template<class Node>
struct PersidentSegmentTree {
#define lc(u) tr[u].l
#define rc(u) tr[u].r
const int n;
int tot = 0;
vector<Node> tr;
vector<int> root;
PersidentSegmentTree(): n(0) {}
PersidentSegmentTree(int n_): n(n_) {
int N = (n << 6) + 10;
tr.reserve(N); root.reserve(N);
tr.resize(N); root.resize(N);
}
PersidentSegmentTree(vector<int>& a): PersidentSegmentTree(a.size() - 1) {
function<void(int&, int, int)> build = [&](int& now, int l, int r) {
now = ++ tot;
if (l == r) {
return ;
}
int m = (l + r) >> 1;
build(lc(now), l, m);
build(rc(now), m + 1, r);
};
build(root[0], 1, n);
}
//上传
void pushup(int u) {
if (tr[lc(u)].Sum >= tr[rc(u)].Sum) {
tr[u].Sum = tr[lc(u)].Sum;
tr[u].pos = tr[lc(u)].pos;
} else {
tr[u].Sum = tr[rc(u)].Sum;
tr[u].pos = tr[rc(u)].pos;
}
}
//动态开点/更新树结点
void insert(int& now, int l, int r, int pos, int w) {
if (!now)
now = ++ tot;
if (l == r) {
tr[now].Sum += w;
tr[now].pos = pos;
return;
}
int m = l + r >> 1;
if (pos <= m)
insert(lc(now), l, m, pos, w);
else
insert(rc(now), m + 1, r, pos, w);
pushup(now);
}
//开新前缀树,last代表前缀,now代表新树根
void insert(int& now, int last, int l, int r, int pos, int w) {
now = ++ tot;
tr[now] = tr[last];
if (l == r) {
return;
}
int m = l + r >> 1;
if (pos <= m)
insert(lc(now), lc(last), l, m, pos, w);
else
insert(rc(now), rc(last), m + 1, r, pos, w);
}
//单点
int query(int now, int l, int r, int pos) {
if (l == r) {
return tr[now].Sum;
}
int m = l + r >> 1;
if (pos <= m)
return query(lc(now), l, m, pos);
else
return query(rc(now), m + 1, r, pos);
}
//区间查询 [u,v]->[root[l-1],root[r]]
int query(int u, int v, int l, int r, int pos) {
if (l == r) {
return tr[u].Sum;
}
int m = l + r >> 1;
if (pos <= m)
return query(lc(u), lc(v), l, m, pos);
else
return query(rc(u), rc(v), m + 1, r, pos);
}
void merge(int &u, int v, int l, int r) {
if (!u || !v) {
u = u + v;
return;
}
if (l == r) {
tr[u].Sum += tr[v].Sum;
return ;
}
int m = l + r >> 1;
merge(lc(u), lc(v), l, m);
merge(rc(u), rc(v), m + 1, r);
pushup(u);
}
};
struct Node {
int l, r;
int Sum = 0, pos = 0;
};
标签:int,合并,线段,tr,pos,rc,now,Sum,模板
From: https://www.cnblogs.com/Kescholar/p/18350415