#include <stdio.h>
#define N 10
typedef struct {
char isbn[20]; // isbn号
char name[80]; // 书名
char author[80]; // 作者
double sales_price; // 售价
int sales_count; // 销售册数
} Book;
void output(Book x[], int n)
{
printf("ISBN号 书名 作者 售价 销售册数\n");
int i;
for(i=0; i<n; i++)
printf("%17s %-25s %-17s %-5g %-5d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
void sort(Book x[], int n)
{
int i,j;
for(i=0; i<n-1; i++)
{
for(j=0; j<n-1-i; j++)
{
Book t;
if(x[j].sales_count<x[j+1].sales_count)
{
t = x[j];
x[j] = x[j+1];
x[j+1] = t;
}
}
}
}
double sales_amount(Book x[], int n)
{
int i;
double s=0;
for(i=0; i<n; i++)
s += x[i].sales_price*x[i].sales_count;
return s;
}
int main() {
Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59},
{"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16},
{"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42},
{"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}};
printf("图书销量排名: \n");
sort(x, N);
output(x, N);
printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
return 0;
}
#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
// 函数声明
void input(Date *pd); // 输入日期给pd指向的Date变量
int day_of_year(Date d); // 返回日期d是这一年的第多少天
int compare_dates(Date d1, Date d2); // 比较两个日期:
// 如果d1在d2之前，返回-1;
// 如果d1在d2之后，返回1
// 如果d1和d2相同，返回0
void test1() {
Date d;
int i;
printf("输入日期:(以形如2023-12-11这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
}
void input(Date *pd)
{
scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}
int day_of_year(Date d)
{
int n;
switch(d.month)
{
case 1: n = d.day; break;
case 2: n = 31+d.day; break;
case 3: n = 60+d.day; break;
case 4: n = 91+d.day; break;
case 5: n = 121+d.day; break;
case 6: n = 152+d.day; break;
case 7: n = 182+d.day; break;
case 8: n = 213+d.day; break;
case 9: n = 244+d.day; break;
case 10: n = 274+d.day; break;
case 11: n = 305+d.day; break;
case 12: n = 335+d.day; break;
}
if(d.year%4!=0)
n -= 1;
return n;
}
int compare_dates(Date d1, Date d2)
{
if(d1.year<d2.year)
return -1;
else if(d1.year>d2.year)
return 1;
else if(day_of_year(d1)<day_of_year(d2))
return -1;
else if(day_of_year(d1)==day_of_year(d2))
return 0;
else
return 1;
}
#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20]; // 用户名
char password[20]; // 密码
enum Role type; // 账户类型
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n)
{
int i;
for(i=0; i<n; i++)
{
char T[20];
int l,j;
l = strlen(x[i].password);
for(j=0; j<l; j++)
T[j] = '*';
printf("%-10s%-15s",x[i].username,T,x[i].type);
switch(x[i].type)
{
case 0: printf("admin \n"); break;
case 1: printf("student\n"); break;
case 2: printf("teacher\n"); break;
}
}
}
#include <stdio.h>
#include <string.h>
typedef struct {
char name[20]; // 姓名
char phone[12]; // 手机号
int vip; // 是否为紧急联系人，是取1；否则取0
} Contact;
// 函数声明
void set_vip_contact(Contact x[], int n, char name[]); // 设置紧急联系人
void output(Contact x[], int n); // 输出x中联系人信息
void display(Contact x[], int n); // 按联系人姓名字典序升序显示信息，紧急联系人最先显示
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[])
{
int i;
for(i=0; i<n; i++)
if( strcmp(name,x[i].name)==0 )
x[i].vip = 1;
}
void display(Contact x[], int n)
{
int i;
for(i=0; i<n-1; i++)
{
int j;
for(j=0; j<n-1-i; j++)
{
if( strcmp(x[j].name,x[j+1].name)>0 )
{
Contact t;
t = x[j];
x[j] = x[j+1];
x[j+1] = t;
}
}
}
for(i=0; i<n; i++)
if( x[i].vip == 1)
printf("%-7s%-20s*\n",x[i].name,x[i].phone);
for(i=0; i<n; i++)
if( x[i].vip != 1)
printf("%-7s%-20s\n",x[i].name,x[i].phone);
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
标签：case,int,break,实验,printf,Date,day From： https://www.cnblogs.com/5464665465L/p/17894167.html