求数列的和
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 90450 Accepted Submission(s): 54647
Problem Description
数列的定义如下:
数列的第一项为n,以后各项为前一项的平方根,求数列的前m项的和。
Input
输入数据有多组,每组占一行,由两个整数n(n<10000)和m(m<1000)组成,n和m的含义如前所述。
Output
对于每组输入数据,输出该数列的和,每个测试实例占一行,要求精度保留2位小数。
Sample Input
81 4 2 2
Sample Output
94.73 3.41
import java.util.Scanner;
public class Main{
private static Scanner scanner;
public static void main(String[] args) {
scanner = new Scanner(System.in);
while (scanner.hasNext()) {
double n = scanner.nextInt();
int m = scanner.nextInt();// m 个
double s = n;
while (m-- > 1) {
s = s + Math.sqrt(n);
n = Math.sqrt(n);
}
System.out.printf("%.2f", s);
System.out.println();
}
}
}