#include<stdio.h>
#include<string.h> #define N 3 typedef struct student{ int id; char name[20]; char subject[20]; double perf; double mid; double final; double total; char level[10]; } STU; void input(STU [], int); void output(STU [],int); void calc(STU [],int); int fail(STU [],STU [], int); void sort(STU [],int); int main() { STU st[N],fst[N]; int k; printf("录入学生成绩信息:\n"); input(st,N); printf("\n成绩处理...\n"); calc(st,N); k = fail(st,fst,N); sort(st,N); printf("\n学生成绩排名情况:\n"); output(st,N); printf("\n不及格学生信息:\n"); output(fst,N); return 0; } void input(STU s[],int n){ int i; for(i = 0;i<n;i++) scanf("%d %s %s %lf %lf %lf",&s[i].id,s[i].name,s[i].subject,&s[i].perf,&s[i].mid,&s[i].final); } void output(STU s[],int n){ int i; printf("---------------\n"); printf("学号 姓名 科目 平时 期中 总评 等级\n"); for(i = 0;i<n;i++) printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level); } void calc(STU s[], int n){ int i; for(i = 0;i<n;i++){ s[i].total = s[i].perf*0.2+s[i].mid*0.2+s[i].final*0.6; if(s[i].total>=90) strcpy(s[i].level,"优"); else if(s[i].total>=80&&s[i].total<90) strcpy(s[i].level,"良"); else if(s[i].total>=70&&s[i].total<80) strcpy(s[i].level,"中"); else if(s[i].total>=60&&s[i].total<70) strcpy(s[i].level,"及格"); else strcpy(s[i].level,"不及格"); } } int fail(STU s[],STU t[], int n){ int i,cnt = 0; for(i = 0;i<n;i++) if(s[i].total<60) t[cnt++] = s[i]; return cnt; } void sort(STU s[], int n){ int i, j; STU t; for(i = 0;i<n-1;i++) for(j = 0;j<n-1-i;j++) if(s[i].total<s[j+1].total){ t = s[j]; s[j] = s[j+1]; s[j+1] = t; } }
task 2
#include <stdio.h> #include <string.h> #define N 10 #define M 80 typedef struct { char name[M]; char author[M]; } Book; int main() { Book x[N] = { {"《一九八四》", "乔治.奥威尔"}, {"《美丽新世界》", "赫胥黎"}, {"《昨日的世界》", "斯蒂芬.茨威格"}, {"《万历十五年》", "黄仁宇"}, {"《一只特立独行的猪》", "王小波"}, {"《百年孤独》", "马尔克斯"}, {"《查令十字街84号》", "海莲.汉芙"}, {"《只是孩子》", "帕蒂.史密斯"}, {"《刀锋》", "毛姆"}, {"《沉默的大多数》", "王小波"} }; Book *ptr; int i; char author[M]; printf("所有图书信息:\n"); for(ptr = x;ptr<x+N;++ptr) printf("%-30s%-30s\n",ptr->name,ptr->author); printf("\n输入作者名:"); gets(author); for(ptr = x;ptr<x+N;++ptr) if(strcmp(ptr->author,author) == 0){ printf("%-30s%-30s\n",ptr->name,ptr->author); } return 0; }
task 3_1
#include <stdio.h> #include <stdlib.h> #define N 80 typedef struct FilmInfo { char name[N]; char director[N]; char region[N]; int year; struct FilmInfo *next; } Film; void output(Film *head); Film *insert(Film *head, int n); int main() { int n; Film *head; head = NULL; printf("输入影片数目: "); scanf("%d", &n); head = insert(head, n); printf("\n所有影片信息如下: \n"); output(head); return 0; } Film *insert(Film *head, int n) { int i; Film *p; for(i = 1; i <= n; ++i) { p = (Film *)malloc(sizeof(Film)); printf("请输入第%d部影片信息: ", i); scanf("%s %s %s %d", p->name, p->director, p->region, &p->year); p->next = head; head = p; } return head; } void output(Film *head) { Film *p; p = head; while(p != NULL) { printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year); p = p -> next; } }
task3_2
#include <stdio.h> #include <stdlib.h> #define N 80 typedef struct FilmInfo { char name[N]; char director[N]; char region[N]; int year; struct FilmInfo *next; } Film; void output(Film *head); Film *insert(Film *head, int n); int main() { int n; Film *head; Film *p; p = (Film *)malloc(sizeof(Film)); p->next = NULL; head = p; printf("输入影片数目: "); scanf("%d", &n); head = insert(head, n); printf("\n所有影片信息如下: \n"); output(head); return 0; } Film *insert(Film *head, int n) { int i; Film *p; for(i = 1; i <= n; ++i) { p = (Film *)malloc(sizeof(Film)); printf("请输入第%d部影片信息: ", i); scanf("%s %s %s %d", p->name, p->director, p->region, &p->year); p->next = head->next; head->next = p; } return head; } void output(Film *head) { Film *p; p = head->next; while(p != NULL) { printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year); p = p -> next; } }
task 4
#include <stdio.h> #define N 10 typedef struct { char isbn[20]; // isbn号 char name[80]; // 书名 char author[80]; // 作者 double sales_price; // 售价 int sales_count; // 销售册数 } Book; void output(Book x[], int n); void sort(Book x[], int n); double sales_amount(Book x[], int n); int main() { Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}, {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16}, {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42}, {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}}; printf("图书销量排名: \n"); sort(x, N); output(x, N); printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); return 0; } void output(Book x[],int n){ Book *p; printf("ISBN号 书名 作者 售价 销售册数\n"); for(p = x;p<x+n;p++){ printf("%-20s %-30s %-20s %-20f %-20d\n",p->isbn,p->name,p->author,p->sales_price,p->sales_count); } } void sort(Book x[],int n){ int i,j; Book t; for(i = 0;i<n-1;i++){ for(j = 0;j<n-1-i;j++) if(x[j].sales_count<x[j+1].sales_count){ t = x[j]; x[j] = x[j+1]; x[j+1] = t; } } } double sales_amount(Book x[],int n){ double s = 0; Book *p; for(p = x;p<x+n;p++){ s = s + p->sales_count*p->sales_price; } return s; }
task 5
标签:head,int,void,char,实验,printf,Film From: https://www.cnblogs.com/u3291193/p/17894958.html