950
  • 2024-06-07Codeforces Round 950 (Div. 3)G. Yasya and the Mysterious Tree(字典树处理区间异或值)
    Problem-G-Codeforces存个字典树板子。1#include<bits/stdc++.h>23usingi64=longlong;45constexprintN=1E7;67inttrie[N][2];8intcnt[N][2];910inttot=0;11intnewNode(){12intx=++tot;13trie
  • 2024-06-07Codeforces Round 950 (Div. 3) A B C D E
    A.ProblemGeneratortimelimitpertest:1secondmemorylimitpertest:256megabytesinput:standardinputoutput:standardoutputVladisplanningtoholdm
  • 2024-06-05GCD-sequence(Round 950)
    #include<bits/stdc++.h>#defineendl'\n'usingll=longlong;typedefunsignedlonglongull;usingnamespacestd;voidGordenGhost();signedmain(){#ifdefGordenfreopen("in.txt","rt",stdin);freopen
  • 2024-06-04Codeforces Round 950 (Div. 3)个人题解(A~F1)
    CodeforcesRound950(Div.3)个人题解(A~F1)题解火车头#define_CRT_SECURE_NO_WARNINGS1#include<iostream>#include<vector>#include<algorithm>#include<set>#include<unordered_map>#include<cstring>#include<cstdio&
  • 2024-06-04常春藤算法(Ivy algorithm,LVYA)的复杂城市地形下无人机避障三维航迹规划,可以修改障碍物及起始点(Matlab代码)
    一、部分代码常春藤算法(Ivyalgorithm,LVYA)是MojtabaGhasemi等人于2024年提出智能优化算法。该算法模拟了常春藤植物的生长模式,通过协调有序的种群增长以及常春藤植物的扩散和演化来实现。常春藤植物的生长速率是通过微分方程和数据密集型实验过程建模的。该算法利用附近常春
  • 2024-06-04Codeforces Round 950 (Div. 3)
    https://codeforces.com/contest/1980A.ProblemGenerator题意:Thereisgoingtobemroundsnextmouth,eachofthemonthshouldbeconsistof"ABCDEFG",countthenumebrofalphabetweshouldaddtosatisfythisrequirementunderagivingsequenc
  • 2023-11-22[950] Python RegEx (re library)
    ref:PythonRegExARegEx,orRegularExpression,isasequenceofcharactersthatformsasearchpattern.RegExcanbeusedtocheckifastringcontainsthespecifiedsearchpattern.RegExModulePythonhasabuilt-inpackagecalled re,whichcanbeu
  • 2023-08-08扶植版做出拓展版950通栏轮播效果无缝连接
       一、左侧栏和右侧栏各添加一个自定义区   二、将如下代码分别复制到两个自定义区的源码编辑区内:   1、右侧自定义区代码<DIVclass="slider-promoJ_SliderJ_TWidgettb-slide"style="RIGHT:200px;WIDTH:950px;HEIGHT:450px"data-widget-type="Slide"da
  • 2023-07-20950. Reveal Cards In Increasing Order (Medium)
    Description950.RevealCardsInIncreasingOrder(Medium)Youaregivenanintegerarraydeck.Thereisadeckofcardswhereeverycardhasauniqueinteger.Theintegerontheithcardisdeck[i].Youcanorderthedeckinanyorderyouwant.Initially
  • 2023-07-20950. 按递增顺序显示卡牌 (Medium)
    问题描述950.按递增顺序显示卡牌(Medium)牌组中的每张卡牌都对应有一个唯一的整数。你可以按你想要的顺序对这套卡片进行排序。最初,这些卡牌在牌组里是正面朝下的(即,未显示状态)。现在,重复执行以下步骤,直到显示所有卡牌为止:从牌组顶部抽一张牌,显示它,然后将其从牌组中移出。