链接
https://leetcode.cn/problems/number-complement/description/
思路
没啥好说的,二进制与十进制的互相转换,基本功。
代码
class Solution: def findComplement(self, num: int) -> int: bin_li = self.int2bin(num) bin_li = self.reverse(bin_li) return self.bin2int(bin_li) def bin2int(self, bin_li): res = 0 for i in range(len(bin_li)): ex = len(bin_li)-1-i res += int(bin_li[i]) * pow(2, ex) return res def int2bin(self, num): res = [] while num != 0: res.append(num % 2) num = num // 2 return res[::-1] def reverse(self, bin_li): res = [] for i in bin_li: if int(i) == 1: res.append(0) else: res.append(1) return res
标签:bin,数字,int,res,self,li,num,476,补数 From: https://www.cnblogs.com/bjfu-vth/p/17676813.html