实现简单链表

#include<stdio.h>
struct stu 
{
    int age;
    char name[20];
    struct stu* next;
};
int main()
{
    struct stu s1 = { 20,"zhangsan",NULL };
    struct stu s2 = { 21,"lisi",NULL };
    struct stu s3 = { 28,"wang",NULL };
    struct stu current = { 19,"刘流六",NULL };
    struct stu* first = &current;
    current.next = &s1;
    s1.next = &s2;
    s2.next = &s3;
    int count = 0;
    do
    {
        count++;
        printf("第%d个学生：%d %s\n",count, first->age, first->name);
        first = first->next;
    } while (first != NULL);
    return 0;
}