首页 > 编程语言 >C++ 学习笔记

C++ 学习笔记

时间:2022-09-02 19:46:31浏览次数:51  
标签:ch return int 笔记 学习 C++ now root vec

\[\texttt{Tips for C++ Programming} \]

0.快读快输

inline char gc() { static char buf[1000000], *p1 = buf, *p2 = buf; return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1000000, stdin), p1 == p2) ? EOF : *p1++; }
inline int read() { char c = gc(); int res = 0, f = 1; for (; c < '0' || c > '9'; c = gc()) if (c == '-') f = -1; for (; c >= '0' && c <= '9'; c = gc()) res = res * 10 + c - '0'; return res * f; }
inline void write(int x) { static int sta[50], top = 0; if (x < 0) putchar('-'), x = -x; do { sta[ top++ ] = x % 10; x /= 10; } while (x); while (top)  putchar(sta[ --top ] + 48); }
inline void writesp(int x) { write(x); putchar(' '); }
inline void writeln(int x) { write(x); putchar('\n'); }

1.for 循环宏定义

#define UP(l, i, a, b) for (l i = (l)(a); i <= (l)(b); ++i)
#define DOWN(l, i, a, b) for (l i = (l)(a); i >= (l)(b); --i)

2.快读快输(听说 \(n \geq 5\times 10^8\) 时更快?)

#include <cstdio>
#include <sys/mman.h>
#include <sys/stat.h>

char *p;
inline int read() {
    int x = 0, r = 1;
    while (*p < 48) {if (*p == '-') r = -r; p++;}
    while (*p >= 48) x = (x << 3) + (x << 1) + *p - 48, p++;
    return x * r;
}

inline void write(int x) {
    char s[20]; int c = 0;
    do {s[ c++ ] = x % 10; x /= 10;} while(x);
    for (int i = c - 1; i >= 0; --i) putchar_unlocked(s[i] + 48);
    putchar('\n');
}

inline void init() {
    struct stat in;
    fstat(0, &in);
    p = (char*)mmap(0, in.st_size, 1, 2, 0, 0);
}

3.高精度模板

class BigInteger {
	private:
		std :: vector <int> vec;
	public:
		BigInteger() {
			vec.clear();
		}
		BigInteger* operator = (int n) {
			vec.clear();
			while (n) {
				vec.emplace_back(n % 10);
				n /= 10;
			}
			return this;
		}
		BigInteger* operator = (std :: string s) {
			int len = s.length();
			reverse(s.begin(), s.begin() + len);
			vec.clear();
			for (int i = 0; i < len; i++) vec.emplace_back(s[i] - '0');
			return this;
		}
		BigInteger operator + (const BigInteger A) {
			BigInteger C;
			C.vec.emplace_back(0);
			for (int i = 0; i < vec.size() || i < A.vec.size(); i++) {
				int a = (i < vec.size() ? vec[i] : 0);
				int b = (i < A.vec.size() ? A.vec[i] : 0);
				C.vec[i] += a + b;
				C.vec.emplace_back(C.vec[i] / 10);
				C.vec[i] %= 10;
			}
			while (C.vec.back() == 0) {
				C.vec.pop_back();
				if (C.vec.empty()) break;
			}
			return C;
		}
		BigInteger operator - (const BigInteger A) {
			std :: vector <int> temp;
			for (int i = 0; i < vec.size(); i++) temp.emplace_back(vec[i]);
			BigInteger C;
			for (int i = 0; i < vec.size() || i < A.vec.size(); i++) {
				int a = (i < vec.size() ? vec[i] : 0);
				int b = (i < A.vec.size() ? A.vec[i] : 0);
				if (a >= b) C.vec.emplace_back(a - b);
				else {
					while (a < b) {
						a += 10; vec[ i + 1 ]--;
					}
					C.vec.emplace_back(a - b);
				}
			}
			vec.swap(temp);
			while (C.vec.back() == 0) {
				C.vec.pop_back();
				if (C.vec.empty()) break;
			}
			return C;
		}
		struct complex {
			double real, imaginary;
			complex() = default;
			complex(const double Re = 0.0, const double Im = 0.0) : real(Re), imaginary(Im) {}
			complex operator + (const complex &A) {
				return complex(real + A.real, imaginary + A.imaginary);
			}
			complex operator - (const complex &A) {
				return complex(real - A.real, imaginary - A.imaginary);
			}
			complex operator * (const complex &A) {
				return complex(real * A.real - imaginary * A.imaginary, imaginary * A.real + real * A.imaginary);
			}
		};
		void fft(std :: vector <complex> &a, int inv, std :: vector <int> rev, int limit) {
			const double pi = acos(-1.0);
			for (int i = 0; i < limit; i++)
				if (i < rev[i]) std :: swap(a[i], a[ rev[i] ]);
			for (int mid = 1; mid < limit; mid <<= 1) {
				complex Wn = complex(cos(pi / mid), inv * sin(pi / mid));
				for (int L = 0; L < limit; L += (mid << 1)) {
					complex w = complex(1, 0);
					for (int j = 0; j < mid; j++, w = w * Wn) {
						complex w1 = a[ L + j ], w2 = a[ L + j + mid ];
						a[ L + j ] = w1 + w2 * w;
						a[ L + j + mid ] = w1 - w2 * w;
					}
				}
			}
		}
		BigInteger operator * (const BigInteger A) {
			int limit = 1, l = 0;
			std :: vector <int> rev;
			std :: vector <complex> a, b;
			rev.clear(); rev.emplace_back(0);
			int len = vec.size() + A.vec.size() + 1;
			for (; limit <= len; limit <<= 1, l++);
			for (int i = 1; i < limit; i++)
				rev.emplace_back((rev[ i >> 1 ] >> 1) | ((i & 1) << (l - 1)));
			for (int i = 0; i < limit; i++) {
				if (i < vec.size()) a.emplace_back(complex(vec[i], 0)); else a.emplace_back(complex(0, 0));
				if (i < A.vec.size()) b.emplace_back(complex(A.vec[i], 0)); else b.emplace_back(complex(0, 0));
			}
			fft(a, 1, rev, limit); fft(b, 1, rev, limit);
			for (int i = 0; i < limit; i++) a[i] = a[i] * b[i];
			fft(a, -1, rev, limit);
			BigInteger C;
			for (int i = 0; i <= vec.size() + A.vec.size(); i++) {
				C.vec.emplace_back(std :: round(a[i].real / limit));
			}
			for (int i = 0; i < C.vec.size(); i++) {
				if (i == C.vec.size() - 1) {
					C.vec.emplace_back(C.vec[i] / 10);
					C.vec[i] %= 10;
					break;
				}
				else {
					C.vec[ i + 1 ] += C.vec[i] / 10;
					C.vec[i] %= 10;
				}
			}
			while (C.vec.back() == 0) {
				C.vec.pop_back();
				if (C.vec.empty()) break;
			}
			return C;
		}
		BigInteger operator / (const int p) {
			BigInteger C;
			std :: reverse(vec.begin(), vec.end());
			long long x = 0;
			for (int i = 0; i < vec.size(); i++) {
				x = x * 10 + vec[i];
				C.vec.emplace_back(x / p);
				x %= p;
			}
			std :: reverse(vec.begin(), vec.end());
			std :: reverse(C.vec.begin(), C.vec.end());
			while (C.vec.back() == 0) C.vec.pop_back();
			return C;
		}
		int operator % (const int p) {
			BigInteger C;
			std :: reverse(vec.begin(), vec.end());
			int x = 0;
			for (int i = 0; i < vec.size(); i++) {
				x = (1ll * x * 10 + vec[i]) % p;
			}
			std :: reverse(vec.begin(), vec.end());
			return x;
		}
		bool operator < (const BigInteger A) {
			if (vec.size() < A.vec.size()) return true;
			else if (vec.size() > A.vec.size()) return false;
			for (int i = 0; i < vec.size(); i++) {
				if (vec[i] < A.vec[i]) return true;
				else if (vec[i] > A.vec[i]) return false;
			}
			return false;
		}
		bool operator == (const BigInteger A) {
			if (vec.size() != A.vec.size()) return false;
			for (int i = 0; i < vec.size(); i++) {
				if (vec[i] != A.vec[i]) return false;
			}
			return true;
		}
		bool operator > (const BigInteger A) {
			if (vec.size() > A.vec.size()) return true;
			else if (vec.size() < A.vec.size()) return false;
			for (int i = 0; i < vec.size(); i++) {
				if (vec[i] > A.vec[i]) return true;
				else if (vec[i] < A.vec[i]) return false;
			}
			return false;
		}
		bool operator <= (const BigInteger A) {
			return (*this) < A || (*this) == A;
		}
		bool operator >= (const BigInteger A) {
			return (*this) > A || (*this) == A;
		}
		void write() {
			if (vec.empty()) std :: cout << 0;
			for (int i = vec.size() - 1; ~i; i--) std :: cout << vec[i];
		}
		void writeln() {
			write(); std :: cout << '\n';
		}
		void writesp() {
			write(); std :: cout << ' ';
		}
};

4.Splay 模板

struct Splay {
	struct Node {
		int val, cnt, siz;
		Node *fa, *ch[2];
		Node() {
			val = cnt = siz = 0;
			fa = ch[0] = ch[1] = NULL;
		}
	};
	
	Node *root = NULL;
	
	inline Node *newnode() {
		return new Node;
	}
	
	inline void Clear(Node *x) {
		x -> val = x -> cnt = x -> siz = 0;
		x -> fa = x -> ch[0] = x -> ch[1] = NULL;
	}
	
	inline void update(Node *x) {
		if (x -> ch[0] == NULL && x -> ch[1] == NULL) x -> siz = x -> cnt;
		else if (x -> ch[0] == NULL) x -> siz = x -> ch[1] -> siz + x -> cnt;
		else if (x -> ch[1] == NULL) x -> siz = x -> ch[0] -> siz + x -> cnt;
		else x -> siz = x -> ch[0] -> siz + x -> ch[1] -> siz + x -> cnt;
	}
	
	inline int id(Node *x) {
		if (x -> fa != NULL) return x -> fa -> ch[1] == x;
		else return -1;
	}
	
	inline void rotate(Node *x) {
		Node *father = x -> fa, *grandfather = father -> fa;
		int it = id(x), it2 = id(father);
		father -> ch[it] = x -> ch[ it ^ 1 ];
		if (x -> ch[ it ^ 1 ] != NULL) x -> ch[ it ^ 1 ] -> fa = father;
		father -> fa = x;
		x -> ch[ it ^ 1 ] = father;
		if (grandfather != NULL) grandfather -> ch[it2] = x;
		x -> fa = grandfather;
		update(father);
		update(x);
	}
	
	inline void splay(Node *x) {
		while (x -> fa != NULL) {
			if (x -> fa == root) {
				rotate(x);
			}
			else if (id(x) == id(x -> fa)) {
				rotate(x -> fa);
				rotate(x);
			}
			else {
				rotate(x);
				rotate(x);
			}
		}
		root = x;
	}
	
	inline void insert(int val) {
		if (root == NULL) {
			root = newnode();
			root -> val = val;
			root -> cnt = 1;
			update(root);
		}
		else {
			Node *now = root, *father = now -> fa;
			while (true) {
				if (now -> val == val) {
					now -> cnt++;
					update(now);
					break;
				}
				else if (val < now -> val) {
					father = now;
					now = now -> ch[0];
				}
				else {
					father = now;
					now = now -> ch[1];
				}
				if (now == NULL) {
					now = newnode();
					father -> ch[ val > father -> val ] = now;
					now -> fa = father;
					now -> val = val;
					now -> cnt = 1;
					update(now);
					update(father);
					break;
				}
			}
			splay(now);
		}
	}
	
	inline void del(int val) {
		if (root -> ch[0] == NULL && root -> ch[1] == NULL && root -> cnt == 1) {
			Clear(root);
			root = NULL;
			return ;
		}
		Node *now = root;
		while (true) {
			if (val < now -> val) {
				now = now -> ch[0];
			}
			else if (val > now -> val) {
				now = now -> ch[1];
			}
			else break;
		}
		splay(now);
		if (root -> cnt > 1) {
			root -> cnt--;
			update(root);
		}
		else {
			Node *left = root -> ch[0], *right = root -> ch[1];
			Clear(root);
			if (left == NULL) root = right, root -> fa = NULL;
			else if (right == NULL) root = left, root -> fa = NULL;
			else {
				right -> fa = NULL;
				root = left;
				root -> fa = NULL;
				Node *now = root;
				while (now -> ch[1] != NULL) now = now -> ch[1];
				splay(now);
				root -> ch[1] = right;
				right -> fa = root;
				update(root);
			}
		}
	}
		
	inline int Rank(int val) {
		Node *now = root;
		while (true) {
			if (val < now -> val) now = now -> ch[0];
			else if (val > now -> val) now = now -> ch[1];
			else break;
		}
		splay(now);
		return (now -> ch[0] != NULL ? now -> ch[0] -> siz : 0) + 1;
	}
	
	inline int kth(int k) {
		int ans = 0;
		Node *now = root;
		while (true) {
			int left = 0;
			if (now -> ch[0] != NULL) left = now -> ch[0] -> siz;
			if (k <= left) {
				now = now -> ch[0];
			}
			else if (k <= left + now -> cnt) {
				ans = now -> val;
				break;
			}
			else {
				k -= left + now -> cnt;
				now = now -> ch[1];
			}
		}
		splay(now);
		return ans;
	}
	
	inline int prec() {
		Node *now = root -> ch[0];
		if (now == NULL) return -inf;
		while (now -> ch[1] != NULL) now = now -> ch[1];
		return now -> val;
	}
	
	inline int succ() {
		Node *now = root -> ch[1];
		if (now == NULL) return inf;
		while (now -> ch[0] != NULL) now = now -> ch[0];
		return now -> val;
	}
};

\[\texttt{To be continued...} \]

标签:ch,return,int,笔记,学习,C++,now,root,vec
From: https://www.cnblogs.com/FidoPuppy/p/16651019.html

相关文章

  • 经典算法学习-计算汉明权重 SWAR(SIMD within a register)
    计算汉明权重算法SWAR(SIMDwithinaregister)参考文章:[1]简书:计算汉明权重的SWAR(SIMDwithinaRegister)算法https://www.jianshu.com/p/b0db1f072a66[2]维基百科:S......
  • 2022-09-02 第四小组 王星苹 学习笔记
    学习心得axios对原生ajax的一个封装。学习总结ES6语法。Promise语法。 *axios发送get请求,*请求中如果有参数,还是一个默认的以文档里的形式发送,和之前的任何一......
  • C语言学习笔记
    C语言学习笔记  预处理#include#include指令可以将另一个源文件的全部内容包含进来#include"stdio.h"#include<stdio.h>用尖括号时,C库函数头文件所在......
  • 9/2 开始数学建模的学习
    9/2日18:31下午进行了2小时数学建模的学习,晚上进行大数据与微积分的学习,敲代码自然是没时间了...大学真的好忙,就是那种要想认真学点东西你就会发现时间根本不够用的那种......
  • Markdown学习
    Markdown学习标题三级标题四级标题 字体Hello,World!Hello,World!Hello,World!Hello,World! 引用java 分割线 图片 超链接点击跳转 列表A......
  • 2022.9.2 - ts笔记
    TypeScript中的代码清道夫:非空断言操作符value:{type!:Array,required:true},类型别名及导入导出,对数组内的对象做限制//util/type.d.ts//......
  • 2022-2023-1-20221405《计算机基础与程序设计》第1周学习总结
    作业信息2022-2023-1-计算机基础与程序设计2022-2023-1计算机基础与程序设计第一周作业学习目标快速浏览教材并提问作业正文https://www.cnblogs.com/lengyu1231/p/1......
  • 道长的算法笔记:数论基础汇总
    质数判定与筛选给定一个正整数\(N\),如果存在一个数\(T\),T满足\((2\leqT\leqN-1)\)则称\(N\)是一个合数,如果不存在这样这样的因数\(T\),则称\(N\)质数。简单......
  • java学习笔记018 反射
    1.java.lang.Class获取Class对象的四种方式//1Classclazz1=Person.class;//2Personp=newPerson();Classclazz2=p.getClass();//3 用得多Classclazz3=......
  • 2022-2023-1 20221302《计算机基础与程序设计》第1周学习总结
    作业信息班级:https://edu.cnblogs.com/campus/besti/2022-2023-1-CFAP作业要求:|https://www.cnblogs.com/rocedu/p/9577842.html#WEEK01|作业目标:快速浏览一遍教材计算机......