332.重新安排行程(可跳过)
https://programmercarl.com/0332.重新安排行程.html
有难度,涉及到图,有些用例会超时
/**
* @param {string[][]} tickets
* @return {string[]}
*/
var findItinerary = function(tickets) {
const res = ['JFK'];
const map = {};
for (let [from, to] of tickets) {
if (!map[from]) {
map[from] = [];
}
map[from].push(to);
}
for (let key in map) {
map[key].sort();
}
const backtraversing = ()=>{
if (res.length === tickets.length+1) {
return true;
}
if (!map[res[res.length-1]] || !map[res[res.length-1]].length) {
return false;
}
for (let i=0;i<map[res[res.length-1]].length;i++) {
let city = map[res[res.length-1]][i];
map[res[res.length-1]].splice(i,1);
res.push(city);
if (backtraversing()) {
return true;
}
res.pop();
map[res[res.length-1]].splice(i,0,city);
}
}
backtraversing();
return res;
};
能想到思路,但具体的实现有些写不出来
function isVaild(arr, row, col) {
for (let i = 0; i< row; i++) {
if (arr[i][col] === 'Q') {
return false;
}
}
for (let i=row-1,j=col-1;i>=0&&j>=0;i--,j--) {
if (arr[i][j]==='Q') {
return false;
}
}
for (let i=row-1,j=col+1;j<arr.length&&i>=0;i--,j++) {
if (arr[i][j]==='Q') {
return false;
}
}
return true;
}
/**
* @param {number} n
* @return {string[][]}
*/
var solveNQueens = function(n) {
const res = [];
const path = [];
const matrix = new Array(n).fill(0).map(()=>new Array(n).fill('.'));
const backtraversing = (n, row, matrix) => {
if (n === row) {
res.push([...path]);
return;
}
for (let i=0;i<n;i++) {
if (!isVaild(matrix, row, i)) {
continue;
}
matrix[row][i] = 'Q';
path.push(matrix[row].join(''));
backtraversing(n, row+1, matrix);
matrix[row][i]='.';
path.pop();
}
}
backtraversing(n, 0, matrix);
return res;
};
function isValid(row, col, val, board) {
let len = board.length
// 行不能重复
for(let i = 0; i < len; i++) {
if(board[row][i] === val) {
return false
}
}
// 列不能重复
for(let i = 0; i < len; i++) {
if(board[i][col] === val) {
return false
}
}
let startRow = Math.floor(row / 3) * 3
let startCol = Math.floor(col / 3) * 3
for(let i = startRow; i < startRow + 3; i++) {
for(let j = startCol; j < startCol + 3; j++) {
if(board[i][j] === val) {
return false
}
}
}
return true
}
/**
* @param {character[][]} board
* @return {void} Do not return anything, modify board in-place instead.
*/
var solveSudoku = function(board) {
const back = (board) => {
let len = board.length;
for(let row = 0;row<len;row++) {
for (let col =0;col<len;col++) {
if (board[row][col]!=='.') continue;
for (let k=1;k<=9;k++) {
let strNum = k+'';
if (!isValid(row,col,strNum,board)) continue;
board[row][col] = strNum;
if (back(board)) return true;
board[row][col] = '.';
}
return false;
}
}
return true;
}
back(board);
return board;
};
总结
https://programmercarl.com/回溯总结.html