Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
代码长度限制
16 KB
时间限制
400 ms
内存限制
64 MB
栈限制
8192 KB
#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
int sum = a + b;
stringstream ss;
ss << sum;
string formatted_sum = ss.str();
// Output the sum in standard format with commas
int len = formatted_sum.length();
for (int i = 0; i < len; ++i) {
cout << formatted_sum[i];
if ((len - i - 1) % 3 == 0 && i != len - 1 && formatted_sum[i] != '-') {
cout << ",";
}
}
cout << endl;
return 0;
}
标签:case,Format,int,sum,contains,include,Specification,1001
From: https://blog.csdn.net/2301_80161204/article/details/140684783