validValues

2024-12-05对`a == ('1'||'2'||'3') ? false : true`写法进行改进，写出你优化后的方法
Theoriginalexpressiona==('1'||'2'||'3')?false:trueisflawedanddoesn'tworkasintended.The('1'||'2'||'3')partwillalwaysevaluateto'1'becauseofhowthe||(OR