1. 实验任务1 button.hpp
1 #pragma once 2 #include <iostream> 3 #include <string> 4 using std::string; 5 using std::cout; 6 // 按钮类 7 class Button { 8 public: 9 Button(const string& text); 10 string get_label() const; 11 void click(); 12 private: 13 string label; 14 }; 15 Button::Button(const string& text) : label{ text } { 16 } 17 inline string Button::get_label() const { 18 return label; 19 } 20 void Button::click() { 21 cout << "Button '" << label << "' clicked\n"; 22 }View Code window.hpp
1 #pragma once 2 #include "button.hpp" 3 #include <vector> 4 #include <iostream> 5 using std::vector; 6 using std::cout; 7 using std::endl; 8 // 窗口类 9 class Window { 10 public: 11 Window(const string& win_title); 12 void display() const; 13 void close(); 14 void add_button(const string& label); 15 private: 16 string title; 17 vector<Button> buttons; 18 }; 19 Window::Window(const string& win_title) : title{ win_title } { 20 buttons.push_back(Button("close")); 21 } 22 inline void Window::display() const { 23 string s(40, '*'); 24 cout << s << endl; 25 cout << "window title: " << title << endl; 26 cout << "It has " << buttons.size() << " buttons: " << endl; 27 for (const auto& i : buttons) 28 cout << i.get_label() << " button" << endl; 29 cout << s << endl; 30 } 31 void Window::close() { 32 cout << "close window '" << title << "'" << endl; 33 buttons.at(0).click(); 34 } 35 void Window::add_button(const string& label) { 36 buttons.push_back(Button(label)); 37 }View Code task1.cpp
1 #include "window.hpp" 2 #include <iostream> 3 using std::cout; 4 using std::cin; 5 void test() { 6 Window w1("new window"); 7 w1.add_button("maximize"); 8 w1.display(); 9 w1.close(); 10 } 11 int main() { 12 cout << "用组合类模拟简单GUI:\n"; 13 test(); 14 }View Code 问题1:这个模拟简单GUI的示例代码中,自定义了几个类?使用到了标准库的哪几个类?,哪些 类和类之间存在组合关系? 自定义了2个类,用了vector和string类,vector和Button,Window和string,Button和string存在组合关系; 问题2:在自定义类Button和Window中,有些成员函数定义时加了const, 有些设置成了inline。如 果你是类的设计者,目前那些没有加const或没有设置成inline的,适合添加const,适合设置成 inline吗?陈述你的答案和理由。 不适合,剩下的需要修改元素或者执行操作并不简单; 问题3:类Window的定义中,有这样一行代码,其功能是? 初始化一个字符串s,s是40个*; 2. 实验任务2 task2.cpp
1 #include<iostream> 2 #include<vector> 3 4 using namespace std; 5 void output1(const vector<int>& v) { 6 for (auto& i : v) 7 cout << i << ","; 8 cout << "\b\b \n"; 9 } 10 11 void output2(const vector<vector<int>>v) { 12 for (auto& i : v) { 13 for (auto& j : i) 14 cout << j << ", "; 15 cout << "\b\b \n"; 16 } 17 } 18 void test1() { 19 vector<int>v1(5, 42); 20 const vector<int>v2(v1); 21 22 v1.at(0) = -999; 23 cout << "v1: "; output1(v1); 24 cout << "v2: "; output1(v2); 25 cout << "v1.at(0) = " << v1.at(0) << endl; 26 cout << "v2.at(0) = " << v2.at(0) << endl; 27 } 28 void test2() { 29 vector<vector<int>>v1{ {1,2,3},{4,5,6,7} }; 30 const vector<vector<int>>v2(v1); 31 32 v1.at(0).push_back(-999); 33 cout << "v1: \n"; output2(v1); 34 cout << "v2: \n"; output2(v2); 35 36 vector<int>t1 = v1.at(0); 37 cout << t1.at(t1.size() - 1) << endl; 38 const vector<int> t2 = v2.at(0); 39 cout << t2.at(t2.size() - 1) << endl; 40 } 41 int main() { 42 cout << "测试1:\n"; 43 test1(); 44 cout << "\n测试2:\n"; 45 test2(); 46 }View Code
问题1:测试1模块中,这三行代码的功能分别是?
初始化v1为42,42,42,42,42;用v1初始化v2;将v1的第一个数改成-999; 问题2:测试2模块中,这三行代码的功能分别是? 初始化v1为有三个vector类成员的vector型数组;用v1初始化v2;在v1的第一个vector成员中加入-999作为该成员的第四个成员; 问题3:测试2模块中,这四行代码的功能分别是? 用v1的第一个成员初始化t1;输出t1的最后一个成员;用v2的第一个成员初始化t2;输出t2的最后一个成员; 问题4:根据执行结果,反向分析、推断: ① 标准库模板类vector内部封装的复制构造函数,其实现机制是深复制还是浅复制? 深复制 ② 模板类vector的接口at(), 是否至少需要提供一个const成员函数作为接口? 1个 3. 实验任务3 vectorInt.hpp1 #pragma once 2 #include <iostream> 3 #include <cassert> 4 using std::cout; 5 using std::endl; 6 // 动态int数组对象类 7 class vectorInt { 8 public: 9 vectorInt(int n); 10 vectorInt(int n, int value); 11 vectorInt(const vectorInt& vi); 12 ~vectorInt(); 13 14 int& at(int index); 15 const int& at(int index) const; 16 17 vectorInt& assign(const vectorInt& v); 18 int get_size()const; 19 20 private: 21 int size; 22 int* ptr; 23 }; 24 vectorInt::vectorInt(int n) : size{ n }, ptr{ new int[size] } { 25 } 26 vectorInt::vectorInt(int n, int value) : size{ n }, ptr{ new int[size] } { 27 for (auto i = 0; i < size; ++i) 28 ptr[i] = value; 29 } 30 vectorInt::vectorInt(const vectorInt& vi) : size{ vi.size }, ptr{ new int[size] } 31 { 32 for (auto i = 0; i < size; ++i) 33 ptr[i] = vi.ptr[i]; 34 } 35 vectorInt::~vectorInt() { 36 delete[] ptr; 37 } 38 const int& vectorInt::at(int index)const { 39 assert(index >= 0 && index < size); 40 41 return ptr[index]; 42 } 43 int& vectorInt::at(int index){ 44 assert(index >= 0 && index < size); 45 46 return ptr[index]; 47 } 48 vectorInt& vectorInt::assign(const vectorInt& v) { 49 delete[]ptr; 50 51 size = v.size; 52 ptr = new int[size]; 53 54 for (int i = 0; i < size; i++) 55 ptr[i] = v.ptr[i]; 56 57 return *this; 58 } 59 int vectorInt::get_size() const { 60 return size; 61 }View Code task3.cpp
1 #include "vectorInt.hpp" 2 #include<iostream> 3 4 using namespace std; 5 6 void output(const vectorInt &vi) { 7 for (auto i = 0; i < vi.get_size(); ++i) 8 cout << vi.at(i) << ", "; 9 cout << "\b\b \n"; 10 } 11 void test1() { 12 int n; 13 cout << "Enter n:"; 14 cin >> n; 15 16 vectorInt x1(n); 17 for (auto i = 0; i < n; i++) 18 x1.at(i) = i * i; 19 cout << "x1:"; output(x1); 20 21 vectorInt x2(n, 42); 22 vectorInt x3(x2); 23 x2.at(0) = -999; 24 cout << "x2:"; output(x2); 25 cout << "x3:"; output(x3); 26 27 } 28 void test2() { 29 const vectorInt x(5, 42); 30 vectorInt y(10, 0); 31 32 cout << "y: "; output(y); 33 y.assign(x); 34 cout << "y: "; output(y); 35 cout << "x.at(0) = " << x.at(0) << endl; 36 cout << "y.at(0) = " << y.at(0) << endl; 37 } 38 int main() { 39 cout << "测试1: \n"; 40 test1(); 41 cout << "\n测试2: \n"; 42 test2(); 43 }View Code 问题1:vectorInt类中,复制构造函数(line14)的实现,是深复制还是浅复制? 深复制; 问题2:vectorInt类中,这两个at()接口,如果返回值类型改成int而非int&(相应地,实现部分也同步修改),测试代码还能正确运行吗? 不能 如果把line18返回值类型前面的const掉,针对这个测试代码,是否有潜在安全隐患?尝试分析说明。 存在安全隐患,const int&表明这是一个返回值为const类型的引用,int值不可修改,去掉const后,引用值可能被修改,所以存在安全隐患。 问题3:vectorInt类中,assign()接口,返回值类型可以改成vectorInt吗?你的结论,及原因分析 可以,但不好。vectorInt表示这是一个类型的引用,而不是一个对象的拷贝,加上&后,提高了效率 4. 实验任务4 matrix.hpp
1 #pragma once 2 #include <iostream> 3 #include <cassert> 4 using std::cout; 5 using std::endl; 6 // 类Matrix的声明 7 class Matrix { 8 public: 9 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value 10 Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value 11 Matrix(const Matrix& x); // 复制构造函数, 使用已有的矩阵X构造 12 ~Matrix(); 13 void set(const double* pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 14 void clear(); // 把矩阵对象的值置0 15 const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用 16 double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用 17 int get_lines() const; // 返回矩阵对象行数 18 int get_cols() const; // 返回矩阵对象列数 19 void display() const; // 按行显示矩阵对象元素值 20 private: 21 int lines; // 矩阵对象内元素行数 22 int cols; // 矩阵对象内元素列数 23 double* ptr; 24 }; 25 // 类Matrix的实现:待补足 26 Matrix::Matrix(int n, int m) :lines{ n }, cols{ m } { 27 ptr = new double[n * m](); 28 } 29 Matrix::Matrix(int n) :Matrix(n, n){} 30 Matrix::Matrix(const Matrix& x) :lines{ x.lines }, cols{ x.cols }{ 31 delete[] ptr; 32 33 ptr = new double[lines * cols]; 34 for (int i = 0; i < lines * cols; ++i) 35 ptr[i] = x.ptr[i]; 36 } 37 Matrix::~Matrix() { 38 delete[] ptr; 39 } 40 void Matrix::set(const double* pvalue) { 41 for (int i = 0; i < lines; ++i) { 42 for (int j = 0; j < cols; j++) { 43 ptr[i * cols + j] = pvalue[i * cols + j]; 44 } 45 } 46 } 47 void Matrix::clear() { 48 std::fill(ptr, ptr + lines * cols, 0); 49 } 50 const double& Matrix::at(int i, int j) const { 51 assert(i >= 0 && i < lines && j >= 0 && j < cols); 52 return ptr[i * cols + j]; 53 } 54 double& Matrix::at(int i, int j) { 55 assert(i >= 0 && i < lines && j >= 0 && j < cols); 56 return ptr[i * cols + j]; 57 } 58 int Matrix::get_lines() const { 59 return lines; 60 } 61 62 int Matrix::get_cols() const { 63 return cols; 64 } 65 void Matrix::display() const { 66 for (int i = 0; i < lines; ++i) { 67 for (int j = 0; j < cols; ++j) { 68 cout << ptr[i * cols + j] << " "; 69 } 70 cout << endl; 71 } 72 }View Code task4.cpp
1 #include "matrix.hpp" 2 #include <iostream> 3 #include <cassert> 4 using std::cin; 5 using std::cout; 6 using std::endl; 7 const int N = 1000; 8 // 输出矩阵对象索引为index所在行的所有元素 9 void output(const Matrix& m, int index) { 10 assert(index >= 0 && index < m.get_lines()); 11 for (auto j = 0; j < m.get_cols(); ++j) 12 cout << m.at(index, j) << ", "; 13 cout << "\b\b \n"; 14 } 15 void test1() { 16 double x[1000] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; 17 int n, m; 18 cout << "Enter n and m: "; 19 cin >> n >> m; 20 Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m 21 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 22 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n 23 m2.set(x); // 用一维数组x的值按行为矩阵m1赋值 24 Matrix m3(2); // 创建一个2×2矩阵对象 25 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值 26 cout << "矩阵对象m1: \n"; m1.display(); cout << endl; 27 cout << "矩阵对象m2: \n"; m2.display(); cout << endl; 28 cout << "矩阵对象m3: \n"; m3.display(); cout << endl; 29 } 30 void test2() { 31 Matrix m1(2, 3); 32 m1.clear(); 33 const Matrix m2(m1); 34 m1.at(0, 0) = -999; 35 cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl; 36 cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl; 37 cout << "矩阵对象m1第0行: "; output(m1, 0); 38 cout << "矩阵对象m2第0行: "; output(m2, 0); 39 } 40 int main() { 41 cout << "测试1: \n"; 42 test1(); 43 cout << "测试2: \n"; 44 test2(); 45 }View Code
5. 实验任务5 user.hpp
1 #pragma once 2 #include<iostream> 3 #include<string> 4 #include<vector> 5 6 using namespace std; 7 class User { 8 public: 9 User(const string &name,const string &password = "123456",const string &email=""):name(name),password(password),email(email){} 10 11 void set_email() { 12 int a = 0; 13 while (true) { 14 if (a == 0) 15 cout << "Enter email address:"; 16 else 17 cout << "Please re_enter email:"; 18 cin >> email; 19 a++; 20 if (email.find('@') != string::npos) { 21 cout << "email is set successfully..." << endl; 22 break; 23 } 24 else 25 cout << "illegal email."; 26 } 27 } 28 29 30 void change_password() { 31 int n = 0; 32 string old_password; 33 34 while (n < 3) { 35 if (n ==0) 36 cout << "Enter old password:"; 37 else 38 cout << "Please re_enter again:"; 39 cin >> old_password; 40 41 if (old_password == password) { 42 string new_password; 43 cout << "Enter new password:"; 44 cin >> new_password; 45 password = new_password; 46 cout << "new password is set successfully..." << endl; 47 break; 48 } 49 else { 50 cout << "password input error. "; 51 n++; 52 } 53 } 54 if(n==3) 55 cout << "Please try after a while." << endl; 56 } 57 58 void display()const { 59 cout << "name: " << name << endl; 60 cout << "pass: " << std::string(password.length(), '*') << endl; 61 cout << "email: " << email << endl; 62 } 63 64 65 private: 66 string name; 67 string password; 68 string email; 69 };View Code task5.cpp
1 #include "user.hpp" 2 #include <iostream> 3 #include <vector> 4 #include <string> 5 using std::cin; 6 using std::cout; 7 using std::endl; 8 using std::vector; 9 using std::string; 10 void test() { 11 vector<User> user_lst; 12 User u1("Alice", "2024113", "[email protected]"); 13 user_lst.push_back(u1); 14 cout << endl; 15 User u2("Bob"); 16 u2.set_email(); 17 u2.change_password(); 18 user_lst.push_back(u2); 19 cout << endl; 20 User u3("Hellen"); 21 u3.set_email(); 22 u3.change_password(); 23 user_lst.push_back(u3); 24 cout << endl; 25 cout << "There are " << user_lst.size() << " users. they are: " << endl; 26 for (auto& i : user_lst) { 27 i.display(); 28 cout << endl; 29 } 30 } 31 int main() { 32 test(); 33 }View Code
6. 实验任务6 date.h
1 class Date { 2 private: 3 int year; 4 int month; 5 int day; 6 int totalDays; 7 public: 8 Date(int year, int month, int day); 9 int getYear() const { return year; } 10 int getMonth()const { return month; } 11 int getDay()const { return day; } 12 int getMaxDay()const; 13 bool isLeapYear()const { 14 return year % 4 == 0 && year % 100 != 0 || year % 400 == 0; 15 } 16 void show() const; 17 int distance(const Date& date)const { 18 return totalDays - date.totalDays; 19 } 20 };View Code
account.h
1 #ifndef _ _ACCOUNT_H_ _ 2 #define _ _ACCOUNT_H_ _ 3 #include"date.h" 4 #include<string> 5 class SavingsAccount { 6 private: 7 std::string id; 8 double balance; 9 double rate; 10 Date lastDate; 11 double accumulation; 12 static double total; 13 void record(const Date& date, double amount, const std::string& desc); 14 void error(const std::string& msg) const; 15 double accumulate(const Date& date)const { 16 return accumulation + balance * date.distance(lastDate); 17 18 } 19 public: 20 SavingsAccount(const Date& date, const std::string& id, double rate); 21 const std::string& getId()const { return id; } 22 double getBalance()const { return balance; } 23 double getRate()const { return rate; } 24 static double getTotal() { return total; } 25 void deposit(const Date& date, double amount, const std::string& desc); 26 void withdraw(const Date& date, double amount, const std::string& desc); 27 void settle(const Date& date); 28 void show()const; 29 }; 30 #endif //_ _ACCOUNT_H_ _View Code
date.cpp
1 #include"date.h" 2 #include<iostream> 3 #include<cstdlib> 4 using namespace std; 5 namespace { 6 const int DAYS_BEFORE_MONTH[] = { 0,31,59,90,120,151,181,212,243,273,304,334,365 }; 7 } 8 Date::Date(int year, int month, int day) :year(year), month(month), day(day) { 9 if (day <= 0 || day > getMaxDay()) { 10 cout << "Invalid date: "; 11 show(); 12 cout << endl; 13 exit(1); 14 } 15 int years = year - 1; 16 totalDays = years * 365 + years / 4 - years / 100 + years / 400 + DAYS_BEFORE_MONTH[month - 1] + day; 17 if (isLeapYear() && month > 2)totalDays++; 18 } 19 int Date::getMaxDay()const { 20 if (isLeapYear() && month == 2) 21 return 29; 22 else 23 return DAYS_BEFORE_MONTH[month] - DAYS_BEFORE_MONTH[month - 1]; 24 } 25 void Date::show()const { 26 cout << getYear() << "-" << getMonth() << "-" << getDay(); 27 }View Code
account.cpp
1 #include"account.h" 2 #include<cmath> 3 #include<iostream> 4 using namespace std; 5 double SavingsAccount::total = 0; 6 SavingsAccount::SavingsAccount(const Date& date, const string& id, double rate) 7 :id(id), balance(0), rate(rate), lastDate(date), accumulation(0) { 8 date.show(); 9 cout << "\t#" << id << "created" << endl; 10 11 } 12 void SavingsAccount::record(const Date& date, double amount, const string& desc) { 13 accumulation = accumulate(date); 14 lastDate = date; 15 amount = floor(amount * 100 + 0.5) / 100; 16 balance -= amount; 17 total += amount; 18 date.show(); 19 cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl; 20 21 } 22 void SavingsAccount::error(const string& msg)const { 23 cout << "Error(#" << id << "):" << msg << endl; 24 } 25 void SavingsAccount::deposit(const Date& date, double amount, const string& desc) { 26 record(date, amount, desc); 27 } 28 void SavingsAccount::withdraw(const Date& date, double amount, const string& desc) { 29 if (amount > getBalance()) 30 error("not enough money"); 31 else 32 record(date, -amount, desc); 33 34 } 35 void SavingsAccount::settle(const Date& date) { 36 double interest = accumulate(date) * rate 37 / date.distance(Date(date.getYear() - 1, 1, 1)); 38 if (interest != 0) 39 record(date, interest, "interest"); 40 accumulation = 0; 41 42 } 43 void SavingsAccount::show()const { 44 cout << id << "\tBalance:" << balance; 45 }View Code
6_25.cpp
1 #include"account.h" 2 #include<iostream> 3 using namespace std; 4 int main() { 5 Date date(2008, 11, 1); 6 SavingsAccount accounts[] = { 7 SavingsAccount(date,"03755217",0.015), 8 SavingsAccount(date,"02342342",0.015) 9 10 }; 11 const int n = sizeof(accounts) / sizeof(SavingsAccount); 12 accounts[0].deposit(Date(2008, 11, 5), 5000, "salary"); 13 accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323"); 14 accounts[0].deposit(Date(2008, 12, 5), 5500, "salary"); 15 accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop"); 16 cout << endl; 17 for (int i = 0; i < n; i++) { 18 accounts[i].settle(Date(2009, 1, 1)); 19 accounts[i].show(); 20 cout << endl; 21 } 22 cout << "Total:" << SavingsAccount::getTotal() << endl; 23 return 0; 24 }View Code
标签:std,const,cout,对象,编程,int,实验,vectorInt,include From: https://www.cnblogs.com/nuist0177/p/18525817