计数项目下的代码行数

给出工程路径、指定代码类型，计算总共有多少行代码。

以下代码的原理是，递归搜索文件夹下的源码文件，然后统计该文件有多少行，然后累加。

# -*- coding: utf-8 -*-
# @Author : ZhaoKe
# @Time : 2021-10-08 18:08
import os


sum_line_count = 0


def count_file_line(path):
    # print("当前文件:", path)
    count = 1
    with open(path, 'r', encoding="utf_8_sig") as f:
        line = f.readline()
        while line:
            line = f.readline()
            count += 1
    return count


def count_dir_files_code_lines(path, category):
    global sum_line_count
    if os.path.isdir(path):
        for sub_dir in os.listdir(path):
            count_dir_files_code_lines(os.path.join(path, sub_dir), category)
    elif path[-len(category):] == category:
        # elif path[-2:] == "cs":
        sum_line_count += count_file_line(path)
        # print("当前计数：", sum_line_count)
    return sum_line_count


if __name__ == '__main__':
    line_count = count_dir_files_code_lines("E:/ExecuSimu/ExecuDS10/Assets/Scripts", 'cs')
    print(line_count)

以上代码以C#文件为例，文件后缀为"cs"，能够给出正确结果。