任务1:
#pragma once #include<iostream> #include<string> using std::string; using std::cout; class Button{ public: Button(const string &text); string get_label() const; void click(); private: string label; }; Button::Button(const string &text):label{text}{} inline string Button::get_label()const{return label;} void Button::click(){ cout<<"Button"<<label<<"click\n"; }
#pragma once #include "button.hpp" #include<vector> #include<iostream> using std::vector; using std::cout; using std::endl; class window{ public: window(const string &win_title); void display()const; void close(); void add_button(const string &label); private: string title; vector<Button>buttons; }; window::window(const string &win_title):title{win_title}{buttons.push_back(Button("close"));} inline void window::display()const{ string s(40,'*'); cout<<s<<endl; cout<<"window title:"<<title<<endl; cout<<"It has"<<buttons.size()<<"buttons:"<<endl; for(const auto &i: buttons) cout<<i.get_label()<<"button"<<endl; cout<<s<<endl; } void window::close(){ cout<<"close window'"<<title<<"'"<<endl; buttons.at(0).click(); } void window::add_button(const string &label){ buttons.push_back(Button(label)); }
#include"window.hpp" #include<iostream> using namespace std; void test(){ window w1("new window"); w1.add_button("maxmize"); w1.display(); w1.close(); } int main(){ cout<<"用组合类型模拟简单GUI:\n"; test(); }
问题1:定义了两个类,Window,Button类,使用了iostream,string,vector类。Window和Button类有组合关系。
问题2:不用,因为没有经常的调用。
问题3:声明了一个长度为 40 的字符串,内容为'*'。结果是一个包含 40 个*的字符串。
任务2:
#include<iostream> #include<vector> using namespace std; void output1(const vector<int> &v){ for(auto &i: v){ cout<<i<<','; } cout<<"\b\b\n"; } void output2(const vector<vector<int>>v){ for(auto &i:v){ for(auto &j:i){ cout<<j<<","; } cout<<"\b\b\n"; } } void test1(){ vector<int>v1(5,42); const vector<int> v2(v1); v1.at(0)=-999; cout<<"v1:";output1(v1); cout<<"v2:";output1(v2); cout<<"v1.at(0)="<<v1.at(0)<<endl; cout<<"v2.at(0)="<<v2.at(0)<<endl; } void test2(){ vector<vector<int>>v1{{1,2,3},{4,5,6,7}}; const vector<vector<int>>v2(v1); v1.at(0).push_back(-999); cout<<"v1:\n";output2(v1); cout<<"v2:\n";output2(v2); vector<int>t1=v1.at(0); cout<<t1.at(t1.size()-1)<<endl; const vector<int> t2=v2.at(0); cout<<t2.at(t2.size()-1)<<endl; } int main(){ cout<<"测试1:\n"; test1(); cout<<"测试2:\n"; test2(); }
问题1:第一行声明一个int类型的,长度为5的,值都为42的动态数组v1;第二行将v1复制给v2;第三行将v1的第一个数据改为-999。
问题2:第一行声明int类型的二位动态数组v1,第二行将v1复制给v2,第三行给动态数组第一行末尾添加一个-999。
问题3:第一行将v1的第一行复制给t1,第二行输出t1的最后一个值,第三行将v2的第一行复制给t2,第四行输出t2的最后一个值。
问题4:深复制,需要。
任务3:
#pragma once #include<iostream> #include<cassert> using namespace std; class vectorInt{ public: vectorInt(int n); vectorInt(int n,int value); vectorInt(const vectorInt &vi); ~vectorInt(); int &at(int index); const int& at(int index)const; vectorInt& assign(const vectorInt &v); int get_size()const; private: int size; int *ptr; }; vectorInt::vectorInt(int n):size{n},ptr{new int[size]}{} vectorInt::vectorInt(int n,int value):size{n},ptr{new int[size]}{ for(auto i=0;i<size;++i){ ptr[i]=value; } } vectorInt::vectorInt(const vectorInt &vi):size{vi.size},ptr{new int[size]}{ for(auto i=0;i<size;++i) ptr[i]=vi.ptr[i]; } vectorInt::~vectorInt(){ delete [] ptr; } const int& vectorInt::at(int index)const{ assert(index>=0&&index<size); return ptr[index]; } int & vectorInt::at(int index){ assert(index>=0&&index<size); return ptr[index]; } vectorInt& vectorInt::assign(const vectorInt &v){ delete[] ptr; size=v.size; ptr=new int[size]; for(int i=0;i<size;++i) ptr[i]=v.ptr[i]; return *this; } int vectorInt::get_size()const{ return size; }
#include "vectorlnt.hpp" #include<iostream> using namespace std; void output(const vectorInt &vi){ for(auto i=0;i<vi.get_size();++i){ cout<<vi.at(i)<<","; } cout<<"\b\b\n"; } void test1(){ int n; cout<<"Enter n:"; cin>>n; vectorInt x1(n); for(auto i=0;i<n;++i){ x1.at(i)=i*i; } cout<<"x1:";output(x1); vectorInt x2(n,42); vectorInt x3(x2); x2.at(0)=-999; cout<<"x2:";output(x2); cout<<"x3:";output(x3); } void test2(){ const vectorInt x(5,42); vectorInt y(10,0); cout<<"y:";output(y); y.assign(x); cout<<"y:";output(y); cout<<"x.at(0)="<<x.at(0)<<endl; cout<<"y.at(0)="<<y.at(0)<<endl; } int main(){ cout<<"侧式1:\n"; test1(); cout<<"侧式2:\n"; test2(); }
问题1:深复制。
问题2:不能运行。
问题3:可以改,但是会增加内存以及元素的复制。
任务4:
#pragma once #include <iostream> #include <cassert> using std::cout; using std::endl; // 类Matrix的声明 class Matrix { public: Matrix(int n, int m); // 构造函数,构造一个n*m的矩阵, 初始值为value Matrix(int n); // 构造函数,构造一个n*n的矩阵, 初始值为value Matrix(const Matrix &x); // 复制构造函数, 使用已有的矩阵X构造 ~Matrix(); void set(const double *pvalue); // 用pvalue指向的连续内存块数据按行为矩阵赋值 void clear(); // 把矩阵对象的值置0 const double& at(int i, int j) const; // 返回矩阵对象索引(i,j)的元素const引用 double& at(int i, int j); // 返回矩阵对象索引(i,j)的元素引用 int get_lines() const; // 返回矩阵对象行数 int get_cols() const; // 返回矩阵对象列数 void display() const; // 按行显示矩阵对象元素值 private: int lines; // 矩阵对象内元素行数 int cols; // 矩阵对象内元素列数 double *ptr; }; // 类Matrix的实现:待补足 // xxx Matrix::Matrix(int n, int m) : lines(n), cols(m), ptr(new double[n * m]()) {} Matrix::Matrix(int n) : Matrix(n, n) {} Matrix::Matrix(const Matrix &x) : lines(x.lines), cols(x.cols), ptr(new double[x.lines * x.cols]) {} Matrix::~Matrix() { delete[] ptr; } void Matrix::set(const double *pvalue) {} void Matrix::clear() { for(int i=0;i<lines*cols;++i){ ptr[i]=0; } } const double& Matrix::at(int i, int j) const { return ptr[i * cols + j]; } double& Matrix::at(int i, int j) { return ptr[i * cols + j]; } int Matrix::get_lines() const { return lines; } int Matrix::get_cols() const { return cols; } void Matrix::display() const { for (int i = 0; i < lines; ++i) { for (int j = 0; j < cols; ++j) { cout << at(i, j) << " "; } cout << endl; } }
#include "Matrix.hpp" #include <iostream> #include <cassert> using std::cin; using std::cout; using std::endl; const int N = 1000; // 输出矩阵对象索引为index所在行的所有元素 void output(const Matrix &m, int index) { assert(index >= 0 && index < m.get_lines()); for(auto j = 0; j < m.get_cols(); ++j) cout << m.at(index, j) << ", "; cout << "\b\b \n"; } void test1() { double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9}; int n, m; cout << "Enter n and m: "; cin >> n >> m; Matrix m1(n, m); // 创建矩阵对象m1, 大小n×m m1.set(x); // 用一维数组x的值按行为矩阵m1赋值 Matrix m2(m, n); // 创建矩阵对象m1, 大小m×n m2.set(x); // 用一维数组x的值按行为矩阵m1赋值 Matrix m3(2); // 创建一个2×2矩阵对象 m3.set(x); // 用一维数组x的值按行为矩阵m4赋值 cout << "矩阵对象m1: \n"; m1.display(); cout << endl; cout << "矩阵对象m2: \n"; m2.display(); cout << endl; cout << "矩阵对象m3: \n"; m3.display(); cout << endl; } void test2() { Matrix m1(2, 3); m1.clear(); const Matrix m2(m1); m1.at(0, 0) = -999; cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl; cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl; cout << "矩阵对象m1第0行: "; output(m1, 0); cout << "矩阵对象m2第0行: "; output(m2, 0); } int main() { cout << "测试1: \n"; test1(); cout << "测试2: \n"; test2(); }
任务5:
#pragma once #include<iostream> #include<vector> using namespace std; class User { public: User(const string& name1, const string& password1="123456", const string& email1=""); void set_email(); void change_password(); void display() const; private: string name; string password; string email; }; User::User(const string& name1, const string& password1, const string& email1) :name { name1 }, password { password1 }, email { email1 } { } void User::set_email() { cout << "Enter email address: "; string l; cin >> l; while (1) { if (l.find('@') != string::npos) { email = l; cout << "email is set successfully..." << endl; break; } else { cout << "illegal email.Please re-enter email: "; cin >> l; } } } void User::change_password() { cout << "Enter old password: "; string m; cin >> m; int s = 1; while (s < 3) { if (m == password) { cout << "new password: "; cin >> m; password = m; cout << "new password is set successfully..." ; break; } else { cout << "password input error. Please re-enter agagin"; cin >> m; s++; } } } void User::display() const { cout << "name: " << name <<endl; cout << "pass: "; for (char ch : password) { cout << '*'; } cout <<endl; cout << "email: "<<email<<endl; }
#include "user.hpp" #include <iostream> #include <vector> #include <string> using std::cin; using std::cout; using std::endl; using std::vector; using std::string; void test(){ vector<User> user_lst; User u1("Alice", "2024113", "[email protected]"); user_lst.push_back(u1); cout << endl; User u2("Bob"); u2.set_email(); u2.change_password(); user_lst.push_back(u2); cout << endl; User u3("Hellen"); u3.set_email(); u3.change_password(); user_lst.push_back(u3); cout << endl; cout << "There are " << user_lst.size() << " users. they are: " << endl; for(auto &i: user_lst) { i.display(); cout << endl; } } int main() { test(); }
任务6:
#ifndef __DATE_H__ #define __DATE_H__ class Date{ private: int year; int month; int day; int totalDays; public: Date(int year,int month,int day); int getYear()const {return year;} int getMonth()const {return month;} int getDay()const {return day;} int getMaxDay()const; bool isLeapYear()const{ return year%4==0&&year%100!=0||year%400==0; } void show()const; int distance(const Date &date)const{ return totalDays-date.totalDays; } }; #endif//__DATE_H__
#include"date.h" #include<iostream> #include<cstdlib> using namespace std; namespace{ const int DAYS_BEFORE_MONTH[]={0,31,59,90,120,151,181,212,243,273,304,334,365}; } Date::Date(int year,int month,int day):year(year),month(month),day(day){ if(day<=0||day>getMaxDay()){ cout<<"Invalid date:"; show(); cout<<endl; exit(1); } int years=year-1; totalDays=years*365+years/4-years/100+years/400+DAYS_BEFORE_MONTH[month-1]+day; if(isLeapYear()&&month>2)totalDays++; } int Date::getMaxDay()const{ if(isLeapYear()&&month==2) return 29; else return DAYS_BEFORE_MONTH[month]-DAYS_BEFORE_MONTH[month-1]; } void Date::show()const{ cout<<getYear()<<"-"<<getMonth()<<"-"<<getDay(); }
#ifndef __ACCOUNT_H__ #define __aCCOUNT_H__ #include"date.h" #include<string> class SavingsAccount{ private: std::string id; double balance; double rate; Date lastDate; double accumulation; static double total; void record(const Date &date,double amount,const std::string &desc); void error(const std::string &msg)const; double accumulate (const Date &date)const{ return accumulation+balance*date.distance(lastDate); } public: SavingsAccount(const Date &date,const std::string &id,double rate); const std::string &getID()const {return id;} double getBalance()const {return balance;} double getRate()const {return rate;} static double getTotal(){ return total; } void deposit(const Date &date,double amount,const std::string &desc); void withdraw(const Date &date,double amount,const std::string &desc); void settle(const Date& date); void show()const; }; #endif //__ACCOUNT_H__
#include"date account.h" #include<cmath> #include<iostream> using namespace std; double SavingsAccount::total=0; SavingsaAccount::SavingsAccount(const Date &date,const string &id,double rate):id(id),balance(0),rate(rate),lastDate(date),accumulation(0){ date.show(); cout<<"\t#"<<id<<"created"<<endl; } void SavingsAccount::record(const Date &date,double amount ,const string &desc){ accumulation=accumulate(date); lastDate=date; amount=floor(amount*100+0.5)/100; balance+=amount; total+=amount; date.show(); cout<<"\t#"<<id<<"\t"<<amount<<"\t"<<balance<<"\t"<<desc<<endl; } void SavingsAccount::error(const string &msg)const{ cout<<"Error(#"<<id<<"):"<<msg<<endl; } void SavingsAccount::deposit(const Date&date,double amount,const string &desc){ record(date,amount,desc); } void SavingsAccount::withdraw(const Date &date,double amount,const string &desc){ if(amount>getBalance()) error("not enough money"); else record(date,-amount,desc); } void SavingsAccount::settle(const Date &date){ double interest=accumulate(date)*rate/date.distance(Date(date.getYear()-1,1,1)); if(interest!=0) record(date,interest,"interest"); accumulation=0; } void SavingsAccount::show()const{ cout<<id<<"\tBalance:"<<balance; }
#include"date account.h" #include<iostream> using namespace std; int main(){ Date date(2008,11,1); SavingsAccount accounts[]={SavinsAccount(date,"03755217",0.015),SavingsAccount(date,"02342342",0.015)}; const int n=sizeof(accounts)/sizeof(SavingsAccount); accounts[0].deposit(Date(2008,11,5),5000,"salary"); accounts[0].deposit(Date(2008,11,25),10000,"sell stock 0323"); accounts[0].deposit(Date(2008,12,5),5500,"salary"); accounts[0].withdraw(Date(2008,12,20),4000,"buy a laptop"); cout<<endl; for(int i=0;i<n;i++){ accounts[i].settle(Date(2009,1,1)); accounts[i].show(); cout<<endl; } cout<<"Total:"<<SavinsAccount::getTotal()<<endl; return 0; }
标签:std,const,string,int,void,实验,cpp,include From: https://www.cnblogs.com/hb879655/p/18525825