1 #方法一：这是最先想到的
2 s = [[1,2,3], [4,5,6], [7,8,9]]
3 n = int(input())
4
5 r = []
6 for i in s:
7 a = [] #这个很重要，每次要清空
8 for j in i:
9 a.append(j * n)
10 r.append(a)
11
12 print(r)
13
14
15
16
17
18
19 #方法二：参考网友解法修改的
20 s = [[1,2,3], [4,5,6], [7,8,9]]
21 n = int(input())
22
23 print("原始数据：", s)
24 for i in range(len(s)):
25 for j in range(len(s[0])):
26 s[i][j] *= n
27
28 print(s)
标签：python,矩阵,len,int,相乘,print,input,append From： https://www.cnblogs.com/bravesunforever/p/17627031.html