实验任务五
vectorint.hpp
#include<iostream> using namespace std; class vectorint { public: vectorint(int n) { length = n; arr = new int[n]; cout << "constructor 1 callled" << endl; } vectorint(int n, int m) { length = n; arr = new int[n]; for (int i = 0; i < n; i++)arr[i] = m; cout << "constructor 2 callled" << endl; } vectorint(vectorint& x) { length = x.get_size(); arr = new int[length]; for (int i = 0; i < length; i++)arr[i] = x.arr[i]; cout << "copy constructor called" << endl; } int& at(int n) { return arr[n]; } int get_size() { return length; } ~vectorint() { cout << "destructor called" << endl; } private: int length;int *arr; friend void output(vectorint& x); }; void output(vectorint& x) { for (int i = 0; i < x.get_size(); i++) cout << x.arr[i] << " "; cout << '\n'; }
task5.cpp
#include <iostream> #include"vectorint.hpp" void test() { using namespace std; int n; cin >> n; vectorint x1(n); for (auto i = 0; i < n; ++i) x1.at(i) = i * i; output(x1); vectorint x2(n, 42); vectorint x3(x2); output(x2); output(x3); x2.at(0) = 77; output(x2); output(x3); } int main() { test(); }
实验任务六
Matrix.hpp
#include <iostream> using std::cout; using std::endl; class Matrix { public: Matrix(int n); // 构造函数,构造一个n*n的矩阵 Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵 Matrix(const Matrix& X); // 复制构造函数,使用已有的矩阵X构造 ~Matrix() {}; //析构函数 void set(const double* pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 void set(int i, int j, int value); //设置矩阵第i行第j列元素值为value double& at(int i, int j); //返回矩阵第i行第j列元素的引用 double at(int i, int j) const; // 返回矩阵第i行第j列元素的值 int get_lines() const; //返回矩阵行数 int get_cols() const; //返回矩列数 void print() const; // 按行打印输出矩阵 private: int lines; // 矩阵行数 int cols; // 矩阵列数 double* p; // 指向存放矩阵数据的内存块的首地址 }; Matrix::Matrix(int n) { lines = n; cols = n; p = new double[n * n]; } Matrix::Matrix(int n, int m) { lines = n; cols = m; p = new double[n * m]; } Matrix::Matrix(const Matrix& X) { lines = X.lines; cols = X.cols; p = new double[lines * cols]; for (int i=0; i < lines * cols; i++) p[i] = X.p[i]; } void Matrix::set(const double* pvalue) { for (int i = 0; i < lines * cols; i++) { p[i] =* pvalue; pvalue++; } } void Matrix::set(int i, int j, int value) { p[i * cols + j] = value; } double& Matrix::at(int i, int j) { return p[i * cols + j]; } double Matrix::at(int i, int j) const{ return p[i * cols + j]; } int Matrix::get_lines() const { return lines; } int Matrix::get_cols() const { return cols; } void Matrix::print() const { for (int i = 0; i < lines * cols; i++) { cout << p[i] ; if (i > 0 && (i + 1) % cols == 0)cout << endl; else cout << ','; } } // 类Matrix的实现:待补足 // ×××
task6.cpp
#include <iostream> #include "Matrix.hpp" void test() { using namespace std; double x[] = { 1, 21, 13, 24, 45, 36 }; Matrix m1(2, 3); // 创建一个3×2的矩阵 m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 m1.print(); // 打印矩阵m1的值 cout << "the first line is: " << endl; cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl; // 输出矩阵m1第1行两个元素的值 cout << endl; Matrix m2(2, 3); m2.set(x); m2.print(); cout << "the first line is: " << endl; cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl; cout << endl; Matrix m3(m2); // 用矩阵m2构造新的矩阵m3 m3.set(0, 0, 19); // 将矩阵m3第0行第0列元素值设为999 m3.print(); } int main() { test(); }
运行测试截图
更改数据后
总结
对于深复制和浅复制有了更多认识,但是一些前面的关键词类似于auto和一些语法用法有一些遗忘,调试也不够及时,课后还是要多加练习。
标签:const,Matrix,int,double,lines,cols,实验 From: https://www.cnblogs.com/akumanpower/p/16851930.html