B. Sum of Two Numbers

https://codeforces.com/problemset/problem/1788/B

思路

计算原数的所有位置上的digit和

得到digit和的一半

对于原数从左到右切分，前半部分digit和为half

例如：

1331

-->>

1300

0031

Code

https://codeforces.com/problemset/submission/1788/193134592

int t;
vector<int> digits;
vector<int> bdigits;
vector<int> sdigits;
 
void storedigits(int num){
    while(num){
        int r = num%10;
        
        digits.push_back(r);
 
        num /= 10;
    }
 
    reverse(digits.begin(), digits.end());
}
 
int getds(int num){
    int sum = 0;
 
    while(num){
        int r = num%10;
        sum += r;
 
        num /= 10;
    }
 
    return sum;
}
 
void split(int half){
    int dlen = digits.size();
    int sum = 0;
    REP(i, dlen){
        int one = digits[i];
 
        if (sum < half){
            if(sum + one <= half){
                bdigits.push_back(one);
                sdigits.push_back(0);
            } else {
                int bpart = half - sum;
                int spart = one - bpart;
 
                bdigits.push_back(bpart);
                sdigits.push_back(spart);
            }
        } else{
            bdigits.push_back(0);
            sdigits.push_back(one);
        }
        
        sum += one;
    }
}
 
int tonum(vector<int>& digits){
    int dlen = digits.size();
    
    int pow = 1;
    int sum = 0;
    REP(i, dlen){
        int one = digits[dlen-i-1];
        
        sum += one*pow;
        
        pow *= 10;
    }
    
    return sum;
}
 
int printdigits(vector<int>& digits){
    int dlen = digits.size();
 
    REP(i, dlen){
        int one = digits[i];
        
        cout << one << " ";
    }
    
    cout << endl;
}
 
int main()
{
    cin >> t;
 
    REP(i, t){
        int n;
 
        cin >> n;
 
        digits.clear();
        
        storedigits(n);
//        printdigits(digits);
 
        int ds = getds(n);
        int half = ds/2;
        
        bdigits.clear();
        sdigits.clear();
        
        split(half);
//        printdigits(bdigits);
//        printdigits(sdigits);
        
        int bnum = tonum(bdigits);
        int snum = tonum(sdigits);
        
        cout << bnum << " " << snum << endl;
    }
 
    return 0;
}