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#yyds干货盘点# LeetCode 腾讯精选练习 50 题:螺旋矩阵 II

时间:2022-10-28 19:03:37浏览次数:75  
标签:yyds matrix int 50 II column num left row

题目:

给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。

 

示例 1:

输入:n = 3

输出:[[1,2,3],[8,9,4],[7,6,5]]

示例 2:

输入:n = 1

输出:[[1]]

代码实现:

class Solution {
public int[][] generateMatrix(int n) {
int num = 1;
int[][] matrix = new int[n][n];
int left = 0, right = n - 1, top = 0, bottom = n - 1;
while (left <= right && top <= bottom) {
for (int column = left; column <= right; column++) {
matrix[top][column] = num;
num++;
}
for (int row = top + 1; row <= bottom; row++) {
matrix[row][right] = num;
num++;
}
if (left < right && top < bottom) {
for (int column = right - 1; column > left; column--) {
matrix[bottom][column] = num;
num++;
}
for (int row = bottom; row > top; row--) {
matrix[row][left] = num;
num++;
}
}
left++;
right--;
top++;
bottom--;
}
return matrix;
}
}

标签:yyds,matrix,int,50,II,column,num,left,row
From: https://blog.51cto.com/u_13321676/5805235

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