换根dp 模板
去到相邻的点可以根据去到的点的子树有多少个结点,来调整当前的值
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <vector>
#include <queue>
#include <array>
using namespace std;
typedef long long ll;
vector<vector<int>>gra;
vector<int>siz;
int n;
ll dfs(int now, int pre)
{
siz[now] = 1;
int ans = 1;
for(int nex : gra[now])
{
if(nex == pre) continue;
ans += dfs(nex, now);
siz[now] += siz[nex];
}
return ans;
}
int bfs(int s, ll sum)
{
queue<array<ll, 2>>q;
vector<int>vis(n + 1), tot(n + 1, 0);
q.push({s, sum});
while(q.size())
{
auto [now, val] = q.front();
q.pop();
if(vis[now]) continue;
vis[now] = 1;
tot[now] = val;
if(val > tot[s]) s = now;
for(int nex : gra[now])
{
if(vis[nex]) continue;
q.push({nex, val - siz[nex] - siz[nex] + n});
}
}
return s;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> n;
gra.resize(n + 1);
siz.resize(n + 1);
for(int i=1; i<n; i++)
{
int a, b;
cin >> a >> b;
gra[a].push_back(b);
gra[b].push_back(a);
}
ll sum = dfs(1, 1);
int rt = bfs(1, sum);
cout << rt << endl;
return 0;
}
标签:include,洛谷,int,siz,Station,nex,gra,now,P3478
From: https://www.cnblogs.com/dgsvygd/p/16875178.html