如何解决 TypeError：列表索引必须是整数或切片，而不是 str

我想建造一个刮刀。我写了这段代码，但它不断出错。如果有人可以提供帮助，我将不胜感激。

def fetch_json(api_link, timeout=10):
    try:
        response = requests.get(api_link, timeout=timeout)
        if response.status_code == 200:
            return response.json()
        else:
            print(f"Failed to fetch data from API for link: {api_link}")
            return None
    except requests.exceptions.Timeout:
        print(f"Timeout occurred while fetching data for link: {api_link}. Skipping...")
        return None
    except requests.exceptions.RequestException as e:
        print(f"Error occurred while fetching data for link {api_link}: {e}")
        return None

api_link = "https://apiv2.cricket.com.au/web/players/list?isActive=1&teamId=&jsconfig=eccn%3Atrue&format=json"

player_data= fetch_json(api_link)

name = []

if player_data:
    players = player_data['players']
    for player in players:
        id = "".join(players['id'])
        displayname = "".join(players['displayname'])
        name.append({
            "id" : player.get("id"),
            "displayname" : player.get("displayname")
        })
    print(f"Player Name Retrived")
    
player_name = pd.DataFrame(name)

它在 id 列上显示错误，我似乎无法解决这个问题。

错误出现在这两行中：

        id = "".join(players['id'])
        displayname = "".join(players['displayname'])

你正在迭代 players 列表，所以每个 player 已经是字典了。你不需要用 players['id'] 访问 id ，直接使用 player['id'] 即可。另外， join 方法用于将字符串列表连接成一个字符串，但 player['id'] 和 player['displayname'] 应该已经是字符串了，所以不需要使用 join 。

将这两行代码改为：

        id = player.get("id")
        displayname = player.get("displayname")

修正后的代码：

import requests
import pandas as pd

def fetch_json(api_link, timeout=10):
    # ... (代码与之前相同)

api_link = "https://apiv2.cricket.com.au/web/players/list?isActive=1&teamId=&jsconfig=eccn%3Atrue&format=json"

player_data= fetch_json(api_link)

name = []

if player_data:
    players = player_data['players']
    for player in players:
        id = player.get("id")
        displayname = player.get("displayname")
        name.append({
            "id" : id,
            "displayname" : displayname
        })
    print(f"Player Name Retrived")

player_name = pd.DataFrame(name)

修改后，代码应该就能正常运行，并成功提取球员的 ID 和显示名称。