const vectorInt &v);
    int get_size() const;

private:
    int size;
    int *ptr;       // ptr指向包含size个int的数组
};

vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} {
}

vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} {
    for(auto i = 0; i < size; ++i)
        ptr[i] = value;
}

vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} {
    for(auto i = 0; i < size; ++i)
        ptr[i] = vi.ptr[i];
}

vectorInt::~vectorInt() {
    delete [] ptr;
}

const int& vectorInt::at(int index) const {
    assert(index >= 0 && index < size);

    return ptr[index];
}

int& vectorInt::at(int index) {
    assert(index >= 0 && index < size);

    return ptr[index];
}

vectorInt& vectorInt::assign(const vectorInt &v) {  
    delete[] ptr;       // 释放对象中ptr原来指向的资源

    size = v.size;
    ptr = new int[size];

    for(int i = 0; i < size; ++i)
        ptr[i] = v.ptr[i];

    return *this;
}

int vectorInt::get_size() const {
    return size;
}

#include "vectorInt.hpp"
#include <iostream>

using std::cin;
using std::cout;

void output(const vectorInt &vi) {
    for(auto i = 0; i < vi.get_size(); ++i)
        cout << vi.at(i) << ", ";
    cout << "\b\b \n";
}


void test1() {
    int n;
    cout << "Enter n: ";
    cin >> n;

    vectorInt x1(n);
    for(auto i = 0; i < n; ++i)
        x1.at(i) = i*i;
    cout << "x1: ";  output(x1);

    vectorInt x2(n, 42);
    vectorInt x3(x2);
    x2.at(0) = -999;
    cout << "x2: ";  output(x2);
    cout << "x3: ";  output(x3);
}

void test2() {
    const vectorInt  x(5, 42);
    vectorInt y(10, 0);

    cout << "y: ";  output(y);
    y.assign(x);
    cout << "y: ";  output(y);
    
    cout << "x.at(0) = " << x.at(0) << endl;
    cout << "y.at(0) = " << y.at(0) << endl;
}

int main() {
    cout << "测试1: \n";
    test1();

    cout << "\n测试2: \n";
    test2();
}

问题一：深复制；

问题二：不能，&被删，返回的就是int数值，不能被赋值；存在，可能被修改

问题三：可以，对象和引用都可实现相同的功能

实验任务四：

#pragma once

#include <iostream>
#include <cassert>

using std::cout;
using std::endl;

// 类Matrix的声明
class Matrix {
public:
    Matrix(int n, int m);           // 构造函数，构造一个n*m的矩阵, 初始值为value
    Matrix(int n);                  // 构造函数，构造一个n*n的矩阵, 初始值为value
    Matrix(const Matrix& x);        // 复制构造函数， 使用已有的矩阵X构造
    ~Matrix();

    void set(const double* pvalue);         // 用pvalue指向的连续内存块数据按行为矩阵赋值
    void clear();                           // 把矩阵对象的值置0

    const double& at(int i, int j) const;   // 返回矩阵对象索引(i,j)的元素const引用
    double& at(int i, int j);               // 返回矩阵对象索引(i,j)的元素引用

    int get_lines() const;                  // 返回矩阵对象行数
    int get_cols() const;                   // 返回矩阵对象列数

    void display() const;                    // 按行显示矩阵对象元素值

private:
    int lines;      // 矩阵对象内元素行数
    int cols;       // 矩阵对象内元素列数
    double* ptr;
};

Matrix::Matrix(int n, int m) :lines(n), cols(m), ptr(new double[lines * cols]) {}    // 构造函数，构造一个n*m的矩阵, 初始值为value

Matrix::Matrix(int n) :lines(n), cols(n), ptr(new double[lines * cols]) {}// 构造函数，构造一个n*n的矩阵, 初始值为value

Matrix::Matrix(const Matrix& x) :lines(x.lines), cols(x.cols) {
    double* a = new double[cols * lines];
    for (int i = 0; i < cols * lines; ++i)
        *(a + i) = *(x.ptr + i);
    ptr = a;

}// 复制构造函数， 使用已有的矩阵X构造


void Matrix::set(const double* pvalue) {

    
    for (int n = 0; n < cols * lines; ++n)
        *(ptr + n) = *(pvalue + n);

}      // 用pvalue指向的连续内存块数据按行为矩阵赋值
void Matrix::clear() {
    
    for (int n = 0; n < cols * lines; ++n)
        *(ptr + n) = 0;
}                           // 把矩阵对象的值置0

const double& Matrix::at(int i, int j) const {
    return *(ptr + (i * cols + j));
}   // 返回矩阵对象索引(i,j)的元素const引用
double& Matrix::at(int i, int j) {
    return *(ptr + (i * cols + j));
}               // 返回矩阵对象索引(i,j)的元素引用

int Matrix::get_lines() const {
    return lines;
}                // 返回矩阵对象行数
int Matrix::get_cols() const {

    return cols;
}                   // 返回矩阵对象列数

void Matrix::display() const {
    for (int i = 0; i < lines; ++i) {
        for (int j = 0; j < cols; ++j)
        {
            cout << *(ptr + i * cols + j)<<",";
        }
        cout << endl;
    }

}
Matrix::~Matrix() {
    delete ptr;
}

#include "matrix.hpp"
#include <iostream>
#include <cassert>

using std::cin;
using std::cout;
using std::endl;


const int N = 1000;

// 输出矩阵对象索引为index所在行的所有元素
void output(const Matrix &m, int index) {
    assert(index >= 0 && index < m.get_lines());

    for(auto j = 0; j < m.get_cols(); ++j)
        cout << m.at(index, j) << ", ";
    cout << "\b\b \n";
}


void test1() {
    double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9};

    int n, m;
    cout << "Enter n and m: ";
    cin >> n >> m;

    Matrix m1(n, m);    // 创建矩阵对象m1, 大小n×m
    m1.set(x);          // 用一维数组x的值按行为矩阵m1赋值

    Matrix m2(m, n);    // 创建矩阵对象m1, 大小m×n
    m2.set(x);          // 用一维数组x的值按行为矩阵m1赋值

    Matrix m3(2);       // 创建一个2×2矩阵对象
    m3.set(x);          // 用一维数组x的值按行为矩阵m4赋值

    cout << "矩阵对象m1: \n";   m1.display();  cout << endl;
    cout << "矩阵对象m2: \n";   m2.display();  cout << endl;
    cout << "矩阵对象m3: \n";   m3.display();  cout << endl;
}

void test2() {
    Matrix m1(2, 3);
    m1.clear();
    
    const Matrix m2(m1);
    m1.at(0, 0) = -999;

    cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl;
    cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl;
    cout << "矩阵对象m1第0行: "; output(m1, 0);
    cout << "矩阵对象m2第0行: "; output(m2, 0);
}

int main() {
    cout << "测试1: \n";
    test1();

    cout << "测试2: \n";
    test2();
}

 实验任务5：

#include<iostream>
#pragma once
#include<string>
#include<iomanip>
using namespace std;
class User {
private:
    string name;
    string email;
    string password;
public:
    User(string name, string password = "123456", string email = "");
    User();
    void set_email();
    void change_password();
    void display();
};

User::User(string name, string password, string email) :name{ name }, password{ password }, email{ email } {}

User::User() {}
void User::set_email() {
    cout << "Enter email address:";
    string newn;
    cin >> newn;
    while (newn.find('@') == string::npos) {
        cout << "illegal email.Please re-enter email:";
        cin >> newn;
    }
    email = newn;
    cout << "email is set successfully..." << endl;
}
void User::change_password() {
    cout << "Enter old password:";
    string newn;

    int n = 2;
    cin >> newn;
    while (n--) {
        
        if (newn == password)
        {
            
            cout << "Enter new password:";
            cin >> newn;
            password = newn;
            cout << "new password is set successfully..." << endl << endl;
            break;
        }
        
        cout << "password input error.Please re-enter again:";
        cin >> newn;
    }
    if (n == -1) {
        cout << "password input error. Please try after a while." << endl;
        
    }
}
void User::display() {
    cout << endl;
    cout << left<<setw(10) << "name:" << name << endl;
    string s(password.length(), '*');
    cout <<left<< setw(10) << "pass:" << s << endl;
    cout <<left<< setw(10) << "email:" << email << endl;
}

#include "User.hpp"
#include <iostream>
#include <vector>
#include <string>

using std::cin;
using std::cout;
using std::endl;
using std::vector;
using std::string;

void test() {
    vector<User> user_lst;

    User u1("Alice", "2024113", "[email protected]");
    user_lst.push_back(u1);
    cout << endl;

    User u2("Bob");
    u2.set_email();
    u2.change_password();
    user_lst.push_back(u2);
    cout << endl;

    User u3("Hellen");
    u3.set_email();
    u3.change_password();
    user_lst.push_back(u3);
    cout << endl;

    cout << "There are " << user_lst.size() << " users. they are: " << endl;
    for (auto& i : user_lst) {
        i.display();
        cout << endl;
    }
}

int main() {
    test();
}

 实验任务六：

processing
#pragma once

#include<iostream>
#include<cstdlib>

using namespace std;
class Date {
    private:
        int year;
        int month;
        int day;
        int totalDays;
    public:
        Date(int year, int month, int day);
        int getYear()const {
            return year;
        }
        int getMonth()const {
            return month;
        }
        int getDay()const {
            return day;
        }
        int getMaxDay()const;
        bool isLeapYear()const {
            return year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
        }
        void show() const;
        int distance(const Date& date)const {
            return totalDays - date.totalDays;
        }
};
namespace {
    const int DAYS_BEFIRE_MONTH[] = { 0,31,59,90,120,151,181,212,243,273,304 ,334,365 };
}
Date::Date(int year, int month, int day) :year(year), month(month), day(day) {
    if (day <= 0 || day > getMaxDay()) {
        cout << "Invalid date: ";
        show();
        cout << endl;
        exit(1);
    }
    int years = year - 1;
    totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFIRE_MONTH[month - 1] + day;
    if (isLeapYear() && month > 2) totalDays++;
}
int Date::getMaxDay()const {
    if (isLeapYear() &&month == 2)
        return 29;
    else return DAYS_BEFIRE_MONTH[month] - DAYS_BEFIRE_MONTH[month - 1];
}
void Date::show()const {
    cout << getYear() << "-" << getMonth() << "-" << getDay();
}

cpp
#pragma once

#include"date.hpp"
#include<string>
#include<cmath>
#include<iostream>

using namespace std;

class SavingsAccount {
    private:
        string id;
        double balance;
        double rate;
        Date lastDate;
        double accumulation;
        static double total;
        void record(const Date& date, double amount, const string& desc);
        void error(const string& msg) const;
        double accumulate(const Date& date)const {
            return accumulation + balance * date.distance(lastDate);
        }
    public:
        SavingsAccount(const Date& date, const string& id, double rate);
        const string& getId()const {
            return id;
        }
        double getBalance()const {
            return balance;
        }
        double getRate()const {
            return rate;
        }
        static double getTotal() {
            return total;
        }
        void deposit(const Date& date, double amount, const string& desc);
        void withdraw(const Date& date, double amount, const string& desc);
        void settle(const Date& date);
        void show() const;
};
double SavingsAccount::total = 0;
SavingsAccount::SavingsAccount(const Date& date, const string& id, double rate) :
    id(id), balance(0), rate(rate), lastDate(date), accumulation(0) {
    date.show();
    cout << "\t#" << id << "created" << endl;
}
void SavingsAccount::record(const Date& date, double amount, const string& desc) {
    accumulation = accumulate(date);
    lastDate = date;
    amount = floor(amount * 100 + 0.5) / 100;
    balance += amount;
    total += amount;
    date.show();
    cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl;
}
void SavingsAccount::error(const string& msg) const {
    cout << "Error(#" << id << "):" << msg << endl;
}
void SavingsAccount::deposit(const Date& date, double amount, const string& desc) {
    record(date, amount, desc);
}
void SavingsAccount::withdraw(const Date& date, double amount, const string& desc) {
    if (amount > getBalance())
        error("not enough money");
    else
        record(date, -amount, desc);
}
void SavingsAccount::settle(const Date& date) {
    double interest = accumulate(date) * rate / date.distance(Date(date.getYear() - 1, 1, 1));
    if (interest != 0) record( date,interest,"interest" );
    accumulation = 0;
}
void SavingsAccount::show()const {
    cout << id << "\tBalance: " << balance;
}

cpp
#include"account.hpp"
#include<iostream>
using namespace std;
int main() {
    Date date { 2008,11,1 };
    SavingsAccount accounts[] = {
        SavingsAccount(date,"03755217",0.015),
        SavingsAccount(date,"02342342",0.015)
    };
    const int n = sizeof(accounts) / sizeof(SavingsAccount);
    accounts[0].deposit(Date(2008, 11, 5), 5000, "salary");
    accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323");
    accounts[0].deposit(Date(2008, 12, 5), 5500, "salary");
    accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop");
    cout << endl;
    for (int i = 0; i < n; i++) {
        accounts[i].settle(Date(2009, 1, 1));
        accounts[i].show();
        cout << endl;
    }
    cout << "Total: " << SavingsAccount::getTotal() << endl;
    return 0;
}