1、235. 二叉搜索树的最近公共祖先
class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if(root.val > p.val && root.val > q.val){
return lowestCommonAncestor(root.left, p, q);
} else if (root.val < p.val && root.val < q.val) {
return lowestCommonAncestor(root.right, p, q);
} else {
return root;
}
}
}
2、701.二叉搜索树中的插入操作
class Solution {
public TreeNode insertIntoBST(TreeNode root, int val) {
TreeNode addNode = new TreeNode(val);
if(root == null){
root = addNode;
}
if(root.val > val){
root.left = insertIntoBST(root.left, val);
}
if(root.val < val){
root.right = insertIntoBST(root.right, val);
}
return root;
}
}
3、450.删除二叉搜索树中的节点
class Solution {
public TreeNode deleteNode(TreeNode root, int key) {
if(root == null ) {
return root;
}
if(root.val == key) {
if(root.left == null){
return root.right;
} else if(root.right == null){
return root.left;
}else {
TreeNode cur = root.right;
while(cur.left != null){
cur = cur.left;
}
cur.left = root.left;
root = root.right;
return root;
}
}
if(root.val > key ) {
root.left = deleteNode(root.left, key);
}
if(root.val < key) {
root.right = deleteNode(root.right, key);
}
return root;
}
}
标签:right,TreeNode,val,day21,return,root,left
From: https://www.cnblogs.com/hzj-bolg/p/17093814.html