首页 > 其他分享 >PAT (Advanced Level) Practise 1031 Hello World for U (20)

PAT (Advanced Level) Practise 1031 Hello World for U (20)

时间:2022-11-09 18:34:18浏览次数:42  
标签:Practise PAT string Level int characters printf line include


1031. Hello World for U (20)


时间限制



400 ms



内存限制



65536 kB



代码长度限制



16000 B



判题程序



Standard



作者



CHEN, Yue


Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:



h d e l l r lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n

1characters, then left to right along the bottom line with n

2 characters, and finally bottom-up along the vertical line with n

3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n

1 = n

3 = max { k| k <= n

2 for all 3 <= n

2 <= N } with n

1 + n

2 + n

3 - 2 = N.


Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.


Sample Input:


helloworld!


Sample Output:


h ! e d l l lowor



直接算出有多少行多少列就好了



#include<cstdio>
#include<cstring>
#include<vector>
#include<queue>
#include<functional>
#include<algorithm>
using namespace std;
typedef long long LL;
const int maxn=1e5+10;
const int mod=1e9+7;
int n,m;
char s[maxn];

int main()
{
scanf("%s",s);
n=(strlen(s)+2)/3;
m=strlen(s)+2-2*n;
for (int i=0;i<n;i++)
{
printf("%c",s[i]);
for (int j=1;j<m-1;j++)
{
if (i<n-1) printf(" ");
else printf("%c",s[i+j]);
}
printf("%c\n",s[strlen(s)-i-1]);
}
return 0;
}



标签:Practise,PAT,string,Level,int,characters,printf,line,include
From: https://blog.51cto.com/u_15870896/5837725

相关文章