反转一个整数

#include <stdio.h>

int reverse_number(int num) { int reversed = 0;

while (num != 0) {
    int remainder = num % 10;
    reversed = reversed * 10 + remainder;
    num /= 10;
}

return reversed;

}

int main() { int num = 12345; int reversed_num = reverse_number(num); printf("反转后的数字：%d\n", reversed_num);

return 0;

}