area 0:
r1 0/0/0 :192.168.1.1 26
r2 0/0/0 :192.168.1.2 26
r3 0/0/0 :192.168.1.3 26
r3 loopbank 0 192.168.1.65 26
area 1:
r3 0/0/1 :192.168.1.129 25
r4 0/0/0 :192.168.1.130 25
r4 loopbank 4.4.4.4 24
加密：
area 0：
[R1-GigabitEthernet0/0/0]ospf authentication-mode md5 1 cipher 222
[R2-GigabitEthernet0/0/0]ospf authentication-mode md5 1 cipher 222
[R3-GigabitEthernet0/0/0]ospf authentication-mode md5 1 cipher 222
area 1
[R3-GigabitEthernet0/0/1]ospf authentication-mode md5 1 cipher 111
[R4-GigabitEthernet0/0/0]ospf authentication-mode md5 1 cipher 111
给R4写个缺省：[R4-ospf-1]default-route-advertise always
此时发现，R3为DR,R2为BDR
所以，r1,r2不参选：
[R1-GigabitEthernet0/0/0]ospf dr-priority 0
[R2-GigabitEthernet0/0/0]ospf dr-priority 0
标签：ospf,GigabitEthernet0,192.168,authentication,cipher,实验,OSPF,md5 From： https://blog.csdn.net/shsbcheknexj/article/details/140358817