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#yyds干货盘点# LeetCode面试题:螺旋矩阵 II

时间:2023-03-25 21:03:42浏览次数:34  
标签:nextColumn yyds 面试题 matrix int II column directionIndex row

1.简述:

给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。

 

示例 1:

输入:n = 3

输出:[[1,2,3],[8,9,4],[7,6,5]]

示例 2:

输入:n = 1

输出:[[1]]

2.代码实现:

class Solution {
    public int[][] generateMatrix(int n) {
        int maxNum = n * n;
        int curNum = 1;
        int[][] matrix = new int[n][n];
        int row = 0, column = 0;
        int[][] directions = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}}; // 右下左上
        int directionIndex = 0;
        while (curNum <= maxNum) {
            matrix[row][column] = curNum;
            curNum++;
            int nextRow = row + directions[directionIndex][0], nextColumn = column + directions[directionIndex][1];
            if (nextRow < 0 || nextRow >= n || nextColumn < 0 || nextColumn >= n || matrix[nextRow][nextColumn] != 0) {
                directionIndex = (directionIndex + 1) % 4; // 顺时针旋转至下一个方向
            }
            row = row + directions[directionIndex][0];
            column = column + directions[directionIndex][1];
        }
        return matrix;
    }
}

标签:nextColumn,yyds,面试题,matrix,int,II,column,directionIndex,row
From: https://blog.51cto.com/u_15488507/6149625

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