数据转换-位串字节数组

0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

1 参考《GMT 0009-2012 SM2密码算法使用规范》第6节“数据转换” 在附件中的utils.h和utils.c中完成位串与８位字节串的转换功能(10')：
int Bitstr2ByteArr(unsigned char * bs, unsigned char * ba，int *lba);
int ByteArr2Bitstr(unsigned char * ba, unsigned char * bs, int *lbs);

2 并写出测试代码测试上述函数(不能与下面代码一样)，比如(10'):

unsigned char bs [] = "1010010100011100";
int len;
Bitstr2ByteArr(bs, char * ba, &len);
//结果：ba = “051C”; len=2

char ba[] = "051C";
ByteArr2Bitstr(char * ba, char * bs);
//结果：bs= "1010010100011100"
3 提交代码（或代码链接）和运行结果

main.c

        #include <stdio.h>
	#include <string.h>
	#include "utils.h"
	int main(){
	        int bitList[8] = { 0 };
	    int a;
	    sscanf("20191227", "%x", &a);
	    ByteArr2Bitstr(a, bitList);
	    printf("0x20191227 be changed to\n");
	    for (int i =0 ;i<32;++i)
	        printf("%i",bitList[i]);//八位长
	        printf("\n");
	    int b,n;
	    n=Bitstr2ByteArr(bitList,b);
	    printf("the data will be changed to\n");
	    printf("%x\n",n);
	}

utils.c

        #include <stdio.h>
	#include <string.h>
	#include "utils.h"
	int ByteArr2Bitstr(int ba,int * bs){
	    for (int i =0 ;i<8;++i)
	        {
	            int nTmp = (1 << i);
	            bs[7-i] = (( ba & nTmp) == nTmp )? 1 : 0;
	        }
	}
	 
	int Bitstr2ByteArr(int * bs,int ba)
	{
	    int n = 0;
	    for (int i = 0 ; i < 8;++i)
	    {
	        n += bs[7-i] * (1 << i);
	    }
	    *bs = n;
	    return n;
	}

utils.h

        #ifndef  _UTILS_H_
	#define  _UTILS_H_
	 
	int ByteArr2Bitstr(int ba,int * bs);
	int Bitstr2ByteArr(int * bs,int ba);
	#endif

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