实验六 C语言结构体、枚举应用

4.任务4

 1 #include <stdio.h>
 2 #define N 10
 3 
 4 typedef struct {
 5     char isbn[20];          
 6     char name[80];         
 7     char author[80];        
 8     double sales_price;    
 9     int  sales_count;       
10 } Book;
11 
12 void output(Book x[], int n);
13 void sort(Book x[], int n);
14 double sales_amount(Book x[], int n);
15 
16 int main() {
17     Book x[N] = {{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59},
18                  {"978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16},
19                  {"978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27},
20                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
21                  {"978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42},
22                  {"978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39},
23                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
24                  {"978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31},
25                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
26                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}};
27     
28     printf("图书销量排名: \n");
29     sort(x, N);
30     output(x, N);
31 
32     printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
33     
34     return 0;
35 }
36 
37 void output(Book x[], int n){
38     int i;
39     printf("ISBN号            书名                      作者               售价    销售册数\n");
40     for(i=0;i<n-1;i++)
41       printf("%-17s %-25s %-20s %-6.0f %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
42 }
43 
44 void sort(Book x[], int n){
45     int i,j;
46     Book t;
47     for(i=0;i<n-1;i++)
48       for(j=0;j<n-1-i;j++)
49         if(x[j].sales_count<x[j+1].sales_count){
50             t=x[j];
51             x[j]=x[j+1];
52             x[j+1]=t;
53         }
54 }
55 
56 double sales_amount(Book x[], int n){
57     int i;
58     double m=0.0;
59     for(i=0;i<n;i++){
60         m=m+x[i].sales_price*x[i].sales_count;
61     }
62     return m;
63 }

5.实验5

  1 #include <stdio.h>
  2 
  3 typedef struct {
  4     int year;
  5     int month;
  6     int day;
  7 } Date;
  8 
  9 void input(Date *pd);                   
 10 int day_of_year(Date d);              
 11 int compare_dates(Date d1, Date d2);    
 12                                        
 13 
 14 void test1() {
 15     Date d;
 16     int i;
 17 
 18     printf("输入日期:(以形如2023-12-11这样的形式输入)\n");
 19     for(i = 0; i < 3; ++i) {
 20         input(&d);
 21         printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
 22     }
 23 }
 24 
 25 void test2() {
 26     Date Alice_birth, Bob_birth;
 27     int i;
 28     int ans;
 29 
 30     printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n");
 31     for(i = 0; i < 3; ++i) {
 32         input(&Alice_birth);
 33         input(&Bob_birth);
 34         ans = compare_dates(Alice_birth, Bob_birth);
 35         
 36         if(ans == 0)
 37             printf("Alice和Bob一样大\n\n");
 38         else if(ans == -1)
 39             printf("Alice比Bob大\n\n");
 40         else
 41             printf("Alice比Bob小\n\n");
 42     }
 43 }
 44 
 45 int main() {
 46     printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
 47     test1();
 48 
 49     printf("\n测试2: 两个人年龄大小关系\n");
 50     test2();
 51 }
 52 
 53 void input(Date *pd) {
 54       scanf("%d-%d-%d",&(*pd).year,&(*pd).month,&(*pd).day);
 55 
 56 }
 57 
 58 int day_of_year(Date d) {
 59     int i,a=0;
 60     int x[13]={31,28,31,30,31,30,31,31,30,31,30,31};
 61     if((d.year%400==0)||d.year%4==0&&d.year%100!=0){
 62         x[1]=29;
 63     }
 64     for(i=0;i<d.month-1;i++){
 65         a=a+x[i];
 66     }
 67     a=a+d.day;
 68     return a;
 69     
 70 
 71 }
 72 
 73 int compare_dates(Date d1, Date d2) {
 74     int x;
 75     if(d1.year<d2.year ){
 76         x=-1;
 77         return x;
 78     }
 79     else if(d1.year>d2.year){
 80         x=1;
 81         return x;
 82     }
 83     else{
 84         if(d1.month<d2.month ){
 85             x=-1;
 86             return x;
 87         }
 88         else if(d1.month>d2.month ){
 89             x=1;
 90             return x;
 91         }
 92         else{
 93                 if(d1.day<d2.day ){
 94             x=-1;
 95             return x;
 96         }
 97         else if(d1.day>d2.day ){
 98             x=1;
 99             return x;
100         }
101         else{x=0;
102         return x;
103             
104         }
105             
106         }
107     }
108 
109 }

6.实验6

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 enum Role {admin, student, teacher};
 5 
 6 typedef struct {
 7     char username[20];  
 8     char password[20];  
 9     enum Role type;     
10 } Account;
11 
12 
13 void output(Account x[], int n);   
14 
15 int main() {
16     Account x[] = {{"A1001", "123456", student},
17                     {"A1002", "123abcdef", student},
18                     {"A1009", "xyz12121", student}, 
19                     {"X1009", "9213071x", admin},
20                     {"C11553", "129dfg32k", teacher},
21                     {"X3005", "921kfmg917", student}};
22     int n;
23     n = sizeof(x)/sizeof(Account);
24     output(x, n);
25 
26     return 0;
27 }
28 
29 void output(Account x[], int n) {
30     int i,j;
31     for(i=0;i<n;i++){
32         printf("%-10s",x[i].username);
33         for(j=0;j<strlen(x[i].password);j++){
34             printf("*");
35         }
36         printf("\t");
37         switch(x[i].type){
38             case 0:printf("admin\n");break;
39             case 1:printf("student\n");break;
40             case 2:printf("teacher\n");
41         }
42     }
43 
44 }