实验1

task1-1.c

#include <stdio.h>
int main(){
    printf(" o \n");
    printf("<H>\n");
    printf("I I\n");
    printf(" o \n");
    printf("<H>\n");
    printf("I I\n");
    return 0;
}

task1-2.c

#include <stdio.h>
int main(){
    printf(" o       o \n");
    printf("<H>     <H>\n");
    printf("I I     I I\n");
    return 0;
}

task2.c

#include <stdio.h>
 int main() 
{
    double a, b, c;
    scanf("%lf%lf%lf", &a, &b, &c);
    if(a+b>c && b+c>a && a+c>b)
        printf("能构成三角形\n");
    else
        printf("不能构成三角形\n");
    return 0;
}

task3.c

#include <stdio.h>
 int main()
 {
    char ans1, ans2; 
    printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) :  ");
    ans1 = getchar(); 
    getchar(); 
    printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) :  ");
    ans2 = getchar();
    if (ans1 == 'y' || ans1 == 'Y' && ans2 == 'y' || ans2 == 'Y') 
        printf("\n罗马不是一天建成的, 继续保持哦:)\n");
    else
        printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
    return 0;
}

回答问题：删去line9后无法回答第二个问题，直接给出了“罗马”语句

        原因：line9中的getchar用来读取下一个标准字符，而没有了之后，就不能继续读取下一个字符

task4.c

#include<stdio.h>

 int main()
 {
    double x, y;
    char c1, c2, c3;
    int a1, a2, a3;
    
    scanf(" %d %d %d",&a1,&a2,&a3);   
    printf("a1 = %d, a2 = %d, a3 = %d\n",a1,a2,a3);   
    
    scanf(" %c %c %c", &c1, &c2, &c3);    
    printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
    
    scanf("%lf %lf", &x, &y);
    printf("x = %lf, y = %lf\n",x,y);
    return 0;
 }

task5.c

#include <stdio.h>
 int main() 
{
    int year;
   double a;
   a = 1000000000/(3600*24*365.0);
   year = (a+0.5)/1;
   
   
    printf("10亿秒约等于%d年\n", year);
    return 0;
 }

task6-2.c

#include <stdio.h>
 #include <math.h>
 int main()
 {
    double x, ans;
    
    while(scanf("%lf", &x) != EOF)
    {
        ans = pow(x, 365);
         printf("%.2f的365次方: %.2f\n", x, ans);
         printf("\n"); 
} 
return 0;
} 

task7

#include <stdio.h>
int main()
{
    double f,c;
    while(scanf("%lf",&c) !=EOF)
    {
        f = 1.8*c+32;
        printf("摄氏度c=%.2f时，华氏度f=%.2f\n",c,f);
        printf("\n");
    }
    
    return 0;
}

task8.c

#include <stdio.h>
 #include <math.h>
 int main()
 {
     
    double a,b,c,s,area;
    
    while(scanf("%lf %lf %lf", &a,&b,&c) != EOF)
    {
        s = (a+b+c)/2;
        area = sqrt(s*(s-a)*(s-b)*(s-c));
        
         printf("a = %.0f,b = %.0f,c = %.0f,area = %.3f\n", a,b,c,area);
         
         printf("\n"); 
} 
return 0;
}