UVA210 双端队列模拟并行程序

#include<iostream>
#include<algorithm>
#include<string>
#include<sstream>
#include<vector>
#include<queue>
#include<cstring>
using namespace std;
const int maxn = 10001;
//uva210:题意 模拟n个程序的并行执行，有赋值，打印，lock，unlock，end五种。
//输入n,t1,t2,t3,t4,t5,Q;

int n, t1, t2, t3, t4, t5, Q;
deque<int>wait;//等待队列
deque<int>stop;//阻止队列
int num[maxn];

int main(void)
{
    cin >> n >> t1 >> t2 >> t3 >> t4 >> t5 >> Q;
    string s;
    int id = 0;
    while(getline(cin,s))
    {
        char c = s[2];
        while (Q) {
            if (c == '='&&Q-t1>=0)
            {
                int ch = s[1];
                num[ch-'a']==(int)s
            }
        }
        
    }
    
    return 0;
}
#include<iostream>
#include<stack>
#include<deque>
#include<vector>

int n, t1, t2, t3, t4, t5, Q;
deque<int>wait;//阻塞队列
deque<int>ready;//等待队列
vector<string> str;//存储执行语句
int var[101];//存储变量
int block;

void run(int i)//在ready队列中执行到第i个（str下标）的命令
{
    int time = Q;
    char c;
    while(time>0)
    {
        c = str[i][2];
        if(c=='=')
        {
            time -= t1;
            //赋值范围为0-99
            var[str[i][0] - 'a'] = isdigit(str[i][4]) ? (int)str[i][4] * 10 + str[i][5] : (int)str[i][5];
        }
        else if(c=='i')
        {
            time -= t2;
            cout << i<<' ' << var[str[i][6]] << endl;
        }
        else if(c=='c')
        {
            
            if(!ready.empty()&&block)
            {
                wait.push_back(i);
                return;
            }
            time -= t3;
            block = 1;
        }
        else if(c=='l')
        {
            if(!wait.empty())
            {
                ready.push_back(wait.front());
                wait.pop_front();
            }
            block = 0;
            time -= t4;
        }
        else 
        {
            time -= t5;
            return;
        }
    }
}

int main()
{
    //输入
    cin >> n >> t1 >> t2 >> t3 >> t4 >> t5 >> Q;
    string s;
    for(int i=1;i<=n;i++)
    {
        while(getline(cin,s))
        {
            str[i] = s;
            ready.push_front(i);//str的下标传入到ready中，之后处理
        }
    }
    //处理
    while (!ready.empty()) {
        int x = ready.front();
        ready.pop_front();
        //    cout<<x<<" ";
        run(x); // 依次执行准备列队的队头 
    }
    
}