函数原型

下列程序输入3个整数(3个数之和不会超过整型数的最大值)，计算并输出它们的平均值。下划线填入那个（些）行既不会导致编译错误也不会导致编译警告。
#include <stdio.h>

____________________________________________________________
A)    函数原型直接省略
B)    getAverage(int a,int b,int c);
C)    double getAverage(int a,int b,int c);
D)    double getAverage(int a,b,c);
E)    double getAverage(int x,int y,int z);
F)    double getAverage(int a,int b,int c) {}
G)    double  getAverage(int a,int b);
H)    double getAverage(int,int,int);
I)    double getAverage(double a,double b,double c);
J)    double getAverage(int a;int b;int c);
K)    double getAverage(a,b,c);

int main() {
    int a,b,c;
    scanf("%d%d%d",&a,&b,&c);
    printf("%.3f\n",getAverage(a,b,c));
    return 0;
}

double getAverage(int a,int b,int c) {return a/3.0+b/3.0+c/3.0;}

#include<stdio.h>

int main(){
  
  printf("CEH");
}

函数定义

下列程序输入3个整数(3个数之和不会超过整型数的最大值)，计算并输出它们的平均值。下划线填入那个（些）行既不会导致编译错误也不会导致编译警告,并且可以得到正确的结果。
#include <stdio.h> 

double getAverage(int a,int b,int c);

int main() {
    int a,b,c;
    scanf("%d%d%d",&a,&b,&c);
    printf("%.3f\n",getAverage(a,b,c));
    return 0;
}
____________________________________________________________________________________
A)    double getAverage(int a,int b,int c) {return (double)(a+b+c)/3.0};
B)    double getAverage(int a,int b,int c) {return a/3.0+b/3.0+c/3.0;}
C)    double getAverage(int α,int β,int γ) {return (double)(α+β+γ)/3.0;}
D)    double getAverage(int a,int b,int c) {return a/3+b/3+c/3;}
E)    double getAverage(int a,int b,int c) {return ((double)a+b+c)/3.0;}
F)    double getAverage(int a,int b,int c) {return (double)(a+b+c)/3.0;}
G)    double getAverage(int a,int b,int c) {return (a+b+c)/3.0;}
H)    double getAverage(int a,int b,int c) {return (a+b+c)/3;}
I)    double getAverage(int a,int b,int c) {return (a+b+c/3.0);}
J)    double getAverage(int a,int b,int c) {return double(a+b+c)/3;}
K)    double getAverage(int a,int b,int c) {return (double)(a+b+c)/(double)3;}
L)    double getAverage(int x,int y,int z) {return (double)(x+y+z)/3.0;}
M)    函数定义直接省略
N)    getAverage(int a,int b,int c) {return (double)(a+b+c)/3.0;}
O)    int getAverage(int a,int b,int c) {return (double)(a+b+c)/3.0;}
P)    double getAverage(int a,b,c) {return (double)(a+b+c)/3.0;}
Q)    double getAverage(int a;int b;int c) {return (double)(a+b+c)/3.0;}
R)    double getAverage(int x1,int x2,int x3) {return (double)(x1+x2+x3)/3.0;}
S)    double getAverage(int a,int b,int c) {int x=a+b+c;return x/3.0;}
T)    double getAverage(int a,int b,int c) {double x=a+b+c;return x/3;}
U)    double getAverage(int a,int b) {return (double)(a+b)/2.0;}
V)    double getAverage(double a,double b,double c) {return (a+b+c)/3.0;}

#include<stdio.h>

int main(){
  printf("BEFGKLRST");
}

函数调用

下列程序输入3个整数(3个数之和不会超过整型数的最大值)，计算并输出它们的平均值。下划线填入那个（些）行既不会导致编译错误也不会导致编译警告。
#include <stdio.h>

double getAverage(int a,int b,int c);

int main() {
    int a,b,c;
    scanf("%d%d%d",&a,&b,&c);
    __________________________________________________________
A)    printf("%.3f\n",getAverage(x,y,z));
B)    printf("%.3f\n",getAverage(a,b,c));
C)    printf("%.3f\n",getAverage(int a,b,c));
D)    printf("%.3f\n",getAverage(a+1,b+b,c*c));
E)    printf("%.3f\n",getAverage(int a,int b,int c));
F)    printf("%.3f\n",getAverage(+123,'A',0xa3));
G)    printf("%.3f\n",getAverage(1L,3.5,7.f));
H)    printf("%.3f\n",getAverage(&a,&b,&c));
I)    printf("%.3f\n",getAverage(a;b;c));
J)    printf("%.3f\n",getAverage(a,b));
    return 0;
}

double getAverage(int a,int b,int c) {return a/3.0+b/3.0+c/3.0;}

#include<stdio.h>

int main(){
 printf("BDF");
  
}

计算3个整数的平均值

输入3个非常大的整数（三者之和会大于整数的最大值），计算它们的平均值，假定IDE的long类型的长度>int类型的长度。下划线填入那个（些）行程序可以获得正确的结果。
#include <stdio.h>
#include <limits.h>

double getAverage(int a,int b,int c);

int main() {
    printf("%.3f\n",getAverage(INT_MAX,INT_MAX,INT_MAX));
    return 0;
}
_____________________________________________________________________________
A)    double getAverage(int a,int b,int c) {return (double)(a+b+c)/3.0;}
B)    double getAverage(int a,int b,int c) {return a/3+b/3+c/3;}
C)    double getAverage(int a,int b,int c) {return a/3.0+b/3.0+c/3.0;}
D)    double getAverage(int a,int b,int c) {return ((double)a+b+c)/3.0;}
E)    double getAverage(int a,int b,int c) {double x=a+b+c;return x/3;}
F)    double getAverage(int a,int b,int c) {long int x=(long)a+b+c;return x/3.0;}
G)    double getAverage(int a,int b,int c) {return (a+b+c)/3.0;}
H)    double getAverage(int a,int b,int c) {int x=a+b+c;return x/3.0;}

#include<stdio.h>

int main() {

	printf("CDF");
}