五、能整除某个数

# 0到1000的能整除2的数
def zheng_chu():
    ls = []
    for i in range(0, 1001):
        if i % 2 == 0:
            ls.append(i)
    return ls
a=zheng_chu()
print(a)

# 0到1000的能整除列表中所有数的数

def list_chu(*args):
    sum=[]
    for i in range(0,1001):
        for j in args:
            if i%j==0:
                if i not in sum:
                    sum.append(i)
            else:
                if i in sum:
                    sum.remove(i)
                    break
    return sum

a=[2,4,6]
print(list_chu(*a))