c++多线程
多线程其实非常简单
多线程是多任务处理的一种特殊形式,多任务处理允许让电脑同时运行两个或两个以上的程序。一般情况下,两种类型的多任务处理:基于进程和基于线程。
创建线程
#include <pthread.h>
pthread_create (thread, attr, start_routine, arg)
//创建一个 POSIX 线程
/*
thread 指向线程标识符指针
attr 一个不透明的属性对象,可以被用来设置线程属性。您可以指定线程属性对象,也可以使用默认值 NULL
start_routine 线程运行函数起始地址,一旦线程被创建就会执行
arg 运行函数的参数。它必须通过把引用作为指针强制转换为 void 类型进行传递。如果没有传递参数,则使用 NULL
*/
终止线程
#include <pthread.h>
pthread_exit (status)
//终止一个 POSIX 线程
/*
在这里,pthread_exit 用于显式地退出一个线程。通常情况下,pthread_exit() 函数是在线程完成工作后无需继续存在时被调用。
如果 main() 是在它所创建的线程之前结束,并通过 pthread_exit() 退出,那么其他线程将继续执行。否则,它们将在 main() 结束时自动被终止。
*/
实例
#include <iostream>
#include <cstdlib>
#include <pthread.h>
using namespace std;
#define NUM_THREADS 5
void *PrintHello(void *threadid)
{
int tid = *((int*)threadid);
cout << "线程ID, " << tid << endl;
pthread_exit(NULL);
}
int main ()
{
pthread_t threads[NUM_THREADS];
int indexes[NUM_THREADS];
int rc;
int i;
for( i=0; i < NUM_THREADS; i++ ){
cout << " 创建线程, " << i << endl;
indexes[i] = i;
rc = pthread_create(&threads[i], NULL, PrintHello, (void *)&(indexes[i]));
if (rc){
cout << "无法创建线程," << rc << endl;
exit(-1);
}
}
pthread_exit(NULL);
}
向线程传递参数
#include <iostream>
#include <cstdlib>
#include <pthread.h>
using namespace std;
#define NUM_THREADS 5
struct thread_data{
int thread_id;
char *message;
};
void *PrintHello(void *threadarg)
{
struct thread_data *my_data;
my_data = (struct thread_data *) threadarg;
cout << "Thread ID : " << my_data->thread_id ;
cout << " Message : " << my_data->message << endl;
pthread_exit(NULL);
}
int main ()
{
pthread_t threads[NUM_THREADS];
struct thread_data td[NUM_THREADS];
int rc;
int i;
for( i=0; i < NUM_THREADS; i++ ){
cout <<"main() : creating thread, " << i << endl;
td[i].thread_id = i;
td[i].message = (char*)"This is message";
rc = pthread_create(&threads[i], NULL,
PrintHello, (void *)&td[i]);
if (rc){
cout << "Error:unable to create thread," << rc << endl;
exit(-1);
}
}
pthread_exit(NULL);
}
这个实例演示了如何通过结构传递多个参数。
连接和分离线程
//我们可以使用以下两个函数来连接或分离线程
pthread_join (threadid, status)
pthread_detach (threadid)
这个实例演示了如何使用 pthread_join() 函数来等待线程的完成。
#include <iostream>
#include <cstdlib>
#include <pthread.h>
#include <unistd.h>
using namespace std;
#define NUM_THREADS 5
void *wait(void *t)
{
int i;
long tid;
tid = (long)t;
sleep(1);
cout << "Sleeping in thread " << endl;
cout << "Thread with id : " << tid << " ...exiting " << endl;
pthread_exit(NULL);
}
int main ()
{
int rc;
int i;
pthread_t threads[NUM_THREADS];
pthread_attr_t attr;
void *status;
pthread_attr_init(&attr);
pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_JOINABLE);
for( i=0; i < NUM_THREADS; i++ ){
cout << "main() : creating thread, " << i << endl;
rc = pthread_create(&threads[i], NULL, wait, (void *)&i );
if (rc){
cout << "Error:unable to create thread," << rc << endl;
exit(-1);
}
}
pthread_attr_destroy(&attr);
for( i=0; i < NUM_THREADS; i++ ){
rc = pthread_join(threads[i], &status);
if (rc){
cout << "Error:unable to join," << rc << endl;
exit(-1);
}
cout << "Main: completed thread id :" << i ;
cout << " exiting with status :" << status << endl;
}
cout << "Main: program exiting." << endl;
pthread_exit(NULL);
}
c++11后的标准的线程库
#include <iostream>
#include <thread>
std::thread::id main_thread_id = std::this_thread::get_id();
void hello()
{
std::cout << "Hello Concurrent World\n";
if (main_thread_id == std::this_thread::get_id())
std::cout << "This is the main thread.\n";
else
std::cout << "This is not the main thread.\n";
}
void pause_thread(int n) {
std::this_thread::sleep_for(std::chrono::seconds(n));
std::cout << "pause of " << n << " seconds ended\n";
}
int main() {
std::thread t(hello);
std::cout << t.hardware_concurrency() << std::endl;
std::cout << "native_handle " << t.native_handle() << std::endl;
t.join();
std::thread a(hello);
a.detach();
std::thread threads[5];
std::cout << "Spawning 5 threads...\n";
for (int i = 0; i < 5; ++i)
threads[i] = std::thread(pause_thread, i + 1);
std::cout << "完成生成线程,现在正等待加入:\n";
for (auto &thread : threads)
thread.join();
std::cout << "All threads joined!\n";
}
标签:std,多线程,thread,void,C++,线程,pthread,include
From: https://www.cnblogs.com/demc/p/16905702.html