task 5:
vectorInt.hpp
#include<iostream> using namespace std; class vectorInt { public: vectorInt(int n); vectorInt(int n, int value); vectorInt(const vectorInt &y); ~vectorInt(); friend void output(vectorInt &t); int get_size() const; int &at(int i); private: int size; int *p; }; vectorInt::vectorInt(int n) : size{n} { p = new int[size]; cout << "constructor 1 called." << endl; } vectorInt::vectorInt(int n, int value) : size{n} { p = new int[size]; for(int i = 0; i < size; i++) { p[i] = value; } cout << "constructor 2 called." << endl; } vectorInt::vectorInt(const vectorInt &y) : size{y.size} { p = new int[size]; for(int i = 0; i < size; i++) { p[i] = y.p[i]; } cout << "copy constructor called." << endl; } vectorInt::~vectorInt() { delete[] p; cout << "destructor called" << endl; } void output(vectorInt &t) { for(int i = 0; i < t.size; i++) { cout << t.p[i] << ", "; } cout << "\b\b " << endl; } int vectorInt::get_size() const { return size; } int &vectorInt::at(int i) { if(i >= 0 && i < size); return p[i]; }
task5.cpp
#include <iostream> #include "vectorInt.hpp" void test() { using namespace std; int n; cin >> n; vectorInt x1(n); for(auto i = 0; i < n; ++i) x1.at(i) = i*i; output(x1); vectorInt x2(n, 42); vectorInt x3(x2); output(x2); output(x3); x2.at(0) = 77; output(x2); output(x3); } int main() { test(); }
task6:
Matrix.hpp
#include <iostream> using std::cout; using std::endl; class Matrix { public: Matrix(int n); // 构造函数,构造一个n*n的矩阵 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵 Matrix(const Matrix &X); // 复制构造函数,使用已有的矩阵X构造 ~Matrix(); //析构函数 void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 void set(int i, int j, int value); //设置矩阵第i行第j列元素值为value double &at(int i, int j); //返回矩阵第i行第j列元素的引用 double at(int i, int j) const; // 返回矩阵第i行第j列元素的值 int get_lines() const; //返回矩阵行数 int get_cols() const; //返回矩列数 void print() const; // 按行打印输出矩阵 private: int lines; // 矩阵行数 int cols; // 矩阵列数 double *p; // 指向存放矩阵数据的内存块的首地址 }; // 类Matrix的实现 Matrix::Matrix(int n):Matrix{n, n}{} Matrix::~Matrix() { delete[] p; } Matrix::Matrix(int n, int m) : lines{n}, cols{m} { p = new double[lines * cols]; } Matrix::Matrix(const Matrix &x) : lines{x.lines}, cols{x.cols} { p = new double[lines * cols]; for(int i = 0; i < lines * cols; i++) { p[i] = x.p[i]; } } void Matrix::set(const double *pvalue) { for(int i = 0; i < lines * cols; i++) { p[i] = pvalue[i]; } } void Matrix::set(int i, int j, int value) { p[i * cols + j] = value; } double &Matrix::at(int i, int j) { return p[i * cols + j]; } double Matrix::at(int i, int j) const { return p[i * cols + j]; } int Matrix::get_lines() const { return lines; } int Matrix::get_cols() const { return cols; } void Matrix::print() const { for(int i = 0; i < lines; i++) { for(int j = 0; j < cols; j++) { cout << p[i * cols + j] << ", "; } cout << "\b\b " << endl; } }
task6.cpp
#include <iostream> #include "matrix.hpp" void test() { using namespace std; double x[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}; Matrix m1(3, 4); // 创建一个3 ×4的矩阵 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 m1.print(); // 打印矩阵m1的值 cout << "the first line is: " << endl; cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl; // 输出矩阵m1第1行两个元素的值 cout << endl; Matrix m2(4, 3); m2.set(x); m2.print(); cout << "the first line is: " << endl; cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl; cout << endl; Matrix m3(m2); // 用矩阵m2构造新的矩阵m3 m3.set(0, 0, 999); // 将矩阵m3第0行第0列元素值设为999 m3.print(); } int main() { test(); }
标签:const,Matrix,int,lines,cols,实验,vectorInt From: https://www.cnblogs.com/miantiaooooo/p/16861405.html