*/
* Copyright (c) 2016,烟台大学计算机与控制工程学院
* All rights reserved.
* 文件名:text.cpp
* 作者:常轩
* 微信公众号:Worldhello
* 完成日期:2016年6月8日
* 版本号:V1.0
* 问题描述:
* 程序输入:无
* 程序输出:见运行结果
*/
#include <string>
#include <set>
#include <iterator>
#include <iostream>
using namespace std;
int main()
{
set <string> strset;
strset.insert("cantaloupes");
strset.insert("grapes");
strset.insert("apple");
strset.insert("orange");
strset.insert("banana");
strset.insert("grapes");
copy(strset.begin(), strset.end(), ostream_iterator<string>(cout, " "));
cout << endl;
return 0;
}
#include <functional>
#include <numeric>
#include <vector>
#include <iostream>
using namespace std;
int main()
{
vector<int> v(5);
for (int i = 0; i < 5; i++)
v[i] = i + 1;
int sum = accumulate(v.begin(), v.end(), 0);
cout << "Sum of values == " << sum << endl;
int product = accumulate(v.begin(), v.end(), 1, multiplies<long>());
cout << "Product of values == " << product << endl;
return 0;
}
#include <algorithm>
#include <functional>
#include <vector>
#include <iostream>
#include <numeric>
#include <iterator>
using namespace std;
int main()
{
int a[] = {1,4,7,2,5,8};
int b[] = {1,2,3,3,2,1};
const int ASZ = sizeof a / sizeof a[0];
const int BSZ = sizeof b / sizeof b[0];
ostream_iterator<int> out(cout," ");
copy(a, a + ASZ, out);
cout<<endl;
copy(b, b + BSZ, out);
cout<<endl;
int r = accumulate(a, a + ASZ, 0);
cout << "accumulate 1: " << r << endl;
// Should produce the same result:
r = accumulate(b, b + BSZ, 0, plus<int>());
cout << "accumulate 2: " << r << endl;
r = inner_product(a, a + ASZ, b, 0);
// 或 r = inner_product(a, a + ASZ, b, 0, plus<int>(), multiplies<int>());
cout << "inner_product : " << r << endl;
int* it = partial_sum(a, a + ASZ, b);
// 或 int* it = partial_sum(a, a + ASZ, b, plus<int>());
copy(b, it, out);
cout<<endl;
it = adjacent_difference(a, a + ASZ, b);
// 或 it = adjacent_difference(a, a + ASZ, b, minus<int>());
copy(b, it, out);
cout<<endl;
return 0;
}